mysql-num-rows

PHP / MYSQL error: mysql_num_rows(): supplied argument is not a valid [closed]

雨燕双飞 提交于 2019-12-12 01:47:51
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . I have the following code: $sql = mysql_query("SELECT id FROM logins WHERE id='" . $this->skID . "'"); if(mysql_num_rows($sql) == 0) { return false; } else { list($skID) = mysql_fetch_row($sql); return $skID; } which brings back the below error. mysql_num_rows(): supplied argument is not a valid MySQL result

Selecting MySQL query via PHP variables

最后都变了- 提交于 2019-12-12 00:12:58
问题 I am getting zero in $booked_num , I tried the query in SQL with values in place of variables, it worked fine. But I don't know where I am making a mistake, please help. I already echoed every variable and everything is fine, but nothing is there in $booked_row and $booked_num is echoing zero. require_once 'mysql_connector.php'; $booked_result = mysql_query('select * from booked where train_no = ".$train_no." and date = ".$date." and st_from = ".$st_from." and st_to = ".$st_to.";') or die

mysql_numrows() error in MySQL Query Web Page Display

隐身守侯 提交于 2019-12-12 00:12:04
问题 I am writing a web page that selects certain fields from a database that meet a criteria. A connection to the database is made, but nothing displays in the table but the header. In the Apache2 logs I see [Mon May 07 01:30:21 2012] [error] [client MyIP] PHP Notice: Use of undefined constant localhost - assumed 'localhost' in /var/www/medical.php on line 3 [Mon May 07 01:30:21 2012] [error] [client MyIP] PHP Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in /var/www

Error Help: Warning: mysql_num_rows() expects parameter 1 to be resource

你离开我真会死。 提交于 2019-12-11 04:54:04
问题 I'm building a simple PHP CRUD app and I'm running into this error: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in <?php $query = "select * from user"; $result = mysql_query($query); if (mysql_num_rows($result) > 1) { echo "<table align='center' border='1'>"; echo "<tr>"; echo "<th>Id</th>"; echo "<th>Username</th>"; echo "<th>Password</th>"; echo "</tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>".$row['id']."</td>"; echo "<td>".$row[

num_rows() not returning correct number of row when result is not empty

ぐ巨炮叔叔 提交于 2019-12-08 12:15:29
问题 I am working on one Join query in CodeIgniter. Query run perfectly fine. The problem is $query->num_rows() .This is how I write my join query. $this->db->select('related colums'); $this->db->from('table1 as t1'); $this->db->join('table2 as t2', 't1.id = t2.id', 'left outer'); $this->db->join('table3 as t3', 't1.id_second = t3.id', 'left outer'); $this->db->where('t1.column', $some_varibale); $this->db->order_by("t1.column", "desc"); $query = $this->db->get(); $query_result = $query->result

PHP MySQLi num_rows Always Returns 0

本小妞迷上赌 提交于 2019-12-05 12:58:16
I have built a class which leverages the abilities of PHP's built-in MySQLi class, and it is intended to simplify database interaction. However, using an OOP approach, I am having a difficult time with the num_rows instance variable returning the correct number of rows after a query is run. Take a look at a snapshot of my class... class Database { //Connect to the database, all goes well ... //Run a basic query on the database public function query($query) { //Run a query on the database an make sure is executed successfully try { //$this->connection->query uses MySQLi's built-in query method,

Proper way to ask if mysql_num_rows in PHP

本秂侑毒 提交于 2019-12-03 21:09:37
Because mysql_num_rows returns false if there are no rows returned, would it be best to do: $query = mysql_query("SELECT id FROM table WHERE something = 'this'"); $result = mysql_num_rows($query); if ($result) { } Or should I do: if ($result >= 1) { } The proper one $result = mysql_query("SELECT id FROM table WHERE something = 'this'"); if (mysql_num_rows($result)){ //there are results } however, you could do this easier, without checking $result = mysql_query("SELECT id FROM table WHERE something = 'this'"); while($row = mysql_fetch_assoc($result)) //there are results } Please. Give your

$result->num_rows always returns 0

痞子三分冷 提交于 2019-12-02 04:23:20
after reading tons of threads, tutorials and whatever - I feel like posting here and hope that someone can help me. I tried out every advice I could get, but it's still not working. Here is my code : $prep_stmt = "SELECT id, DATE_FORMAT(added,'%d.%M'), title FROM offers ORDER BY added DESC LIMIT ?, ?;"; $stmt = $mysqli->prepare($prep_stmt); $stmt->bind_param ('ii',$lowlimit, $page); $stmt->execute(); $stmt->bind_result($id, $added, $title); while ($stmt->fetch()) { ... # some random output here } $count = $stmt->num_rows; echo "c -> ". $count;exit; I always get "c -> 0" ... but there IS output

Mysqli Prepared Stmt returns 0 num_rows

雨燕双飞 提交于 2019-12-01 12:50:23
Help. I am getting 0 num_rows but if i execute the query in the console i am getting results. I m kinda new to prepared stmts. Here is my code Database connection class: class DbConnection { const HOST = "localhost"; const USR = "root"; const PWD = ""; const DB = "club_db"; } Login class: class UsrLogin extends DbConnection { private $conn; /*db connector*/ /*login vars*/ private $usr; private $pwd; /*ctrl var*/ public $AccessGranted = false; function __construct($username,$password){ /*initialize db connection*/ $this->conn = new mysqli(DbConnection::HOST,DbConnection::USR,DbConnection::PWD

PHP and MySQL: Number of rows returned

梦想与她 提交于 2019-12-01 11:29:11
How can I see how many rows the following query returns? mysql_select_db($database_aoldatabase, $aoldatabase); $query1 = "select * from sale where secid = $invoiceno "; $query2 = "select * from sale where secid = $invoiceno "; $maxa = mysql_query ($query1) or die ("Query '$query' failed with error message: \"" . mysql_error () . '"'); $maxa2 = mysql_query ($query2) or die ("Query '$query' failed with error message: \"" . mysql_error () . '"'); $row = mysql_fetch_array($maxa); $row2 = mysql_fetch_array($maxa2); Like Michiel said, mysql_num_rows() do the job. But if you want to work with more