mysql | 易学教程

Composite Primary Key and Auto_Increment [duplicate]

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问题 This question already has answers here : mysql two column primary key with auto-increment (4 answers) Closed 7 years ago . I'm trying to do the composite key with one of them auto incrementing, but when I try to enter a new row it just continue the sequential. Here's the example of what happens: Item_1 | Item_2 1 | 1 1 | 2 2 | 3 2 | 4 2 | 5 Here's the example of what I want: Item_1 | Item_2 1 | 1 1 | 2 2 | 1 2 | 2 2 | 3 I create the table this way: CREATE TABLE IF NOT EXISTS `usuarios` ( `cod

Composite Primary Key and Auto_Increment [duplicate]

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node.js mysql query in a for loop

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问题 I have two queries. The first, SELECT auctions.name, wowitemdata.itemName, auctions.itemId, auctions.buyout, auctions.quantity FROM auctions INNER JOIN wowitemdata ON auctions.itemId = wowitemdata.itemID; returns data like this: { name: 'somename', itemName: 'someitemname', itemId: '0000', buyout: '0001', quantity: '5', } The 2nd query uses data from the #1 to get the count() of items cheaper than itemId. The response is to be added to #1 as a new element -> 'undercut'. My function: function

Display progress bar while the php script is running through ajax

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问题 I have a form that submit value to the server though ajax. <form> <input id="titlee" name="titlee"> <input type="file" name="fileToUpload" id="fileToUpload"> <button type="submit" value="submit" id="submit" name="submit">Start</button> <div class="progress"></div> </form> Script <script type="text/javascript"> $(function() { $("#submit").click(function() { var titlee = $("#titlee").val(); var fileToUpload= $("#fileToUpload").val(); var dataString = 'titlee='+ titlee + '&fileToUpload=' +

ASP.NET Core快速入门（第3章：依赖注入）--学习笔记

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点击蓝字关注我们课程链接：http://video.jessetalk.cn/course/explore 良心课程，大家一起来学习哈！任务16：介绍 1、依赖注入概念详解从UML和软件建模来理解从单元测试来理解 2、ASP.NET Core 源码解析任务17：从UML角度来理解依赖 1、什么是依赖当一个类A完成某个任务需要另一个类B来帮助时，A就对B产生了依赖例如CustomerController需要对customer进行新增或查找时用到EF,则对EF的Context产生了依赖 var context = new CustomerContext( new DbContextOptions<CustomerContext>{}); 2、显示依赖与隐式依赖显示依赖：把一个类用到的所有外部组件放到一个类最上面，在构造函数里面初始化 private CustomerContext _context; public CustomerController () { _context = new CustomerContext( new DbContextOptions<CustomerContext>{}); } 隐式依赖：需要用到的地方再初始化，不推荐 var context = new CustomerContext( new DbContextOptions

Mysql下载与安装

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前言：利用别人的方法、知识、经历或精神成为你自己，不思考不实践不总结不反馈，就不会变成你的。 1.下载（1）打开 https://dev.mysql.com/downloads/mysql/ ，下拉，根据个人需求选择合适的版本，我的是Windows10 64位此次选择5.6版本（2）单击5.6版本，往下拉，根据系统选择对应的版本，本人选择64位的，该包是免安装包，需要自己配置环境，官方给的是免安装包，有图形化安装版可以到这个网址http:/ /www.pc6.com/softview/SoftView_41452.html下载，新手建议先使用图形化安装版（3）单击 No thanks, just start my download. （4）弹出下载界面，自定义下载路径，然后下载（5）解压指定的目录下，不建议放在C盘或桌面上，最好放在其他盘上 2.安装（1）依次操作：计算机–右键–属性–高级系统设置–环境变量（2）新建，变量名取Path，变量值即原来解压该软件的路径下的bin目录，点击确定(注意加上\bin) （3）在安装目录下新建文本，点击进去配置相关的参数，点文件另存为，文件名为my.ini,保存类型所有文件，编码ANSI，保存到安装目录下，并将其my.ini复制到目录下（4）注册服务在开始处搜索框输入cmd回车，右击命令提示符，以管理员身份运行回车输入

MySQL query builder PHP class

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问题 I am building application which needs to have OOP style MySQL query builder. I want to be able to flexibly build complex queries using only PHP and to get resulting query string for execution with my own database driver. Does anyone know of a good standalone query builder for PHP? Please note that I don't need database driver I need bare MySQL query builder class (preferably written with camel style function and variable names). 回答1: Finally I took Doctrine ORM and modified it little bit to

LAMP服务环境搭建

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操作系统：CentOS Linux release 7.9 一、安装Apache 1.安装Apache依赖库和相关软件包 # wget -c http://archive.apache.org/dist/apr/apr-1.6.3.tar.gz [root@Linux tool]# tar zxvf apr-1.6.3.tar.gz [root@Linux tool]# cd arp-1.6.3 [root@Linux apr-1.6.3]# ./configure --prefix=/usr/local/apr [root@Linux apr-1.6.3]# make -j 8 && make install # wget https://mirror.bit.edu.cn/apache//apr/apr-util-1.6.1.tar.gz [root@Linux /]# yum install expat expat-devel [root@Linux tool]# tar zxvf apr-util-1.6.1.tar.gz [root@Linux tool]# cd apr-util-1.6.1 [root@Linux apr-util-1.6.1]# ./configure --prefix=/usr/local/apr-util --with-apr=/usr

MySQL LEFT JOIN with GROUP BY and WHERE IN (sub query)

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问题 I have one table with some statistics per date, which I want listed out with MySQL. For some dates there will be no statistics, so the result should look something like this: 2013-03-01: 3 2013-03-02: 2 2013-03-03: 0 2013-03-04: 1 I figured out that filling in the gaps with 0 -zero- could be solved with a separate table with all possible dates and LEFT JOIN. So far so good. The statistics (impressions) is in the table 'campaigndata': id - int(11) date - date campaignid - int(11) impressions -

MySQL ERROR 2026 - SSL connection error - Ubuntu 20.04

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问题 I've recently upgraded my local machine OS from Ubuntu 18.04 to 20.04, I'm running my MySQL-server on CentOS (AWS). Post upgrade whenever I'm trying to connect to MySQL server it is throwing SSL connection error. $ mysql -u yamcha -h database.yourproject.com -p --port 3309 ERROR 2026 (HY000): SSL connection error: error:1425F102:SSL routines:ssl_choose_client_version:unsupported protocol But if I pass --ssl-mode=disabled option along with it, I'm able to connect remotely. $ mysql -u yamcha -h