nodelist

This question already has an answer here: Explanation of [].slice.call in javascript? 7 answers how does Array.prototype.slice.call() work? 13 answers Why doesn't nodelist have forEach? 10 answers I was looking up how to iterate NodeLists and I came across the following bit of code. var nodesArray = Array.prototype.slice.call(nodeList); nodesArray.forEach(function(node) { //... }) What is the purpose of calling Array.prototype.slice against a NodeList? What is the purpose of calling Array.prototype.slice against a NodeList? The Array#slice method "returns a shallow copy of a portion of an

Can anyone tell me what kind of object the NodeList is. I read that it is an array-like object and that it can be accessed via bracket notation, for example var a = someNode.childNode[0]; . How is this possible since via bracket notation we can only access to the properties of an object, and as i know we can not have A NodeList is collection of DOM elements . It's like an array (but it isn't). To work with it, you must turn it into a regular JavaScript array. The following snippet can get the job done for you. const nodeList = document.getElementsByClassName('.yourClass'), nodeArray = [].slice

I need to create a XML Document object using the NodeList. Can some one pls help me to do this. I have shown you the code and the xml below import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.xpath.*; import org.w3c.dom.*; public class ReadFile { public static void main(String[] args) { String exp = "/configs/markets"; String path = "testConfig.xml"; try { Document xmlDocument = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(path); XPath xPath = XPathFactory.newInstance().newXPath(); XPathExpression xPathExpression = xPath.compile(exp); NodeList nodes = (NodeList

In ES6, an iterable is an object that allows for... of , and has a Symbol.iterator key. Arrays are iterables, as are Sets and Maps. The question is: are HTMLCollection and NodeList iterables? Are they supposed to be? MDN documentation seems to suggest a NodeList is an iterable. for...of loops will loop over NodeList objects correctly, in browsers that support for...of (like Firefox 13 and later) This appears to corroborate Firefox's behaviour. I tested the following code in both Chrome and Firefox, and was surprised to find that Firefox seem to think they are iterables, but Chrome does not. In

Does NodeList support addEventListener. If not what is the best way to add EventListener to all the nodes of the NodeList. Currently I am using the code snippet as show below, is there a better way to do this. var ar_coins = document.getElementsByClassName('coins'); for(var xx=0;xx < ar_coins.length;xx++) { ar_coins.item(xx).addEventListener('dragstart',handleDragStart,false); } There is no way to do it without looping through every element. You could, of course, write a function to do it for you. function addEventListenerList(list, event, fn) { for (var i = 0, len = list.length; i < len; i++)

After providing an incorrect answer concerning the .item() property of Node.childNodes for a question, I inspected __proto__ of the returned childNodes of a form element and found a forEach method. The forEach method of Node.childNodes is not documented in the specification of NodeList , in Methods at MDN , or Interface NodeList , and does not appear to be mentioned in Iterate a NodeList using forEach method or pages linked to that Question; though it appears available in Chromium 50. Is the method available only at relatively recent versions of Chrome / Chromium? If yes, is this documented?

is there a way to join 2 NodeLists returned by 2 calls of document.getElementsByTagName? Say, I have the following code var inputs = documentElement.getElementsByTagName('input'); var selects = document.getElementsByTagName('select'); I want to loop through the results. Is it possible in one loop? Thank you in advance! Simon Seems like you can use the same Array.prototype.slice.call that makes the args array-like object become an array. ( See here ) var inputs = document.getElementsByTagName('input'); var selects = document.getElementsByTagName('select'); inputs = Array.prototype.slice.call