nan

问题 I'm grabbing a JSON obj from an external source. It appears as so: {"total":16231642,"totalamount":437442282.55} I set it as a global var, set it in the each function and then try to retrieve it outside of it, below. But i get a Nan as the value. The value is deifinitely being set in the function so i am not entirely sure why this is happening. Any help is appreciated! $( document ).ready(function() { var todaystart; //Get vals from JSON txt $.getJSON( "proxy.php", function( data ) { $.each

问题 I'm trying to remove my NaNs in a very large list. Removing NAs is quite easy with My.List[!is.na(My.List)] But using My.List[!is.nan(My.List)] is not an implemented method for lists (R-Error). Can you help me? Thanks! 回答1: Try MyList <- na.omit(My.List) 回答2: You can use sapply to find the NaN s > x <- list(1, NaN, 3) > > x[!sapply(x, is.nan)] [[1]] [1] 1 [[2]] [1] 3 来源： https://stackoverflow.com/questions/44231564/how-to-remove-nan-in-large-list

问题 from dateutil.rrule import rrule, MONTHLY def fread_year_month(strt_dt, end_dt): dates = [dt for dt in rrule(MONTHLY, dtstart=strt_dt, until=end_dt)] return dates df = pd.DataFrame({ 'value' : [4,2,5,6,7,8,6,5,4,1,2,4], 'date': fread_year_month(dt.datetime(2015, 1, 1),dt.datetime(2015, 12, 1)), 'stock': ['amzn']*12 },columns=[ 'value', 'date', 'stock'] ) df2 = pd.DataFrame({ 'value' : [1,1,1,1,1], 'date': fread_year_month(dt.datetime(2015, 1, 1),dt.datetime(2015, 5, 1)), 'stock': ['msft']*5 }

问题 What is an efficient way to check a large matrix for inf / nan elements in CUDA (C++)? The matrix is stored as float* in the GPU memory. I don't need the location of those elements, just a boolean yes/no answer if at least one bad entry is present. The options are: have one kernel check the whole array (easy to implement but probably slow) have multiple kernels check e.g. the rows and combine the output with OR (are there any CUDA builtins for doing this efficiently?) ..other ideas? Thanks!

问题 I'm struggling to apply some code to a different application which @crazyGamer gave me, let me explain. I will get to the problem, but for now, here is my data: %% Grid setup O = -40:10:+50; H = [-1500,-1000:1000:20000]; [OAT,Hp] = meshgrid(O,H); HpScale = Hp/1000; %% Data I have M = [ 5227.705922 5012.706706 4814.693406 4631.729567 4462.162313 4304.572261 4157.733705 4020.582668 3892.191077 3771.745739 5199.06906 4985.247589 4788.318986 4606.357406 4437.719024 4280.992235 4134.958046 3998

问题 I am trying to get the difference in days between two dates pulled from a SQL database. One is the start date, the other is a completed date. The completed date can and is, in this case, be a NaT value. Essentially I'd like to iterate through each row, and take the difference, if the completed date is NaT I'd like to skip it or assign a NaN value, in a completely new delta column. the code below is giving me this error: 'member_descriptor' object is not callable for n in df.FINAL_DATE: df

问题 I have a large data set which consists of a columns of IDs followed by a monthly time series for each ID. There are frequent missing values in this set, but what I would like to do is replace all NAs after the first non-zero with a zero while leaving all the NAs before the first non-zero value as NA's. eg. [NA NA NA 1 2 3 NA 4 5 NA] would be changed to [NA NA NA 1 2 3 0 4 5 0] Any help or advice you guys could offer would be much appreciated! 回答1: Easy to do using match() and numeric indices:

问题 Language: Java, IDE: eclipse mars The program is supposed to prompt the user (using JOptionPane) for a positive value. I'm trying to catch the invalid entries. My while statement catches the negative numbers but not the strings. When a negative number is entered, the prompt is shown again, but when a string value is entered, the exception is caught and the program moves on (when it should re prompt the user). Once a positive value has been entered, the program assigns it to a value in another

问题 The following is my code: #include <stdlib.h> #include <stdio.h> #include <limits> #define INFINITY std::numeric_limits<float>::infinity() #define NEGINFINITY -std::numeric_limits<float>::infinity() int floatcomp(const void* elem1, const void* elem2) { if (*(const float*)elem1 < *(const float*)elem2) return -1; return *(const float*)elem1 > *(const float*)elem2; } int main() { float array[10] = {INFINITY, 3.5f, 144.4f, NAN, 12.4f, NEGINFINITY, 1.4f, -0.0f, 5.9f}; int i; for (i = 0; i < 10; i+

问题 NaN` means "Not a Number". However I found out that the result of is.numeric(NaN) is [1] "TRUE" Anybody know why? I think the result should be FALSE . 回答1: "Not a Number" does not really mean it is not a number. It is a special coding of a floating-point number. See ANSI/IEEE 754 floating-point standard , or simply the Wikipedia page for NaN. This is a universal standard for all computing languages and R's handling is no exception. In R, typeof(NaN) gives "double", and mode(NaN) gives