multiple-columns

问题 I have been encountering problems like this on the current bootstrap 3 for a while now. I have managed to fix them in the past in one way or another but have no clue of how to fix it this time. I need to create two columns out of one ul by alternating a pull-left & pull-right on list items. What am I doing wrong? http://bootply.com/92446 回答1: You should try using the Grid Template. Here's what I've used for a two Column Layout of a <ul> <ul class="list-group row"> <li class="list-group-item

问题 Here I have a loop containing 5 names in a <table> row. This table should be a ranking where the first column will display a row of the participant names and the other 10 columns should display the scores. For the empty columns where I want to add the score numbers, I'd like to create an array for each participant and make it loop through the <td> . Into the array there are 10 numbers where each number should display on each empty <td> left. //Names $names = array("Mike", "Kyle", "Johnny",

问题 I have a DIV container filled with a dynamic text. The length of the text can be different. The DIV container has a fixed height but no width. The Text is formatted as CSS3 Multicolumn Text width a fixed columns-width . The result is n columns with the width of column-width . Now i want to know either how many columns are there or how is the computed width of the DIV . CSS CODE: .columnize{ float: left; position: relative; width: 840px; overflow: hidden; } .columnize div{ -moz-column-width:

问题 Is it possible in pure CSS to lay out list elements to arbitrary number of columns, preserving the left-to-right order, as on this example? 回答1: Yes, it should be theoretically possible. Since you want the flex items arranged in columns, #flex-container { flex-flow: column wrap; } But then the order of the elements would be preserved vertically (in columns). Since you want horizontally, they must be reordered: #flex-container > :nth-child(4n - 2) { order: 1; } #flex-container > :nth-child(4n

问题 Given this dataframe: feature score searchTerm 0 a 0.534509 pizza 1 b 0.586020 pizza 2 c 0.588972 pizza 3 a 0.566261 chinese 4 b 0.572405 chinese 5 c 0.489369 chinese 6 a 0.499068 thai 7 b 0.431068 thai 8 c 0.441617 thai Feature is limited to ( a , b , c ) I want to pivot the dataframe into this: a b c searchTerm 0.534509 0.586020 0.588972 pizza 0.566261 0.572405 0.489369 chinese 0.499068 0.431068 0.441617 thai ... ... 回答1: You can use pivot: df1 = df.pivot(index='searchTerm', columns=

问题 I want to calculate the running sum in a given column(without using loops, of course). The caveat is that I have this other column that specifies when to reset the running sum to the value present in that row. Best explained by the following example: reset val desired_col 0 0 1 1 1 0 5 6 2 0 4 10 3 1 2 2 4 1 -1 -1 5 0 6 5 6 0 4 9 7 1 2 2 desired_col is the value I want to be calculated. 回答1: You can use 2 times cumsum() : # reset val desired_col #0 0 1 1 #1 0 5 6 #2 0 4 10 #3 1 2 2 #4 1 -1 -1

问题 I have df : df = pd.DataFrame({'a':[7,8,9], 'b':[1,3,5], 'c':[5,3,6]}) print (df) a b c 0 7 1 5 1 8 3 3 2 9 5 6 Then rename first value by this: df.columns.values[0] = 'f' All seems very nice: print (df) f b c 0 7 1 5 1 8 3 3 2 9 5 6 print (df.columns) Index(['f', 'b', 'c'], dtype='object') print (df.columns.values) ['f' 'b' 'c'] If select b it works nice: print (df['b']) 0 1 1 3 2 5 Name: b, dtype: int64 But if select a it return column f : print (df['a']) 0 7 1 8 2 9 Name: f, dtype: int64

问题 Given: A table named TABLE_1 with the following columns: ID ColumnA ColumnB ColumnC I have SQL query where TABLE_1 joins on itself twice based off of ColumnA , ColumnB , ColumnC . The query might look something like this: Select t1.ID, t2.ID, t3.ID From TABLE_1 t1 Left Join TABLE_1 t2 On t1.ColumnA = t2.ColumnA And t1.ColumnB = t2.ColumnB And t1.ColumnC = t2.ColumnC Left Join TABLE_1 t3 On t2.ColumnA = t3.ColumnA And t2.ColumnB = t3.ColumnB And t2.ColumnC = t3.ColumnC ... and query continues

问题 I would like to achieve a grid effect in CSS with elements that all have the same width in size but not in height. I would like the element underneath to be always at 50px of the bottom one, whatever is next. I tried with floats, but that bug. So I tried with Flex, but it still does not do what I want. .container display: flex flex-wrap wrap align-content flex-start align-items flex-start What I would like: What I have: 回答1: Try the new CSS Grid Layout: grid-container { display: grid; /* 1 */

问题 I am using following Query CREATE Table #MEMBER_ATTRIBUTES ( MEMBER_ID int, MEMBER_PROPERTY varchar( 500 ), MEMBER_VALUE varchar( 500 ) ) insert INTO #MEMBER_ATTRIBUTES ( MEMBER_ID ,MEMBER_PROPERTY , MEMBER_VALUE ) select isnull( MEMBER_id ,'0' ), ISNULL ( [MEMBER_PROPERTY] , '''') AS MEMBER_PROPERTY , ISNULL( [MEMBER_VALUE] ,'''' ) AS MEMBER_VALUE from MEMBER_ATTRIBUTES where MEMBER_ID in (86481 ) DECLARE @cols AS NVARCHAR( MAX ), @query AS NVARCHAR ( MAX) SELECT @cols= stuff(( SELECT ', '