nested

问题 Okay, I've noticed something, but couldn't find it in the CSS spec. Styling an element with position: fixed will position it absolutely, with respect to the browser viewport. What happens if you place a fixed-position element inside another? Example CSS along the lines of: .fixed { position: fixed; width: 100px; height: 100px; background: red; } #parent { right 100px; padding: 40px; } .fixed .fixed { background: blue; } And HTML: <div id="parent" class="fixed"> <div class="fixed"> </div> <

问题 How can I do this: type A struct { MemberA string } type B struct { A MemberB string } ... b := B { MemberA: "test1", MemberB: "test2", } fmt.Printf("%+v\n", b) Compiling that gives me: "unknown B field 'MemberA' in struct literal" How can I initialize MemberA (from the "parent" struct) when I provide literal struct member values like this? 回答1: While initialization the anonymous struct is only known under its type name (in your case A ). The members and functions associated with the struct

问题 I have the following Dto and entity with a nested sub entity. public class Dto { public string Property { get; set; } public string SubProperty { get; set; } } public class Entity { public string Property { get; set; } public SubEntity Sub { get; set; } } public class SubEntity { public string SubProperty { get; set; } } How can I set up a mapping with AutoMapper that will allow me to update an existing instance of Entity with the values from a Dto . I'm using Mapper.Map(dto, entity) to

问题 A have a real problem (and a headache) with an assignment... I'm in an introductory programming class, and I have to write a function that, given a list, will return the "maximum" depth it goes to... For example: [1,2,3] will return 1, [1,[2,3]] will return 2... I've written this piece of code (it's the best I could get T_T) def flat(l): count=0 for item in l: if isinstance(item,list): count+= flat(item) return count+1 However, It obviously doens't work like it should, because if there are

问题 Is there an easy way (i.e. a function) to determine the level of nesting in list? I know there is str which can be used to get this information. But is there something that simply gives back the result? And can I use such a function to get the names of all levels of alist (recursively) ? 回答1: A little recursive function can do this for you: depth <- function(this,thisdepth=0){ if(!is.list(this)){ return(thisdepth) }else{ return(max(unlist(lapply(this,depth,thisdepth=thisdepth+1)))) } } If you

问题 I have a nested dictionary, let's call it dictionary d. The key of this dictionary is an integer, and the value of each key is another dictionary. I'm trying a simple code on python 2.7 to update the value of one outer key, but it seems that it's updating the values of ALL of the outer key. Hope these codes will make it easier to understand. Here's my input. >>> template = {'mean':0,'median':0} >>> d[0] = template >>> d[1] = template >>> d[0]['mean'] = 1 >>> d and then here's the output: {0:

问题 I'm trying to figure out how I can use recursion to do n-level nested for loops. For example, if n=3, there would be 3 'levels' for(z=0;z<6;z++){ for(y=0;y<6;y++){ for(x=0;x<6;x++){ if (z+y+x==f){ //do something } } } } and so on. I can't seem to figure out how I would be able to place the if loop in the last for loop and how I can access the variables of previous for loops from the if statement. I know that the question of variable nested loops has been asked alot of times, and I have looked

问题 Possible Duplicate: How can I turn a list into an array in python? How can I turn a list such as: data_list = [0,1,2,3,4,5,6,7,8] into a list of lists such as: new_list = [ [0,1,2] , [3,4,5] , [6,7,8] ] ie I want to group ordered elements in a list and keep them in an ordered list. How can I do this? Thanks 回答1: This assumes that data_list has a length that is a multiple of three i=0 new_list=[] while i<len(data_list): new_list.append(data_list[i:i+3]) i+=3 回答2: This groups each 3 elements in

问题 Using the given routines (how to load Matlab .mat files with scipy), I could not access deeper nested structures to recover them into dictionaries To present the problem I run into in more detail, I give the following toy example: load scipy.io as spio a = {'b':{'c':{'d': 3}}} # my dictionary: a['b']['c']['d'] = 3 spio.savemat('xy.mat',a) Now I want to read the mat-File back into python. I tried the following: vig=spio.loadmat('xy.mat',squeeze_me=True) If I now want to access the fields I get

问题 I have a nested dictionary object and I want to be able to retrieve values of keys with an arbitrary depth. I'm able to do this by subclassing dict : >>> class MyDict(dict): ... def recursive_get(self, *args, **kwargs): ... default = kwargs.get('default') ... cursor = self ... for a in args: ... if cursor is default: break ... cursor = cursor.get(a, default) ... return cursor ... >>> d = MyDict(foo={'bar': 'baz'}) >>> d {'foo': {'bar': 'baz'}} >>> d.get('foo') {'bar': 'baz'} >>> d.recursive