multidimensional-array

问题 I have a table consisting basically of the following: myTable = {{1, 6.345}, {2, 3.678}, {3, 4.890}} and I'd like to sort the table by the decimal values. So I'd like to the output to be: {{2, 3.678}, {3, 4.890}, {1, 6.345}} If possible, I'd like to use the table.sort() function. Thankyou in advance for the help :-) 回答1: Given that your table is a sequence, you can use table.sort directly. This function accepts a comparison predicate as its second argument, which prescribes the comparison

问题 I have two arrays A and B in numpy. A holds cartesian coordinates, each row is one point in 3D space and has the shape (r, 3). B has the shape (r, n) and holds integers. What I would like to do is multiply each element of B with each row in A, so that the resulting array has the shape (r, n, 3). So for example: # r = 3 A = np.array([1,1,1, 2,2,2, 3,3,3]).reshape(3,3) # n = 2 B = np.array([10, 20, 30, 40, 50, 60]).reshape(3,2) # Result with shape (3, 2, 3): # [[[10,10,10], [20,20,20]], # [[60

问题 I have two arrays A and B in numpy. A holds cartesian coordinates, each row is one point in 3D space and has the shape (r, 3). B has the shape (r, n) and holds integers. What I would like to do is multiply each element of B with each row in A, so that the resulting array has the shape (r, n, 3). So for example: # r = 3 A = np.array([1,1,1, 2,2,2, 3,3,3]).reshape(3,3) # n = 2 B = np.array([10, 20, 30, 40, 50, 60]).reshape(3,2) # Result with shape (3, 2, 3): # [[[10,10,10], [20,20,20]], # [[60

问题 I've been perusing similar questions to mine for a couple of days but still haven't found a solution. Thanks any any help: I have two files, one containing methods for dealing with rational numbers and one that handles them in a 2 dimensional array. My problem is matrix.c doesn't recognize the fraction structure in contained in fraction.c. I believe my problem is somehow related to the way I declared my 2d array. In fraction.c: struct fraction { int integer; int num; int den; }; typedef

问题 I've got a series of measurements in a 2D array such as T mu1 mu2 mu3 a b c d e 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 2.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 3.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 1.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 2.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 3.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 2.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 2.0 1.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 2.0 2.0 0.0 0.0 0.0 0.0 0.0 0.0 1.0 2.0 3.0 0.0 0

问题 I have a Connect Four "board" which is a 6*7 2D char array populated with either spaces, X or O. The win condition is met when there are either four Xs or four Os in a row vertically, horizontally or diagonally. I've managed to get the win conditions checked successfully for vertical and horizontal, where the winning char is returned by some methods as below: private char CheckVerticalWinner(char[][] currentBoard) { // check vertical (move down one row, same column) char vWinner = ' '; for

问题 I have a Connect Four "board" which is a 6*7 2D char array populated with either spaces, X or O. The win condition is met when there are either four Xs or four Os in a row vertically, horizontally or diagonally. I've managed to get the win conditions checked successfully for vertical and horizontal, where the winning char is returned by some methods as below: private char CheckVerticalWinner(char[][] currentBoard) { // check vertical (move down one row, same column) char vWinner = ' '; for

问题 I have a dataset of a thousand 128 dimensional features in the shape of e.g. (1000,128). I want to find the sorted nearest neighbors of a 128 dimensional feature in the shape of (128,1). The distance in calculated via a Matrix Multiplication between dataset (1000,128) and feature (128,1) which would give an array of similarities in the shape of (1000,1) : DATASET (1000,128) x FEATURE (128,1) = SIMILARITIES (1000,1) This is done via: # features.shape=(1000,128) ; feature.shape=(128,1) ;

问题 I have an object like this: var myObj = { a: 1, b: 2, c: 3, d: 4 }; And i want to convert that object to a multi-dimensional array like this: var myArray = [['a', 1], ['b', 2], ['c', 3], ['d', 4]]; How could i achieve this? 回答1: You can use Object.entries function. var myObj = { a: 1, b: 2, c: 3, d: 4 }, myArray = Object.entries(myObj); console.log(JSON.stringify(myArray)); ...or Object.keys and Array#map functions. var myObj = { a: 1, b: 2, c: 3, d: 4 }, myArray = Object.keys(myObj).map(v =>

问题 I have an array that looks similar to this: Array ( [0] => Array ( [0] => Model2345 [1] => John Doe [2] => SN1234 ) [1] => Array ( [0] => Model2345 [1] => John Doe [2] => SN3456 ) [2] => Array ( [0] => Model1234 [1] => Jane Doe [2] => SN3456 ) ) I want to have a way to check for duplicate values for keys [1] (the John Doe/Jane Doe key) and [2] (the SNxxxx key) in php, but ignore duplicates for key [0]. How can this be accomplished? 回答1: Try this: $array = your_array(); $current = current(