model

Force deep copy of Django FileField object (mainly new file itself)

两盒软妹~` 提交于 2020-01-05 18:36:22
问题 I have this model: class DocVersion(Commentable): name = models.CharField( 'Version', max_length=100, ) docfile = models.FileField( 'File', upload_to='content/%Y/%m/%d/%H/%M/%S', ) created = models.DateTimeField( 'Created', auto_now_add=True, ) creater = models.ForeignKey( User, ) class Document(DocumentBase): #..... blah ..... versions = models.ManyToManyField( DocVersion, ) In a function in a view, I have this function to do a deep copy of the DocVersion like so: def cp_document(transfer

Model - Foreign Key db_column Naming Issue

一曲冷凌霜 提交于 2020-01-05 15:17:31
问题 I am having an issue with the db_column parameter in Django. Lets say I have created a model in my models.py: class Stats(models.Model): fk = models.ForeignKey(Game, db_column='fk_gameId') score = models.IntegerField(default=0) and trying to make an insert to the table that is generated from the model, the sample code for the insert operation is like: dbQuery = Stats(fk_gameId = requestedGameId, score = gameInfo['score']) dbQuery.save() what happens is that the system throws the following

Can I add an additional computed property to an Ember ArrayProxy?

跟風遠走 提交于 2020-01-05 12:13:20
问题 I'm working on a legacy Ember app that has a bit of a funky setup and I'm trying to clean things up and follow conventions a bit more. One issue is that, rather than returning an array from the model hook of an index route, we're returning an object that contains an array. So, I'm wrapping the model in an ArrayProxy in setupController like this: setupController: (controller, model) -> model_proxy = Ember.ArrayProxy.create({content: model.get('item')}) controller.set('content', model_proxy)

has_one/has_many with dependent destroy but using a different name for the key

岁酱吖の 提交于 2020-01-05 11:59:13
问题 So I'm looking at someone's code which has the following (paraphrased): class user has_one :connection, :dependent => :destroy has_one :second_user, :through => :connection, :class_name => 'User' end class connection belongs_to :user belongs_to :second_user, :class => 'User' end If I have a connection object and delete the associated 'user' it can be destroyed fine. But I also want to make it so that if the User occupying the 'second_user' field is destroyed the connection is destroyed. How

How to use model events with query builder in laravel

限于喜欢 提交于 2020-01-05 07:33:27
问题 I'm using model events such as static::saving, static::saved, etc in my models' static function boot method, and that works great when users save new posts, but when I do something like this: $post::where('id', $post_id)->update(array('published'=>1)); Updating in this way does not run those model events. My current solution is to just not use this method of updating and instead do: $post = Post::find($post_id); $post->published = 1; $post->save(); But is there any way to make the model

Tags relationship in loopback 3

心已入冬 提交于 2020-01-05 05:32:09
问题 In Loopback how can I create tags? For example there are projects { id, name } and there are tags collection with the similar model Now the project needs to have multiple tags, and the same tag can be used in multiple projects. For example while creating a project, the user may type already existing tags, or new tags, and those should be added to the project. I can't find the exact relationship I need in the loopback framework. How do you do that? 回答1: TLDR CREATE TABLE ProjectTag (id AUTO

Django model for variable type of data

♀尐吖头ヾ 提交于 2020-01-05 04:10:27
问题 What I am trying to do is a database to keep track of personal records. The model is almost done, but I'm facing some dificult to store diferent types of records. There are records for time, for weight, for repetitions/laps, distance... So, there are diferent types of data: time, decimal, integer... At first I created a table (or class in django) for each type of data. A table to time, other to weight (decimal) and so on. But I am wonder if there is a better solution to keep only one table

How to use the DTO efficiently based on Scenario in C#

帅比萌擦擦* 提交于 2020-01-05 03:52:05
问题 I'm working on Employee Model, it contains all the information about the Employee For Example: public class Employee { public int EmployeeId { get; set; } public string FirstName { get; set; } public string MiddleName { get; set; } public string LastName { get; set; } public string EmailAddress { get; set; } public string HomePhone { get; set; } public string MobilePhone { get; set; } } I'm having two methods for fetching records of Employee public Employee GetEmployeeName(int id) { // The

How to specify model name in store of an extjs 4?

我是研究僧i 提交于 2020-01-05 02:44:47
问题 I am getting frustrated while working with store and model of extjs 4. I am getting Store defined with no model. You may have mistyped the model name. error even though I have specified model name inside store. Here is my code : Ext.define('iWork.store.CandidateDistribution', { extend: 'Ext.data.TreeStore', autoLoad: true, requires: 'iWork.model.Location', model: 'iWork.model.Location', proxy: { type: 'ajax', url: 'data/CandidateDistribution/CandidateCount.json', reader: { type:

Access models in other project in a Django view cause “table doesn't exist” error

南楼画角 提交于 2020-01-05 00:49:10
问题 Base project structure baseproject baseapp models.py class BaseModel(models.Model) ... Other project structure : project app views.py urls.py project.app.views.py import os os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.conf import settings from baseproject.baseapp.models import BaseModel print BaseModel.objects.count() it raised "Table 'project.baseapp_baemodel' doesn't exist" error when run from command line: "python views.py". import os os.environ['DJANGO_SETTINGS