mysql-5.0

How to use like clause in MySQL 5.0 Statement

由 一曲冷凌霜 提交于 2019-12-24 14:13:57
问题 I have a problem using 'like' clause in MySQL 5.0 I have written a stored procedure in MySQL 5.0 and calling the Stored Procedure from my Java Program the stored procedure below in the select statement i want to take the value of parameter departmentname for like clause please Help with this DROP PROCEDURE IF EXISTS upSelTests; DELIMITER // CREATE PROCEDURE upSelTests ( IN departmentname varchar(50), IN testDateFrom varchar(10), IN testDateTo varchar(10) ) BEGIN declare testDateFrom1 varchar

Creating a Ternary Relationship

由 淺唱寂寞╮ 提交于 2019-12-24 09:41:25
问题 How can I make ternary relationship using power designer? 回答1: The short answer is that you cannot. But you can represent the same concept. Assuming you trying to do that in the Conceptual Data Model, it depends of the Notation you are using (under Tools > Models Options ). With Entity/Relationship, it looks like you cannot do it. With Merise, you create an Association with links toward the 3 entities. With IDEF1X, you create an Entity with dependent relationships toward the 3 entities. 来源：

Using “TYPE = InnoDB” in MySQL throws exception

由 一个人想着一个人 提交于 2019-12-21 03:28:25
问题 When I try to execute the following SQL in MySQL , I'm getting error: SQL: SQL = "CREATE TABLE Ranges ("; SQL += "ID varchar(20) NOT NULL, "; SQL += "Descriptions longtext NULL, "; SQL += "Version_Number int NULL, "; SQL += "Row_Updated bigint NULL, "; SQL += "Last_Updated datetime NULL, "; SQL += "XML longtext NULL, "; SQL += "PRIMARY KEY (ID)"; SQL += ") " + "TYPE = InnoDB"; Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the

How to use subquery in delete/update query in mysql

由 三世轮回 提交于 2019-12-13 07:05:11
问题 I am using a mysql 5.0.77 database using the query: Delete from IPADDRESS where visitdate Not in (SELECT max(visitdate) FROM IPADDRESS WHERE USERNAME='MGSH0002') and USERNAME='MGSH0002' I am getting this error when executed: You can't specify target table IPADDRESS for update in from clause 回答1: Certainly not the best solution but for your problem this will do the trick: delete i1 from IPADDRESS i1, IPADDRESS i2 where i1.username = i2.username and i1.username = 'MGSH0002' and i1.visitdate <

Inserting integer and datetime from PHP to MySQL 5.0 db error

由 ╄→гoц情女王★ 提交于 2019-12-13 01:10:59
问题 I have tried to find out what's wrong. The table is conditions_loop. One column is condition_id, and the other one is a datetime type. the code is this $dt = date("Y-m-d H:i:s"); mysql_query("INSERT INTO conditions_loop (condition_id, date) VALUES ($latest_condition, $dt)") or die(mysql_error()); $latest_condition is a 1 digit integer. The error says You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '13:12:14)

How do I list the first value from a three-way joined table query?

由 可紊 提交于 2019-12-06 13:40:37
问题 Ugh ok I'm terrible at explaining things, so I'll just give you the quotes and links first: Problem 4b (near bottom): 4b. List the film title and the leading actor for all of 'Julie Andrews' films. movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) (Note: movie.id = casting.movieid, actor.id = casting.actorid) My answer (doesn't work): SELECT title, name FROM casting JOIN movie ON casting.movieid = movie.id JOIN actor ON casting.actorid = actor.id

MySql FLOAT datatype and problems with more then 7 digit scale

由 蹲街弑〆低调 提交于 2019-12-06 05:55:57
问题 We are using MySql 5.0 on Ubuntu 9.04. The full version is: 5.0.75-0ubuntu10 I created a test database. and a test table in it. I see the following output from an insert statement: mysql> CREATE TABLE test (floaty FLOAT(8,2)) engine=InnoDb; Query OK, 0 rows affected (0.02 sec) mysql> insert into test value(858147.11); Query OK, 1 row affected (0.01 sec) mysql> SELECT * FROM test; +-----------+ | floaty | +-----------+ | 858147.12 | +-----------+ 1 row in set (0.00 sec) There seems to be a

Which update is faster using join or sequential?

由 ￡可爱￡侵袭症＋ 提交于 2019-12-05 07:49:50
问题 This question is in sequence of my previous Question required update same table on deletion a row. I could write two solutions using Stored Procedure instead of trigger or nested-query . Both use a helper function my_signal(msg). A Stored Procedure to delete employee from Employee Table. Fist Solution : use UPDATE rows in table, without join operation : CREATE PROCEDURE delete_employee(IN dssn varchar(64)) BEGIN DECLARE empDesignation varchar(128); DECLARE empSsn varchar(64); DECLARE empMssn

How do I list the first value from a three-way joined table query?

由 不打扰是莪最后的温柔 提交于 2019-12-04 18:38:56
Ugh ok I'm terrible at explaining things, so I'll just give you the quotes and links first: Problem 4b (near bottom): 4b. List the film title and the leading actor for all of 'Julie Andrews' films. movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) (Note: movie.id = casting.movieid, actor.id = casting.actorid) My answer (doesn't work): SELECT title, name FROM casting JOIN movie ON casting.movieid = movie.id JOIN actor ON casting.actorid = actor.id WHERE name = 'Julie Andrews' AND ord = 1 The problem here is that it wants the list of lead actors of

Using “TYPE = InnoDB” in MySQL throws exception

由 怎甘沉沦 提交于 2019-12-03 09:40:48
When I try to execute the following SQL in MySQL , I'm getting error: SQL: SQL = "CREATE TABLE Ranges ("; SQL += "ID varchar(20) NOT NULL, "; SQL += "Descriptions longtext NULL, "; SQL += "Version_Number int NULL, "; SQL += "Row_Updated bigint NULL, "; SQL += "Last_Updated datetime NULL, "; SQL += "XML longtext NULL, "; SQL += "PRIMARY KEY (ID)"; SQL += ") " + "TYPE = InnoDB"; Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near "TYPE = InnoDB" But if I remove "TYPE = InnoDB" , then the query works fine.
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