move

问题 SEE VISUAL EXPLANATION and EDIT I'm trying to create a bash script to do a rename+move. This is the example situation: |DOCTEMP - NameOfTheFolder---------|NameOfADocument.docx FOLDER---| |DOCFINAL - OtherNameOfTheFolder---|OtherNameOfADocument.pdf | |etc. What I want to do is a script that: Part I Only if the file has docx, pdf, ppt then rename it as its folder but without DOCTEMP - / DOCFINAL - . NameOfADocument.docx => NameOfTheFolder.docx OtherNameOfADocument.pdf => OtherNameOfTheFolder

问题 I am trying to move several thousand documents from a list in one column and then move them to the folders listed in the other column, and then finally a third column with what has been moved and what hasn't (there will be errors where the file doesn't exist. I know how to do it on a file by file basis as below: How do I do it for the whole columns though? Sub Copy_One_File() FileCopy "C:\Users\Ron\SourceFolder\Test.xls", "C:\Users\Ron\DestFolder\Test.xls" End Sub Sub Move_Rename_One_File()

问题 I'm making a game like pacman and so far I am just starting with the grid. I got the grid started but I need to figure out how to move something to a different place in the grid so that when the user clicks or my ghosts move, it will display on the screen. How do I make it move? I have tried a bunch of different ways but none worked for me. import java.awt.*; import javax.swing.*; import javax.swing.border.BevelBorder; public class GUI { public static void main(String[] args) { final JFrame f

问题 In my textbook, the implementation of the vector push_back move implementation is: void push_back( Object && x ) { if( theSize == theCapacity ) reserve( 2 * theCapacity + 1 ); objects[ theSize++ ] = std::move( x ); } My understanding of std::move is that it basically static casts the item as an rvalue reference. So why on the last line did they have to use std::move( x ), when x was passed in already as an rvalue reference? 回答1: x is an rvalue reference, but the rule of thumb you must follow

问题 In my textbook, the implementation of the vector push_back move implementation is: void push_back( Object && x ) { if( theSize == theCapacity ) reserve( 2 * theCapacity + 1 ); objects[ theSize++ ] = std::move( x ); } My understanding of std::move is that it basically static casts the item as an rvalue reference. So why on the last line did they have to use std::move( x ), when x was passed in already as an rvalue reference? 回答1: x is an rvalue reference, but the rule of thumb you must follow

问题 In my textbook, the implementation of the vector push_back move implementation is: void push_back( Object && x ) { if( theSize == theCapacity ) reserve( 2 * theCapacity + 1 ); objects[ theSize++ ] = std::move( x ); } My understanding of std::move is that it basically static casts the item as an rvalue reference. So why on the last line did they have to use std::move( x ), when x was passed in already as an rvalue reference? 回答1: x is an rvalue reference, but the rule of thumb you must follow

问题 In my textbook, the implementation of the vector push_back move implementation is: void push_back( Object && x ) { if( theSize == theCapacity ) reserve( 2 * theCapacity + 1 ); objects[ theSize++ ] = std::move( x ); } My understanding of std::move is that it basically static casts the item as an rvalue reference. So why on the last line did they have to use std::move( x ), when x was passed in already as an rvalue reference? 回答1: x is an rvalue reference, but the rule of thumb you must follow

问题 So iterating over a string and using operator[] or insert to change characters can invalidate the iterator. Is that also the case for an iteration like this? std::string str = "ABCD"; for(auto&& c : str){ for(int i = 0; i < 3; ++i){ switch(c) { case 'A': c = 'B'; break; case 'B': c = 'C'; break; /*...*/ } //do something } } This code works on gcc and msvc but I don't know if I can trust it. I'm using C++14. 回答1: You are modifying existing characters of string so it is completely safe.

问题 So iterating over a string and using operator[] or insert to change characters can invalidate the iterator. Is that also the case for an iteration like this? std::string str = "ABCD"; for(auto&& c : str){ for(int i = 0; i < 3; ++i){ switch(c) { case 'A': c = 'B'; break; case 'B': c = 'C'; break; /*...*/ } //do something } } This code works on gcc and msvc but I don't know if I can trust it. I'm using C++14. 回答1: You are modifying existing characters of string so it is completely safe.

问题 So iterating over a string and using operator[] or insert to change characters can invalidate the iterator. Is that also the case for an iteration like this? std::string str = "ABCD"; for(auto&& c : str){ for(int i = 0; i < 3; ++i){ switch(c) { case 'A': c = 'B'; break; case 'B': c = 'C'; break; /*...*/ } //do something } } This code works on gcc and msvc but I don't know if I can trust it. I'm using C++14. 回答1: You are modifying existing characters of string so it is completely safe.