nodes

Getting all nodes inside a tag

こ雲淡風輕ζ 提交于 2019-12-08 03:37:31
I have a code like this: <div id="container"> Lorem ipsum dolor sit amet <p>This is a paragraph</p> <br /> <span>This is a span</span> Lorem ipsum dolor sit amet </div> Is it possible to get all text nodes and tags inside this div? I want to access each node (including texts) via an array. for example: for(var i=0;i<nodesArray.length;i++) { document.write("Node: "+nodesArray[i]+"<br />"); } OUTPUT: Node: Lorem ipsum dolor sit amet Node: This is a paragraph Node: This is a span Node: Lorem ipsum dolor sit amet I tried "all selector" in jquery but it gets only tags, not texts.. You can use the

Removing fixed classes does not properly remove them from the presetation

a 夏天 提交于 2019-12-08 03:29:52
问题 Concerning: Remove all .fixed classes from force layout nodes with jQuery I can remove the fixed classes now. But the nodes are still fixed in the view. So simply removing the class is not enough I believe. I didn't find any help in the docs of D3 as well. 回答1: Are you wanting to go back to the force layout ? Its because you have only removed the class not the actual fixed property. Try this : d3.selectAll(".node") //select your node here .each(function(d){d.fixed = false;}) .classed("fixed",

jQuery - how to append multiple nodes to container

我怕爱的太早我们不能终老 提交于 2019-12-08 01:41:15
问题 I need to append multiple nodes to a container. Rather than doing a slow DOM append inside each iteration, I want to queue up the nodes in a document fragment (open to other ideas) and append them all at one time. Here is my code: var fragment = document.createDocumentFragment(); $.each( poFailureInfoMultiple, function(i,e){ fragment.appendChild( $('<button/>', { 'class': 'el-contents-center multiple-record' }) ); }); $('#some-container').html( fragment ); My problem is I am getting an error

how to highlight(change color) of all connected(neighbours) nodes and links in a d3 force directed graph

十年热恋 提交于 2019-12-07 23:48:33
问题 I saw this example here http://www.d3noob.org/2013/03/d3js-force-directed-graph-example-basic.html I can understand it to an extent where I can make basic changes, but have not been able to do one thing specifically which is to highlight (change color) of all connected nodes. e.g If I mouse over node 1 or click on node 1,it should find all neighboring nodes and highlight the link paths by changing color. I looked at clicking a node in d3 from a button outside the svg already answered but I

JavaScript: Copy Node to DocumentFragment

我只是一个虾纸丫 提交于 2019-12-07 13:00:00
问题 I gather that the whole point of a DocumentFragment is to be able to construct the contents without touching the DOM until it’s ready to go. Given that DocumentFragment doesn’t support innerHTML , it can be a bit tedious. On the other hand, once constructed, it’s easy to add the contents to an existing DOM node by the fragment itself. If I create a div without adding it to the DOM, I can populate it how I like, including innerHTML . As far as I can tell, it should have no additional impact on

Returning multiple rows from querying XML column in SQL Server (Revisited)

筅森魡賤 提交于 2019-12-07 10:43:37
问题 The Answers to the Question Returning multiple rows from querying XML column in SQL Server 2008 were helpful. But I have an XML data set with a slightly different structure and need help getting valid query output. Here's the code that demonstrates my problem. DECLARE @XML_In XML = ' <ROOT> <PROCESS_RESULT> <CATEGORY>ABC</CATEGORY> <STATUS>ERROR</STATUS> <PROCESS_RESULT_MSG> <MESSAGE_TEXT>ABC Process Category Error</MESSAGE_TEXT> </PROCESS_RESULT_MSG> </PROCESS_RESULT> <PROCESS_RESULT>

How to Traverse a N-Ary Tree

浪子不回头ぞ 提交于 2019-12-07 09:30:28
问题 My Tree/Node Class: import java.util.ArrayList; import java.util.List; public class Node<T> { private T data; private List<Node<T>> children; private Node<T> parent; public Node(T data) { this.data = data; this.children = new ArrayList<Node<T>>(); } public Node(Node<T> node) { this.data = (T) node.getData(); children = new ArrayList<Node<T>>(); } public void addChild(Node<T> child) { child.setParent(this); children.add(child); } public T getData() { return this.data; } public void setData(T

Why memory usage is greater than what I set in Kubernetes's node?

懵懂的女人 提交于 2019-12-07 07:01:08
问题 I allocated resource to 1 pod only with 650MB/30% of memory (with other built-in pods, limit memory is 69% only) However, when the pod handling process, the usage of pod is within 650MB but overall usage of node is 94%. Why does it happen because it supposed to have upper limit of 69%? Is it due to other built-in pods which did not set limit? How to prevent this as sometimes my pod with error if usage of Memory > 100%? My allocation setting ( kubectl describe nodes ): Memory usage of

Graphviz: Node internal orientation

柔情痞子 提交于 2019-12-07 03:34:19
The following graphviz code: digraph g { labelloc="t"; label="Feed creation process"; graph [ rankdir = "LR" ]; node [ fontsize = "16" shape = "record" ]; edge []; abc [shape=none, margin=0, rankdir="" label=< <TABLE BORDER="0" CELLBORDER="1" CELLSPACING="0" CELLPADDING="4"> <TR><TD ROWSPAN="3"><FONT COLOR="red">hello</FONT><BR/>world</TD> <TD COLSPAN="3">b</TD> <TD ROWSPAN="3" BGCOLOR="lightgrey">g</TD> <TD ROWSPAN="3">h</TD> </TR> <TR><TD>c</TD> <TD PORT="here">d</TD> <TD>e</TD> </TR> <TR><TD COLSPAN="3">f</TD> </TR> </TABLE>>]; } Gives: I'd like to rotate the table orientation 90° clockwise

Expression Must have Class Type?

孤人 提交于 2019-12-07 00:47:27
So I've been playing around with Nodes and keep running into this error when I try to test it. If I use Parentheses I get this Error on list. - "Expression must have class type!" If I don't use Parentheses I get this Error on list , insert and display - "this is inaccessible." This happens when Declaring my LList in Main(). What's going on and why is this? My Driver #include "LList.h" #include <iostream> using namespace std; int main() { LList<int> list; bool test = list.insert(5); list.display(); return 0; } Class LList #include "Nodes.h" #ifndef LLIST_H #define LLIST_H template<typename TYPE