multiple-columns

问题 I am trying to do a stock count through product stores but have several part numbers that are listed twice (Column A). When I try to consolidate these I recieve the error 'no data consolidated' which I think is caused by Columns B-F (which will always be the same if Column A value is the same). I want to consolidate the rows where columns A-F are the same, into a singular row with Column G representing the subtotal of Column F for all duplicate rows. Screenshot of Corresponding Spreadsheet I

问题 Does there exists a listbox control in ASP.NET which allows multiple columns and multiple selection? I looked but couldn't find, so what options do I have available now? 回答1: Not natively, you might need a third party library or create your own. I have used DevExpress for this purpose before. 回答2: I'm afraid you won't be able to do it with normal asp .net ListBox control. Telerik Listbox supports list item templating, which allows you to have even a whole table of data within a list box item.

问题 Does there exists a listbox control in ASP.NET which allows multiple columns and multiple selection? I looked but couldn't find, so what options do I have available now? 回答1: Not natively, you might need a third party library or create your own. I have used DevExpress for this purpose before. 回答2: I'm afraid you won't be able to do it with normal asp .net ListBox control. Telerik Listbox supports list item templating, which allows you to have even a whole table of data within a list box item.

问题 I have the following code that extracts needed data from a xml file. I can save it to terminal, and open it with no problem. I am in trouble inserting column names to the txt file, however. I have been searching the answer but found no right solution. Would anyone help me here? Thank you!! import sys reload(sys) sys.setdefaultencoding('utf-8') orig_stdout = sys.stdout sys.stdout = f for program in root.findall('program'): programID = program.find('programID') season = program.find('season')

问题 I have the following code that extracts needed data from a xml file. I can save it to terminal, and open it with no problem. I am in trouble inserting column names to the txt file, however. I have been searching the answer but found no right solution. Would anyone help me here? Thank you!! import sys reload(sys) sys.setdefaultencoding('utf-8') orig_stdout = sys.stdout sys.stdout = f for program in root.findall('program'): programID = program.find('programID') season = program.find('season')

问题 I have done a thorough search but cannot find an answer for my specific issue, using Microsoft Excel 2003. I need to copy Column R descriptions (alphanumerical) from one xls spreadsheet (let's call it ssA) to columns L & M in another spreadsheet (ssB), by svc_itm_cde (service item code). There are about 300 svc_itm_cdes. Three complications: The svc_itm_cde column in ssA is not in the same order as the one in ssB. Some of the rows of L & M in the ssB already contain descriptions and must be

问题 Introduction I have a bunch of data series with 1000 stations and each station all have 4 features (e.g Temperature, Wind, CO2 concentration, solar radiation). All the features are in time-series with hourly resolution. I read this data in .csv files with the support of Pandas. Now I need to save and organize them together for better re-use. My solution I creat columns entitled by 'sample_x, feature_y'. And each column contain the time series data of feature_y for sample_x. This method is

问题 I try to combine each columns of three different dataframes to get an object with the same length of the original dataframe and three columns of every subobject. Each of the original dataframe has 10 columns and 14 rows. I tried it with a for-loop, but the result is not usable for me. t <- NULL for(i in 1 : length(net)) { a <- cbind(imp.qua.00.09[i], exp.qua.00.09[i], net[i]) t <- list(t, a) } t But in the end I would like to get 10 seperated dataframes with three columns. So I want to loop

问题 My GridView in only single column, how can I make it multicolumn? There isn't an option to set column number in GridView properties. Update : 回答1: Because it can be difficult to get a table with 4 columns in a Repeater, here a little example. <table border="1"> <tr> <asp:Repeater ID="Repeater1" runat="server"> <ItemTemplate> <%# Container.ItemIndex %4 == 0 && Container.ItemIndex > 0 ? "</tr><tr>" : "" %> <td><%# Eval("column") %></td> </ItemTemplate> </asp:Repeater> </tr> </table> 回答2: You

问题 I have a dataframe that looks kind of like this with many more rows and columns: > df <- data.frame(country = c ("Australia","Australia","Australia","Angola","Angola","Angola","US","US","US"), year=c("1945","1946","1947"), leader = c("David", "NA", "NA", "NA","Henry","NA","Tom","NA","Chris"), natural.death = c(0,NA,NA,NA,1,NA,1,NA,0),gdp.growth.rate=c(1,4,3,5,6,1,5,7,9)) > df country year leader natural.death gdp.growth.rate 1 Australia 1945 David 0 1 2 Australia 1946 NA NA 4 3 Australia 1947