nested

问题 i have list view inside another list view like lv1-->lv2 now problem is inserting record in nested list view see error... Inserting is not supported by data source 'SqlDataSource2' unless InsertCommand is specified. another problem when i keep datasource2 in LV1 selected template but datasource2 is not binding lv2.. how can bind lv2...? 回答1: you need to bind second listview in first listview row databound event like: In first listview databound event, first you need to finding the second

问题 I have a problem with this piece of code: var elements; var current = 100; $(document).ready(function() { elements = = $('.slide').length; iterate(); }); function iterate() { $('.slide').eq(current).hide().queue( function() { if (++current >= elements) { current = 0; } $('.slide').eq(current).show(); $(this).dequeue(); } ); // Call this function again after the specified duration setTimeout(iterate, 1000); } What I'm trying to do is iterate all elements with 'slide' class but I have a problem

问题 i'm incredibly new to python so please forgive me if i don't understand something!! I've got a 125 lines of code but I have one problem section. as it's currently set up, there is an incorrectly spelled word. it links to similarly spelled words in the dictionary, and the words have a score based off of how similar they are. possible_replacements("sineaster", {"sineaster":{"easter":0.75, "sinister":0.60}}) possible_replacements is the name of the function, "sineaster" is the misspelled word,

问题 The MySQL query: SELECT title,alias,parent FROM '._prefix.'categories WHERE (language = \''._language.'\' || language = \'all\') && status = \'published\' ORDER BY rank ASC The Result (from phpMyAdmin): title | alias | parent Home | home | 0 Todo | todo | 0 Multiuser| todo_mu | 21 Modulsys | todo_mod | 21 The PHP: while($c = mysql_fetch_array($category_result)) { if($c['parent'] == 0) { $output .= '<li><a href="'._rewrite_string.$c['alias'].'" title="'.$c['title'].'">'.$c['title'].'</a>';

问题 I'm trying to develop a simple function that returns the smallest and largest value in Lisp. So far I have the basic solution working for a single Lisp and here is the code (defun get-smallest-large (lst &optional (smallest 0) (largest 0)) (setf smallest (first lst)) (setf largest 0) (dolist (nxt lst) (if (< nxt smallest) (setf smallest nxt) (if (> nxt largest) (setf largest nxt)))) (cons smallest largest)) This works like: (defun get-smallest-large '(1 2 -1 3)) = (-1 . 3) Now, I can't for

问题 I want to create a nested array in Javascript but can't do the thing what I want, I don't know if it is even possible. Here is an example of what kind of array I want to create: var array = ['id1', 'id2', 'id3', 'id4']; Then I want to add new array for each id such way that id values stayed the same. Why? because I want to use indexOf method to find out the element index of main array with sub array id. Something like this: array[0]['par1'] should return the value of parameter1 array[0]['par2

问题 How i can represent a tree from a nested list? L = [['bike', '2 * wheel+1* frame'], ['wheel', '1*rim+1*spoke+1*hub'], ['rim', 60],['spoke', 120] Tree = ['bike', 2, ['wheel', 1, ['rim', 60], 1, ['spoke', 120], 1, ['hub', 2]] Explanation : In this example bike is made from 2 wheels and 1 frames, wheel is made from 1 rim,1spoke and 1 hub ['rim', 60] means that rim's price is 60. I could not understand how to convert the list to tree. 回答1: Here're the steps I'd take: Write a function such that f(

问题 I've been searching about how to merge two cells and I've found two answers Rowspan and Nested. I can't make my table with those two functions because I don't know how to merge cells at the begining and at the end. I've been trying many ways but this is driving me crazy. The table I want to make has 9 columns and 3 rows. So, I want the table looks like: | Header 1 | Header 2 | Header 3 | Header 4 | Header 5 | | | | H1 | H2 | H3 | H4 | H5 | | | | D1 | D2 | D3 | D4 | D5 | D6 | D7 | D8 | D9 |

问题 I have just started learning Stata and I'm having a hard time. My problem is this: I have two different variables, ATC and A , where A is potentially a substring of ATC . Now I want to mark all the observations in which A is a substring of ATC with OK = 1 . I tried this using a simple nested loop: foreach x in ATC { foreach j in A { replace OK = 1 if strpos(`x',`j')!=0 } } However, whenever I run this loop no changes are being made even though there should be plenty. I feel like I should

问题 I'm trying to make a Nested Cursor in Mysql by following this instruction. Then i got this issue: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'DECLARE activityids CURSOR FOR SELECT activity_id FROM @_activity; END BLOCK2;' at line 22 I've 2 table 'account' and 'n_activity' (n = account_id in table 'account') Ex: i've table 'account' and '20_activity'. So i want to loop the 'account_id' and get