multiplying

mysql: how to sum multiplied partials

南楼画角 提交于 2019-12-01 18:14:24
问题 Having tables like: sold_items: code | size | quantity abc123 | small | 4 abc123 | medium | 2 xyz987 | small | 3 xyz987 | medium | 1 xyz987 | large | 2 price_list: code | size | price abc123 | small | 5 abc123 | medium | 7 abc123 | large | 9 xyz987 | small | 10 xyz987 | medium | 13 xyz987 | large | 15 which would be your best (faster query) approach to get results: code | sold_items | cash abc123 | 6 | 34 xyz987 | 6 | 73 回答1: This should work: SELECT si.code, SUM(si.quantity), SUM(si.quantity

mysql: how to sum multiplied partials

江枫思渺然 提交于 2019-12-01 18:10:27
Having tables like: sold_items: code | size | quantity abc123 | small | 4 abc123 | medium | 2 xyz987 | small | 3 xyz987 | medium | 1 xyz987 | large | 2 price_list: code | size | price abc123 | small | 5 abc123 | medium | 7 abc123 | large | 9 xyz987 | small | 10 xyz987 | medium | 13 xyz987 | large | 15 which would be your best (faster query) approach to get results: code | sold_items | cash abc123 | 6 | 34 xyz987 | 6 | 73 This should work: SELECT si.code, SUM(si.quantity), SUM(si.quantity * pl.price) as cash FROM sold_items si INNER JOIN price_list pl ON pl.code = si.code AND pl.size = si.size

Do modern cpus skip multiplications by zero?

試著忘記壹切 提交于 2019-12-01 18:08:27
I would like to know if current cpus avoid multiplying two numbers when at least one of them is a zero. Thanks Modern CPUs - what do you mean by that? Do you mean most commonly used (like x86, AMD64, ARM) or most recently developed. Every processor architecture has it's own properties. Moreover, each company (like Intel or AMD) can make processor different way (that usually being company secret). As you question goes, I doubt that. You know, even checking if number is equal to zero twice prior EVERY multiplication is too much overhead, if you account how low percentage of multiply operations

How can I multiply really big numbers c++

旧街凉风 提交于 2019-12-01 17:43:44
问题 I have the following code int i, a, z; i = 2343243443; a = 5464354324324324; z = i * a; cout << z << endl; When these are multiplied it gives me -1431223188 which is not the answer. How can I make it give me the correct answer? 回答1: As Jarod42 suggested is perfectly okay, but i am not sure whether overflow will take place or not ? Try to store each and every digit of number in an array and after that multiply. You will definitely get the correct answer. For more detail how to multiply using

Do modern cpus skip multiplications by zero?

穿精又带淫゛_ 提交于 2019-12-01 17:11:20
问题 I would like to know if current cpus avoid multiplying two numbers when at least one of them is a zero. Thanks 回答1: Modern CPUs - what do you mean by that? Do you mean most commonly used (like x86, AMD64, ARM) or most recently developed. Every processor architecture has it's own properties. Moreover, each company (like Intel or AMD) can make processor different way (that usually being company secret). As you question goes, I doubt that. You know, even checking if number is equal to zero twice

Using awk how do I combine data in two files and substitute values from the second file to the first file?

懵懂的女人 提交于 2019-12-01 14:54:36
Any ideas how to the following using awk? Two input files, data.txt and keys.txt: data.txt contains some data: A;1 B;2 A;3 keys.txt contains "key;value" pairs ("C" is in this example not part of data.txt, but the awk script should still work): A;30 B;20 C;10 The output should be as follows: A;1;30 B;2;20 A;3;30 Hence, each row in data.txt that contains any key from keys.txt should get the corresponding value appended to the row in data.txt. awk to the rescue! assumes the second file has unique keys unlike first file (if not you need to specify what happens then) $ awk 'BEGIN {FS=OFS=";"} NR=

ListView and items with countdown timer

谁说我不能喝 提交于 2019-12-01 03:29:32
i have a issue with my Listview, i want to set a countdown timer to all ListView's items, and i allready have googled a solution for this, but it isn't work correctly. The Problem is that ListView reuses(recycling) a views, and i always get a wrong item time. I use a tag for my view, but it still not work, i can't understand where i made a mistake, please help me. thx. So here a pictures that shows my problem: pic1 Where i've just started an Activity; pic2 Where i've just scrolled down and up And here my code(whole class): UPDATED public class PromoListActivity extends SherlockActivity {

Multiplying int with long result c#

喜你入骨 提交于 2019-11-30 22:57:05
Wonder why. C# .Net 3.5 int a = 256 * 1024 * 1024; int b = 8; long c = b * a; Console.WriteLine(c);//<-- result is -2147483648 Where does this minus from? Where does this minus from? From the integer overflow. Note that your code is equivalent to: int a = 256 * 1024 * 1024; int b = 8; int tmp = b * a; long c = tmp; Console.WriteLine(c); I've separated out the multiplication from the assignment to the long variable to emphasize that they really are separate operations - the multiplication is performed using Int32 arithmetic, because both operands are Int32 - the fact that the result is assigned

Multiplying int with long result c#

拟墨画扇 提交于 2019-11-30 17:28:02
问题 Wonder why. C# .Net 3.5 int a = 256 * 1024 * 1024; int b = 8; long c = b * a; Console.WriteLine(c);//<-- result is -2147483648 Where does this minus from? 回答1: Where does this minus from? From the integer overflow. Note that your code is equivalent to: int a = 256 * 1024 * 1024; int b = 8; int tmp = b * a; long c = tmp; Console.WriteLine(c); I've separated out the multiplication from the assignment to the long variable to emphasize that they really are separate operations - the multiplication

Multiply char by integer (c++)

China☆狼群 提交于 2019-11-30 13:53:49
Is it possible to multiply a char by an int? For example, I am trying to make a graph, with *'s for each time a number occurs. So something like, but this doesn't work char star = "*"; int num = 7; cout << star * num //to output 7 stars janks I wouldn't call that operation "multiplication", that's just confusing. Concatenation is a better word. In any case, the C++ standard string class, named std::string , has a constructor that's perfect for you. string ( size_t n, char c ); Content is initialized as a string formed by a repetition of character c , n times. So you can go like this: char star