Get PHP array values and print it on different columns

问题

Here I have a loop containing 5 names in a <table> row. This table should be a ranking where the first column will display a row of the participant names and the other 10 columns should display the scores.

For the empty columns where I want to add the score numbers, I'd like to create an array for each participant and make it loop through the <td>. Into the array there are 10 numbers where each number should display on each empty <td> left.

//Names
$names = array("Mike", "Kyle", "Johnny", "Will", "Vasques");

//scores values for each name
$scores = array(
    "Mike"    => array(04, 03, 00, 07, 04, 07, 00, 01, 00, 07, 04),
    "Kyle"    => array(07, 01, 00, 03, 04, 01, 00, 07, 03, 04, 04),
    "Johnny"  => array(07, 07, 00, 03, 00, 04, 00, 01, 01, 04, 03),
    "Will"    => array(03, 04, 00, 03, 04, 07, 00, 01, 00, 07, 04),
    "Vasques" => array(03, 01, 00, 03, 04, 07, 00, 01, 00, 07, 07)
);

//start loop for rows
for($x=0; $x<count($names); $x++) {
  echo "<tr>";
  //column for the names
  echo "<td>$names[$x]</td>";
  //loop for columns where the score should be displayed
  for($td=2; $td<=10; $td++) {
    echo "<td></td>";
  }
  echo "</tr>";
}

It should display something like this:

Mike   04  03  00  07  04  07  00  01  00  07  04
Kyle   07  01  00  03  04  01  00  07  03  04  04
Johnny 03  01  00  03  04  07  00  01  00  07  07

and so on...

回答1:

Try this

echo "<table>";
foreach($scores as $key=>$value)
{
     echo "<tr>";
     echo "<td>$key</td>";
     for($x=0; $x<count($value); $x++) 
     {
         echo "<td>".sprintf('%02d', $value[$x])."</td>";
     }
     echo "</tr>";
}
echo "</table>";

Example full code view

    <?php
//Names
$names = array("Mike", "Kyle", "Johnny", "Will", "Vasques");

//scores values for each name
$scores = array(
    "Mike"    => array(04, 03, 00, '-', '-', '-', '-', '-', '-', 07, 04),
    "Kyle"    => array(07, 01, 00, 03, 04, 01, 00, 07, 03, 04, 04),
    "Johnny"  => array(07, 07, 00, 03, 00, 04, 00, 01, 01, 04, 03),
    "Will"    => array(03, 04, 00, 03, 04, 07, 00, 01, 00, 07, 04),
    "Vasques" => array(03, 01, 00, 03, 04, 07, 00, 01, 00, 07, 07)
);
echo "<table>";
foreach($scores as $key=>$value)
{
     echo "<tr>";
     echo "<td>$key</td>";
     for($x=0; $x<count($value); $x++) 
     {
          if (is_numeric($value[$x])) 
     {
        echo "<td>".sprintf('%02d', $value[$x])."</td>";
     }
     else
     {
         echo "<td>". $value[$x]."</td>";
     }
     }
     echo "</tr>";
}
echo "</table>";

Output

Mike    04  03  00  -   -   -   -   -   -   07  04
Kyle    07  01  00  03  04  01  00  07  03  04  04
Johnny  07  07  00  03  00  04  00  01  01  04  03
Will    03  04  00  03  04  07  00  01  00  07  04
Vasques 03  01  00  03  04  07  00  01  00  07  07

回答2:

You don't need the $names array, you can just output it as the first level array key. Here's an example using foreach() instead of numeric for() loops for cleaner code:

foreach($scores as $name => $values) {
    echo '<tr><td>' . $name . '</td>' . PHP_EOL;
    foreach($values as $val) {
      echo '<td>' . $val . '</td>' . PHP_EOL;
    }
    echo '</tr>' . PHP_EOL;
}

回答3:

<?php
foreach($names as $names)
{
   echo "<tr>";
   echo "<td>$names</td>";
   foreach($scores[$names] as $nmscore)
   {
        echo "<td>$nmscore</td>";

   }
echo "</tr>";
}

回答4:

<?php
foreach($names as $name)
{
   echo "<tr>";
   echo "<td>$name</td>";
   foreach($scores[$name] as $nmscore)
   {
        echo "<td>$nmscore</td>";

   }
echo "</tr>";
}

?>

来源：https://stackoverflow.com/questions/24236603/get-php-array-values-and-print-it-on-different-columns

标签

php

arrays

loops

multiple-columns