nested

JSON: Nested Array

此生再无相见时 提交于 2019-12-29 09:06:23
问题 I have a program that retrieves data from a Database (data store in JSON MySQL). public static int selectData(Connection conn, String db_type) throws SQLException { JSONObject obj = new JSONObject(); String q = "SELECT * FROM common_attr_test"; PreparedStatement preparedStatement = conn.prepareStatement(q); preparedStatement.execute(); ResultSet rs = preparedStatement.executeQuery(); while (rs.next()) { String uuid_user = rs.getString("uuid"); String attributes_uuid = rs.getString("attributes

JSON: Nested Array

…衆ロ難τιáo~ 提交于 2019-12-29 09:05:50
问题 I have a program that retrieves data from a Database (data store in JSON MySQL). public static int selectData(Connection conn, String db_type) throws SQLException { JSONObject obj = new JSONObject(); String q = "SELECT * FROM common_attr_test"; PreparedStatement preparedStatement = conn.prepareStatement(q); preparedStatement.execute(); ResultSet rs = preparedStatement.executeQuery(); while (rs.next()) { String uuid_user = rs.getString("uuid"); String attributes_uuid = rs.getString("attributes

Meteor mongo updating nested array

三世轮回 提交于 2019-12-29 08:54:27
问题 Example document: { "_id" : "5fTTdZhhLkFXpKvPY", "name" : "example", "usersActivities" : [ { "userId" : "kHaM8hL3E3As7zkc5", "startDate" : ISODate("2015-06-01T00:00:00.000Z"), "endDate" : ISODate("2015-06-01T00:00:00.000Z") } ] } I'm new in mongoDB and I read other questions about updating nested array and I can't do it properly. What I want to do is to change startDate and endDate for user with given userId. My problem is that it always pushes new object to array instead of changing object

Kendo data grid - how to set column value from nested JSON object?

余生长醉 提交于 2019-12-29 06:58:10
问题 I have JSON with structure like this: "id":1, "user_role":"ADMIN", "state":"ACTIVE", "address":{ "street":"test 59", "city":"City test", "post_number":"25050" }, How I should to pass values of address.street into column using setting in fields and model? Many thanks for any advice. 回答1: If you want to show all values in a single column do what @RobinGiltner suggests. If you want to show each member of address in a different column you can do: var grid = $("#grid").kendoGrid({ dataSource: data

Accessing or creating nested JavaScript objects with string key without eval

那年仲夏 提交于 2019-12-28 06:53:09
问题 I am looking for a nice solution to access a property by string value, but if the property does not exist it should create it. If the root structure already has defined some parts of the structure, the attributes should not be overwritten, but merged instead. For example if you have an empty object test and you want to set a deep structure without using eval. e.g. test = {} test.foo.name = "Hallo" // <<- foo is an Object test.foo[3] = "Test" // <<- foo should remain as Object, not as Array

How to refer to Enclosing class from Inner class?

房东的猫 提交于 2019-12-28 06:50:13
问题 I am extending ArrayList to create a custom ArrayList that can be modified using normal ArrayList methods while iterating over it. For this I am also creating an Iterator. public class SynchronizedList<E> extends ArrayList<E> { // Fields here //Constructors and methods here public class SynchronizedListIterator<E> implements Iterator<E> { public int index; private E current; public boolean hasNext() { synchronized (/* reference to enclosing List object */) { //code goes here } return false; }

How to create a nested array out of an array in PHP

只愿长相守 提交于 2019-12-28 06:49:06
问题 Say, we have an array: array(1,2,3,4,...) And I want to convert it to: array( 1=>array( 2=>array( 3=>array( 4=>array() ) ) ) ) Can anybody help? Thanks EDIT It would be good to have the solution with iterations. 回答1: $x = count($array) - 1; $temp = array(); for($i = $x; $i >= 0; $i--) { $temp = array($array[$i] => $temp); } 回答2: You can simply make a recursive function : <?php function nestArray($myArray) { if (empty($myArray)) { return array(); } $firstValue = array_shift($myArray); return

XPath/XSLT nested predicates: how to get the context of outer predicate?

血红的双手。 提交于 2019-12-28 04:19:11
问题 It seems that this question was not discussed on stackoverflow before, save for Working With Nested XPath Predicates ... Refined where the solution not involving nested predicates was offered. So I tried to write the oversimplified sample of what I'd like to get: Input: <root> <shortOfSupply> <food animal="doggie"/> <food animal="horse"/> </shortOfSupply> <animalsDictionary> <cage name="A" animal="kittie"/> <cage name="B" animal="dog"/> <cage name="C" animal="cow"/> <cage name="D" animal=

OpenMP: What is the benefit of nesting parallelizations?

∥☆過路亽.° 提交于 2019-12-28 03:38:27
问题 From what I understand, #pragma omp parallel and its variations basically execute the following block in a number of concurrent threads, which corresponds to the number of CPUs. When having nested parallelizations - parallel for within parallel for, parallel function within parallel function etc. - what happens on the inner parallelization? I'm new to OpenMP, and the case I have in mind is probably rather trivial - multiplying a vector with a matrix. This is done in two nested for loops.

Solr documents with child elements?

隐身守侯 提交于 2019-12-28 03:04:35
问题 Is it somehow possible to create a solr document that contains sub-elements? For example, how would I represent something like this: <person first="Bob" last="Smith"> <children> <child first="Little" last="Smith" /> <child first="Junior" last="Smith" /> </children> </person> What is the usual way to solve this problem? 回答1: You can model this in different ways, depending on your searching/faceting needs. Usually you'll use multivalued or dynamic fields. In the next examples I'll omit the