models

Django getting a model from another model

泄露秘密 提交于 2019-12-10 12:19:28
问题 I have two models, a Author and a Article. Each Article is needs to refer back to its Author so I can access its values in my template. What is the most efficient way of doing this? class Author(models.Model): name = models.CharField(max_length=256) picture = models.CharField(max_length=256) class Article(models.Model): title = models.CharField(max_length=256) author = #The Author model that wrote this article date = models.DateTimeField(default=datetime.now) body = models.TextField() 回答1:

Rails: Validating uniqueness across multiple models

爱⌒轻易说出口 提交于 2019-12-10 10:36:29
问题 Is there a way to validate the uniqueness of an attribute among columns in two different models. For example: I have a bike model and a car model. When I create a new bike, I want to validate that the name of the bike is unique in that there is no other bike or car with that name. I don't want to put these into one model because they have vastly different properties. I'm on rails 2.3.8 Thanks. 回答1: Rails doesn't validate across models (I don't think, anyways) automatically. You should

extjs treestore with proxy

心不动则不痛 提交于 2019-12-10 09:26:34
问题 I'm creating a MVC extjs application. I've got a treepanel with a store, which is loading the data from a php source. I get the following json-formatted response: [ { "text": "Home", "leaf": true, "dbName": "NULL", "children": [] }, { "text": "Moje Firma s.r.o.", "leaf": false, "expanded": false, "children": [ { "text": "Vydane", "leaf": true, "dbName": "demo" }, { "text": "Prijate", "leaf": true, "dbName": "demo" } ] }, { "text": "Já Živnostník", "leaf": false, "expanded": false, "children":

json传递对象字典

纵然是瞬间 提交于 2019-12-10 01:00:41
authors = Author.objects.filter(name="小非").first()if authors: print(authors.__dict__) info_dic = authors.__dict__ info_dic.pop("_state") a = json.dumps(info_dic,ensure_ascii=False) a = json.loads(a) print(a)else: print("没有找到匹配项")    {'_state': <django.db.models.base.ModelState object at 0x105466b70>, 'id': 1, 'name': '小红', 'age': 22} {'id': 1, 'name': '小红', 'age': 22} model: class Author(models.Model): name = models.CharField(max_length=30) age = models.IntegerField()] class Book(models.Model): title = models.CharField(max_length=100) price = models.IntegerField() authors = models

Laravel generate models, views and controllers from database or migration script

大憨熊 提交于 2019-12-10 00:03:05
问题 I am new to Laravel 4. I wanted to know if it is possible to generate Models , Views and Controllers from existing database? I Googled and found https://github.com/JeffreyWay/Laravel-4-Generators But it allow to generate migration script, model, views and controllers by providing resource name where as i want to reverse engineering of the same in which by command line i want to create models, views and controllers from the existing database. 回答1: php artisan generate:model dbtablename it will

docker访问宿主机文件目录

落爺英雄遲暮 提交于 2019-12-09 20:37:20
可以通过下面的命令,将宿主机的文件目录加载到docker中。 docker run -it -v /home/xxx/github/insightface/models/:/mmdnn/models mmdnn/mmdnn:cpu.small 通过-v参数,冒号前为宿主机目录,必须为绝对路径,冒号后为镜像内挂载的路径。 来源: CSDN 作者: dupei 链接: https://blog.csdn.net/dupei/article/details/103463663

Abstract base class model vs Proxy model in Django

旧街凉风 提交于 2019-12-09 19:19:43
问题 I am building a control panel that will have multiple sub-applications in Django. One of my models is an application , which will have important settings like name , description , install_path and id (so that I can associate specific settings and configuration values to this application. Right now I'm struggling with trying to figure out how to declare this particular model. Each application will do something completely different than each other application. One might manage specific CMS

dl4j 模型保存的位置几种方式

倖福魔咒の 提交于 2019-12-09 14:40:03
File f = new File(FileUtils.getTempDirectory(), "xx.zip"); System.out.println(modelPath); //C:\Users\小松\AppData\Local\Temp\xx.zip File modelPath = new File(System.getProperty("java.io.tmpdir"), "xx.zip"); System.out.println(modelPath); String rootPath = System.getProperty("user.dir"); String modelDirPath = rootPath.substring(0, rootPath.lastIndexOf(File.separatorChar)) + File.separatorChar + "out" + File.separatorChar + "models"; String modelPath = modelDirPath + File.separatorChar + "xx.json"; //D:\workspace\JavaDL\out\models\xx.json 来源: oschina 链接: https://my.oschina.net/u/3209854/blog

简易博客开发(2)----models, admin

故事扮演 提交于 2019-12-09 14:25:20
django提供了非常方便的数据模型,可以非常简易的设计时间结构,URL结构,输入框等等,django都已经有编写好的数据结构,对于我这种初级编程来说再好没有,否则我就要自己写数据约束,格式,出错等 对于一个博客系统最基本包含三个要素,“作者”, “博客”,“标签” #/myblog/myblog/blog/models.py 1 from django.db import models 2 3 # Create your models here. 4 5 class Author(models.Model): #作者信息 6 """docstring for Author""" 7 name = models.CharField(max_length=30) 8 email = models.EmailField(blank=True) 9 website = models.URLField(blank=True) 10 11 def __unicode__(self): #方便查询时返回一个名字,否则是一个实例 12 return self.name 13 14 class Tag(models.Model): #标签 15 """tag of book""" 16 tag_name = models.CharField(max_length = 30) 17 create

Nested models of the same 'class' in the Backbone.js framework?

帅比萌擦擦* 提交于 2019-12-09 13:58:00
问题 I'm new to Backbone. Is it possible to define a Model in backbone which contains a list of Models of the same type? Example: MyModel = Backbone.Model.extend({ initialize: function() { nestedMyModels:new Array(); }, addMyModel: function(aModel) { // Code here would push() aModel onto array }, render: function() { // Loop through array calling render() recursively } }); I would then have a View which started a recursive call to render(). Example: MyView = Backbone.View.extend({ render:function(