multiple-inheritance

In English, a homograph pair is two words that have the same spelling but different meanings. In software engineering, a pair of homographic methods is two methods with the same name but different requirements. Let's see a contrived example to make the question as clear as possible: interface I1 { /** return 1 */ int f() } interface I2 { /** return 2*/ int f() } interface I12 extends I1, I2 {} How can I implement I12 ? C# has a way to do this, but Java doesn't. So the only way around is a hack. How can it be done with reflection/bytecode tricks/etc most reliably (i.e it doesn't have to be a

So, I think the code probably explains what I'm trying to do better than I can in words, so here goes: import abc class foo(object): __metaclass__ = abc.ABCMeta @abc.abstractmethod def bar(self): pass class bar_for_foo_mixin(object): def bar(self): print "This should satisfy the abstract method requirement" class myfoo(foo, bar_for_foo_mixin): def __init__(self): print "myfoo __init__ called" self.bar() obj = myfoo() The result: TypeError: Can't instantiate abstract class myfoo with abstract methods bar I'm trying to get the mixin class to satisfy the requirements of the abstract/interface

I am little confused about vptr and representation of objects in the memory, and hope you can help me understand the matter better. Consider B inherits from A and both define virtual functions f() . From what I learned the representation of an object of class B in the memory looks like this: [ vptr | A | B ] and the vtbl that vptr points to contains B::f() . I also understood that casting the object from B to A does nothing except ignoring the B part at the end of the object. Is it true? Doesn't this behavior is wrong? We want that object of type A to execute A::f() method and not B::f() . Are

I'm binding IList to a GridView. IMyInterface looks like public interface IMyInterface: IHasTotalHours, IHasLines { DateTime GoalStartDate { get; set; } DateTime GoalEndDate { get; set; } } I bind an instance to a Grid like this: IList<IMyInterface> instance= GetMyData(); myGrid.DataSource = instance; myGrid.DataBind(); When bind this to the grid, the only members that show up in the grid are the direct members of IMyInterface: GoalStartDate and GoalEndDate. Why is that? How do I get the grid to display the members of the other interfaces it inherits? Update The inherited interfaces define

Actual question What are my options to workaround the fact that R6 does not support multiple inheritance ? Disclaimer I know that R is primarily a functional language. However, it does also have very powerful object-orientation built in. Plus: I don't see what's wrong with mimicking OOD principles/behavior when you know you're prototyping for an object-oriented language such as C#, Java, etc. your prototypes of apps need to be self-sufficient ("full stack" including DB-backends, business logic and frontends/UI) you have such great "prototyping technology" like R6 and shiny at your disposal

In the python tutorial it's said that " Python supports a limited form of multiple inheritance ". What are the limitations? Apart from @Matt Anderson's answer I think that the limitations is in fact for the old style classes (which the tutorial for Python 2.6 still addresses ). In the Python 3 tutorial the text is now: Python supports a form of multiple inheritance as well . I'm not sure to what limitations the author of the python tutorial was referring, but I would guess it has in part to do with the way that method / attribute lookup is implemented in python (the "method resolution order"

Am I using a feature of Java 8 or misusing it? Refer the code and explanation below to know as to why it was chosen to be like this. public interface Drawable { public void compileProgram(); public Program getProgram(); default public boolean isTessellated() { return false; } default public boolean isInstanced() { return false; } default public int getInstancesCount() { return 0; } public int getDataSize(); public FloatBuffer putData(final FloatBuffer dataBuffer); public int getDataMode(); public boolean isShadowReceiver(); public boolean isShadowCaster(); //TODO use for AABB calculations

I am reading "Inside the C++ Object Model", trying to understand how multiple and virtual inheritance is achieved via the vtables.(I understand single polymorphism perfectly-well). I am having difficulties understand what exactly is done when a method needs to be located during virtual inheritance, or during casting, because there is a lot of offset calculation to be performed. Would somebody be able to help with understanding how the multiple vtables are used in a multiple or virtual inheritance example? If I could understand the layout and the problem, I could probably understand this issue

I am trying to make sense of the statement in book effective c++. Following is the inheritance diagram for multiple inheritance. Now the book says separate memory in each class is required for vptr. Also it makes following statement An oddity in the above diagram is that there are only three vptrs even though four classes are involved. Implementations are free to generate four vptrs if they like, but three suffice (it turns out that B and D can share a vptr), and most implementations take advantage of this opportunity to reduce the compiler-generated overhead. I could not see any reason why