nested

问题 I am trying to determine the best way to return nested key values using groovy. If I have a map: def map = [ OrganizationName: 'SampleTest', Address: [ Street: '123 Sample St', PostalCode: '00000', ] ] Is there a way to return all of the keys? OrganizationName , OrganizationURL , Address.Street , Address.PostalCode ? If I didn't have an map within a map I could use map.keySet() as String[]. Should I just loop through each key and see if it is an instanceof another map? 回答1: There's no such

问题 I am using Ruby on Rails 3.1.0. I am trying to save a nested model having an attribute that is intended to store the foreign key of the parent model. At the creation time of the parent model I would like to set that attribute value to the parent model id value. In my model I have: class Article < ActiveRecord::Base has_many :article_category_relationships has_many :categories, :through => :article_category_relationships # Accept nested model attributes accepts_nested_attributes_for :articles

问题 I have a spreadsheet that I am converting to an Access DB. I have a column of typed out customer names that I want to replace with the appropriate customer number from our accounting system. I have created a table with the customer info, and a query that shows what ID needs to be inserted into the source data. What I'm looking for is: UPDATE tblStarting_Data SET CustomerID=x WHERE TEMPCustomer=y Where X and Y come from qryIDPerCustomer. Can I use a loop? How do I reference another query? 回答1:

问题 I have created a usercontrol which accept type of enum and assign the values of that enum to a ComboBox control in that usercontrol. Very Simple. I am using this user control in DataTemplates. Problem comes when there comes nested type. I assign that using this notation EnumType="{x:Type myNamespace:ParentType + NestedType}" It works fine at runtime. but at design time it throws error saying Could not create an instance of type 'TypeExtension' Why? Due to this I am not able to see my window

问题 I want to create a object Checklist with the following JSON. But I think the Arraylist categories isn't created. I do not have an exception the debug console enter into bucle when create the object : " Background partial concurrent mark sweep GC freed 165848(5MB) AllocSpace objects, 144(1852KB) LOS objects, 22% free, 55MB/71MB, paused 5.343ms total 67.660ms " {"type_check":"CAB","description":"simple cabin","categories":[{"category_id":"3","description":"Confort"},{"category_id":"4",

问题 I have been trying to parse nested JSON data and below is my code var string = '{"key1": "value", "key2": "value1", "Key3": {"key31":"value 31"}}'; var obj = JSON.parse(string); console.log(obj.key1) console.log(obj[0]); And this is the output $ node try.js value undefined Why I am getting undefined for obj[0] ? How to get value in this case, and also for nested key key31 ? Update Now with the help from @SergeyK and others, I have modified my above code as follows var string = '{"key1":

问题 just playing around with openmp. Look at this code fragments: #pragma omp parallel { for( i =0;i<n;i++) { doing something } } and for( i =0;i<n;i++) { #pragma omp parallel { doing something } } Why is the first one a lot more slower (around the factor 5) than the second one? From theory I thought that the first one must be faster, because the parallel region is only created once and not n-times like the second? Can someone explain this to me? The code i want to parallelise has the following

问题 i have the following code : $(document).ready(function () { for (i = 1; i <= number_of_banners; i++) { var selector = "#link_" + i; $(selector).click(function () { alert(i); }); } }); but the alert() can't get the "i" variable from the for loop. How can I use the i variable of for loop inside the .click function ? 回答1: you can use this code : $(document).ready(function () { for (var i = 1; i <= number_of_banners; i++) { var selector = "#link_" + i; $(selector).on('click', {id: i}, function (e

问题 I am just getting to know pandas and I can't get over a conceptual problem. My dataframe is as follows: df=pd.DataFrame({'ANIMAL':[1,1,1,1,1,2,2,2], 'AGE_D' : [3,6,47,377,698,1,9,241], 'AGE_Y' : [1,1,1,2,2,1,1,1]}) I would like to do a nested group within animal and age_y and then select the min on the subgroup. Desired output would be then: ANIMAL AGE_Y AGE_D 1 1 3 1 2 377 2 1 1 I can do this without nesting within animal, e.g. if my df2 = subset for ANIMAL=1 then df2.loc[df2.groupby('AGE_Y'

问题 I have inherited code which contains static nested classes as: public class Foo { // Foo fields and functions // ... private static class SGroup { private static Map<Integer, SGroup> idMap = new HashMap<Integer, SGroup>(); public SGroup(int id, String type) { // ... } } } From reading SO (e.g. Java inner class and static nested class) I believe that this is equivalent to two separate classes in two separate files: public class Foo { // Foo fields and functions // ... } and public class SGroup