mysql

问题 UPDATE `pams_faker_lead_location` SET `location` = ( SELECT location FROM pams_leads WHERE pams_leads.location_id = pams_faker_lead_location.id ) I dont know when i run the query in Mysql , this error occur. #1242 - Subquery returns more than 1 row anyone can help me solve the problem ? 回答1: This query: SELECT location FROM pams_leads WHERE pams_leads.location_id = pams_faker_lead_location.id gives you more than 1 row. You must change something because if you need update value you need

问题 I am running a local mysql database on my computer using wampserver. I have made a c# console application that I want to use to update values in a table. However I am having issues connecting to the database. My password is an empty string. string user = "John Doe"; string queryString = "UPDATE users SET is_awesome=1 WHERE user=@a1"; string connectionString = "Server=localhost;Database=mydatabase;User Id=root;Password=;"; SqlConnection connection = new SqlConnection(connectionString);

问题 Sample database design USERS WORKDAYS DAYS [id] [name] [user_id] [day_id] [id] [name] 1 john 1 2 1 sunday 2 fred 1 3 2 monday 3 bert 1 4 3 tuesday 4 harry 1 5 4 wednesday 1 6 5 thursday 2 2 6 friday 4 1 7 saturday 4 2 4 3 4 4 4 5 4 6 4 7 How would I query Someone like John, who works exactly all workdays of the week: monday, tuesday, wednesday, thursday, friday Someone like Harry and John who works at least all those days? I work with mysql some time but I cannot find a solution at the moment

问题 I am running a local mysql database on my computer using wampserver. I have made a c# console application that I want to use to update values in a table. However I am having issues connecting to the database. My password is an empty string. string user = "John Doe"; string queryString = "UPDATE users SET is_awesome=1 WHERE user=@a1"; string connectionString = "Server=localhost;Database=mydatabase;User Id=root;Password=;"; SqlConnection connection = new SqlConnection(connectionString);

问题 Sample database design USERS WORKDAYS DAYS [id] [name] [user_id] [day_id] [id] [name] 1 john 1 2 1 sunday 2 fred 1 3 2 monday 3 bert 1 4 3 tuesday 4 harry 1 5 4 wednesday 1 6 5 thursday 2 2 6 friday 4 1 7 saturday 4 2 4 3 4 4 4 5 4 6 4 7 How would I query Someone like John, who works exactly all workdays of the week: monday, tuesday, wednesday, thursday, friday Someone like Harry and John who works at least all those days? I work with mysql some time but I cannot find a solution at the moment

问题 I'm trying to create an MySQL cluster of 3 nodes using mysql-server docker containers. I have 3 separate cloud instances and docker is setup on all 3 of them. Each server will have only 1 container running on it - to achieve High Availability when in cluster. I start the containers on all 3 servers, individually, with the command docker run --name=db -p 3301:3306 -v db:/var/lib/mysql -d mysql/mysql-server I'm mapping the port 3306 of container to my server's 3301 port . I've also created a

问题 I'm trying to create an MySQL cluster of 3 nodes using mysql-server docker containers. I have 3 separate cloud instances and docker is setup on all 3 of them. Each server will have only 1 container running on it - to achieve High Availability when in cluster. I start the containers on all 3 servers, individually, with the command docker run --name=db -p 3301:3306 -v db:/var/lib/mysql -d mysql/mysql-server I'm mapping the port 3306 of container to my server's 3301 port . I've also created a

问题 I want to grant select privilege to user from every host, but getting an error, you're not allow to create a user mysql> GRANT SELECT ON *.* TO 'alice'@'%' WITH GRANT OPTION; ERROR 1410 (42000): You are not allowed to create a user with GRANT I don't want to create a new user, for that I used command CREATE USER I tried to create a new user but the grant command also failed. 回答1: A good idea (and a good practice) in this MySql Version (8 and above) is to config ROLES and then set the users

问题 I have a typical LAMP based site + Zend Framework where I have a base table and a summary table. Summary table is used to display data in reports. Base table - ID | Status 1 | 1 2 | 1 3 | 2 4 | 2 5 | 1 6 | 1 Summary table - Status | Count 1 | 4 2 | 2 The base table will be changed(insert,update,delete) at an average of 20 times per day. Currently, I am using triggers to call a stored procedure which will update the summary table based on the base table. This is the stored procedure. CREATE

问题 I have a typical LAMP based site + Zend Framework where I have a base table and a summary table. Summary table is used to display data in reports. Base table - ID | Status 1 | 1 2 | 1 3 | 2 4 | 2 5 | 1 6 | 1 Summary table - Status | Count 1 | 4 2 | 2 The base table will be changed(insert,update,delete) at an average of 20 times per day. Currently, I am using triggers to call a stored procedure which will update the summary table based on the base table. This is the stored procedure. CREATE