multiple-inheritance

Dealing with Nested React Components' State Changes

寵の児 提交于 2019-12-01 05:36:00
问题 So, I have multiple ReactComponent. Initially, I was thinking that there will be sort of a parent component (let's call this GrandPa) with its own state, and it will pass down some info about its state to another component (call it Parent). Similarly, Parent passes some of his to Child and child to GrandChild. So we have the hierarchy: GrandPa -> Parent -> Child -> GrandChild However, I quickly realized that when I change the state of GrandPa with method this.setState(prevState => (<new state

Why only base class default constructor is called in virtual base multiple inheritance? [duplicate]

隐身守侯 提交于 2019-12-01 05:29:17
问题 This question already has answers here : c++ virtual inheritance (3 answers) Closed 6 years ago . In multiple inheritance, I have a virtual Base class which is inherited by class A and class B . A and B are base classes of AB . Please see the code below. In constructor of A and B , Base(string) constructor is called. I am expecting to get following output: Base::Base(std::string) A::A() B::B() But I am getting following output: Base::Base() A::A() B::B() Why default constructor of Base is

Virtual base classes order of creation

狂风中的少年 提交于 2019-12-01 05:18:42
问题 I have the following problem: struct A1 { A1() { std::cout << "A1, "; } }; struct A2 { A2() { std::cout << "A2, "; } }; struct AA1 : virtual A1, A2 { AA1() { std::cout << "AA1, "; } }; struct AA2 : A1, virtual A2 { AA2(){ std::cout << "AA2, "; } }; struct B : AA1, virtual AA2 { B() { std::cout << "B "; } }; int main() { B b; } When you run this code, the answer is: A1 A2 A1 AA2 A2 AA1 B I want to understand where is the first A1 created. I know the rule that the virtual classes are called

Sequence of constructor calls in multiple inheritance

邮差的信 提交于 2019-12-01 04:36:15
I have tried to find a lot that what if only one class is made virtual in multiple inheritance ? The behaviour of constructor call is not clear to me in this case. Let say for example code- #include<iostream> using namespace std; class grand{ public: grand(){cout<<"grandfather"<<endl;} }; class parent1:virtual public grand{ //virtual used only here public: parent1(){cout<<"parent1 "<<endl;} }; class parent2: public grand{ public: parent2(){cout<<"parent2"<<endl;} }; class child:public parent1,public parent2{ public: child(){cout<<"child"<<endl;} }; int main() { child s; return 0; } The output

How to override a function in another base class?

試著忘記壹切 提交于 2019-12-01 04:35:15
I'm not exactly sure the terminology to use, but here's my example: class Base { public: virtual void test() = 0; }; class Mixin { public: virtual void test() { } }; class Example : public Base, public Mixin { }; int main(int argc, char** argv) { Example example; example.test(); return 0; } I want my Mixin class to implement the pure virtual function Base::test , but when I compile this, it says: test.cpp: In function ‘int main(int, char**)’: test.cpp:15:13: error: cannot declare variable ‘example’ to be of abstract type ‘Example’ Example example; ^ test.cpp:11:7: note: because the following

Multiple inheritance in C#

别来无恙 提交于 2019-12-01 04:24:13
As I am working as a C# developer, I know that we can implement multiple inheritance by use of Interface . Can anybody please provide me link OR code for how to achieve multiple inheritance with C# . I want code for how to achieve multiple inheritance in C# with the use of Interface . Thanks in advance. Here is a good example. http://blog.vuscode.com/malovicn/archive/2006/10/20/How-to-do-multiple-inheritance-in-C_2300_- 2D00 -Implementation-over-delegation-_2800_IOD_2900_.aspx A quick code preview: interface ICustomerCollection { void Add(string customerName); void Delete(string customerName);

virtual method table for multiple-inheritance

六眼飞鱼酱① 提交于 2019-12-01 04:06:58
I'm reading this article " Virtual method table " Example in the above article: class B1 { public: void f0() {} virtual void f1() {} int int_in_b1; }; class B2 { public: virtual void f2() {} int int_in_b2; }; class D : public B1, public B2 { public: void d() {} void f2() {} // override B2::f2() int int_in_d; }; B2 *b2 = new B2(); D *d = new D(); In the article, the author introduces that the memory layout of object d is like this: d: D* d--> +0: pointer to virtual method table of D (for B1) +4: value of int_in_b1 B2* b2--> +8: pointer to virtual method table of D (for B2) +12: value of int_in

Implementing 2 Interfaces with 'Same Name' Properties

狂风中的少年 提交于 2019-12-01 03:35:33
This seems like a reasonable (and maybe simple?) scenario, but how would you do the following: Lets say I have 2 interfaces: Interface ISimpleInterface string ErrorMsg { get; } End Interface Interface IExtendedInterface string ErrorMsg { get; set; } string SomeOtherProperty { get; set; } End Interface I want a class to implement both interfaces: Public Class Foo Implements ISimpleInterface, IExtendedInterface How do I define the ErrorMsg property in the class given that each interface has a different access level? Here is my scenario in case you are wondering: I am writing a UserControl using

In scala multiple inheritance, how to resolve conflicting methods with same signature but different return type?

拜拜、爱过 提交于 2019-12-01 02:29:52
Consider the code below: trait A { def work = { "x" } } trait B { def work = { 1 } } class C extends A with B { override def work = super[A].work } Class C won't compile in scala 2.10, because of "overriding method work in trait A of type => String; method work has incompatible type". How to choose one specific method? I'm afraid there is no way to do that. The super[A].work way works only if A and B have the same return types. Consider this: class D extends B .... val test: List[B] = List(new C(), new D()) test.map(b => b.work) //oops - C returns a String, D returns an Int Scala simply

Multiple inheritance and pure virtual functions

百般思念 提交于 2019-12-01 02:29:06
The following code: struct interface_base { virtual void foo() = 0; }; struct interface : public interface_base { virtual void bar() = 0; }; struct implementation_base : public interface_base { void foo(); }; struct implementation : public implementation_base, public interface { void bar(); }; int main() { implementation x; } fails to compile with the following errors: test.cpp: In function 'int main()': test.cpp:23:20: error: cannot declare variable 'x' to be of abstract type 'implementation' test.cpp:16:8: note: because the following virtual functions are pure within 'implementation': test