ngfor

*ngFor doesn't work in modal (Angular ionic)

生来就可爱ヽ(ⅴ<●) 提交于 2021-01-01 06:35:07
问题 Im using angular in ionic application but in a modal the ngForm doesnt works. I think its cleary whit a simple code. <li *ngFor="let item of [1,2,3,4,5]; let i = index"> {{i}} {{item}} </li> this code show this in all rest of page -> list but in a modal create like this async presentModal(test){ const modal = await this.modalController.create({ component: TestPage, componentProps: { test } }); modal.onWillDismiss().then(dataReturned => { }); return await modal.present(); } dont show anything.

Angular 2 : increment *ngFor by 2 or implementing two paginations with in a Pagination

筅森魡賤 提交于 2020-12-31 06:41:47
问题 I am pretty new to Angular and I was wondering if there is any way to increment the ngFor loop by 2 instead of 1. I am trying to implement two pagination's with in a pagination for which increment the loop by 2 is required. I am getting objects which have objects with in. Lets say users and list of their address. (First NgFor is to paginate the users by 2. If I get 15 users. 2 users will be displayed in one page) li *ngFor="let user of Users | paginate: { itemsPerPage: 1, currentPage: p };let

Angular 2 - ngFor display last 3 items in array

余生长醉 提交于 2020-12-28 22:56:10
问题 got an array with many projects and i want to display the last 3 projects. got in my html <li *ngFor="let project of projects;"> <h2>{{ project.name }}</h2> <p>{{ project.meta_desciption }}</p> </li> it s displaying all the project now (over 20). how can i display only the last 3? I think i need to use "last" somewere in my code, but can't figure it out https://angular.io/docs/ts/latest/api/common/index/NgFor-directive.html 回答1: <li *ngFor="let project of (projects | slice:projects.length - 4

Angular 2 - ngFor display last 3 items in array

别说谁变了你拦得住时间么 提交于 2020-12-28 22:55:19
问题 got an array with many projects and i want to display the last 3 projects. got in my html <li *ngFor="let project of projects;"> <h2>{{ project.name }}</h2> <p>{{ project.meta_desciption }}</p> </li> it s displaying all the project now (over 20). how can i display only the last 3? I think i need to use "last" somewere in my code, but can't figure it out https://angular.io/docs/ts/latest/api/common/index/NgFor-directive.html 回答1: <li *ngFor="let project of (projects | slice:projects.length - 4

Angular 2 - ngFor display last 3 items in array

ぃ、小莉子 提交于 2020-12-28 22:48:36
问题 got an array with many projects and i want to display the last 3 projects. got in my html <li *ngFor="let project of projects;"> <h2>{{ project.name }}</h2> <p>{{ project.meta_desciption }}</p> </li> it s displaying all the project now (over 20). how can i display only the last 3? I think i need to use "last" somewere in my code, but can't figure it out https://angular.io/docs/ts/latest/api/common/index/NgFor-directive.html 回答1: <li *ngFor="let project of (projects | slice:projects.length - 4

how sort array with object by property use ngFor

陌路散爱 提交于 2020-08-10 18:22:26
问题 I neet to display in table sort data js let array = [ {idx: number, name: string, btn: number, index: number}, {idx: number, name: string, btn: number, index: number}, {idx: number, name: string, btn: number, index: number} ] html <tr *ngFor="let ticket of array"> <td>{{ticket.name}}</td> <td>{{ticket.btn}}</td> <td>{{ticket.index}}</td> <tr> I need sort display by index value 回答1: let array = [ { idx: 1, name: 'a', btn: 1, index: 2 }, { idx: 2, name: 'b', btn: 2, index: 3 }, { idx: 3, name:

Angular *ngFor loop through an array of arrays

坚强是说给别人听的谎言 提交于 2020-06-17 03:34:39
问题 I have an array which contains other arrays inside like that: array = [ ["element A", "element B"], ["YES", "NO"] ] And I want to loop through this array of object in an HTML table using ngFor: <table> <thead> <tr> <th>#</th> <th>COLUMN 1</th> <th>COLUMN 2</th> </tr> </thead> <tbody> <template *ngFor="let row of csvContent; let in = index"> <th scope="row">{{in}}</th> <template *ngFor="let c of row; let in = index"> <td> {{c[0]}} </td> </template> </template> </tbody> </table> I want to