min

问题 OK, so I'm working on a home theater system, and to display the list of TV series I have been selecting the first episode of the first season and displaying the associated information for just that episode, then you can drill down to others. That way I can keep all the movies and all the TV shows in a single table which makes the playback functions much easier. The problem is, some of the series I don't have the first episode in the database, and I want them to appear anyway, so I want to

问题 I have this situation in R: my_minimum <- min(my_data_frame[,my_column_number]) This returns the minimum value. What I want is the minimum non-zero value. I have seen a lot of more complicated situations where people want a vector of the non-zero minimum values but I simply want a single number, the lowest non-zero value that exists in my_column_number within my_data_frame For context, this is taking place within a for loop that iteratively plots some stuff for each column, and I need to get

问题 The stdint.h header at my company reads: #define INT64_MIN -9223372036854775808LL But in some code in my project, a programmer wrote: #undef INT64_MIN #define INT64_MIN (-9223372036854775807LL -1) He then uses this definition in the code. The project compiles with no warnings/errors. When I attempted to remove his definition and use the default one, I got: error: integer constant is so large that it is unsigned The two definitions appear to be equivalent. Why does one compile fine and the

问题 I am not completely green to Python, but I am interested in learning/keeping good practices while I develop my skills. I want to remove the high and low values from a list of numbers, which I know how to do, but am curious if there is a better/preferred way to do this. mylist = [1, 4, 0, 3, 2] mylist.sort() #[0, 1, 2, 3, 4] trimmed = mylist[1:-1] #[1, 2, 3] I get the desired answer, but did I get the right answer appropriately? 回答1: Here's another way to do it if you don't want to change the

问题 Thanks for your help in advance. Regards, Raj 回答1: Adding the values to MAX() values would skew the data even if it were possible. There are two hacks to do this though. Right Click > Properties > Y-Axis > set the MIN range value and MAX range values to something that would eliminate all outliers. This is really only suitable for box plots that are close in all values to each other (all percentiles) On your toolbar click Insert > Calculated Column > choose the correct data table and paste in

问题 Suppose I have a set of tuples representing URLS with "scores": {(0.75, 'http://www.foo.com'), (0.33, 'http://www.bar.com'), (0.5, 'http://www.foo.com'), (0.66, 'http://www.bar.com')} . What is a concise way for me to filter out duplicate URLS, returning only the URL with the lowest score? That is, from the example set above, I want to get the following set, where each URL appears only once, with the lowest corresponding score from the original set: {(0.5, 'http://www.foo.com'),(0.33, 'http:/

问题 I'm trying to find the minimum array indices along one dimension of a very large 2D numpy array. I'm finding that this is very slow (already tried speeding it up with bottleneck, which was only a minimal improvement). However, taking the straight minimum appears to be an order of magnitude faster: import numpy as np import time randvals = np.random.rand(3000,160000) start = time.time() minval = randvals.min(axis=0) print "Took {0:.2f} seconds to compute min".format(time.time()-start) start =

问题 I would like to obtain the n-th minimum or the n-th maximum value from numerical columns in the DataFrame in pandas. Example: df = pd.DataFrame({'a': [3.0, 2.0, 4.0, 1.0],'b': [1.0, 4.0 , 2.0, 3.0]}) a b 0 3.0 1.0 1 2.0 4.0 2 4.0 2.0 3 1.0 3.0 The third largest value in column a is 2 and the second smallest value in column b is also 2. 回答1: You can use nlargest / nsmallest - df a b 0 3.0 1.0 1 2.0 4.0 2 4.0 2.0 3 1.0 3.0 df.a.nlargest(3).iloc[-1] 2.0 Or, df.a.nlargest(3).iloc[[-1]] 1 2.0 Name

问题 I have the following SQL: select code, distance from places; The output is below: CODE DISTANCE LOCATION 106 386.895834130068 New York, NY 80 2116.6747774121 Washington, DC 80 2117.61925131453 Alexandria, VA 106 2563.46708627407 Charlotte, NC I want to be able to just get a single code and the closest distance. So I want it to return this: CODE DISTANCE LOCATION 106 386.895834130068 New York, NY 80 2116.6747774121 Washington, DC I originally had something like this: SELECT code, min(distance)

问题 Is there a method to swap the maximum and the minimum of a list? The list will be as follows and the program has to be continued so that it will print the maximum swapped with the minimum, the second maximum swapped with the second minimum and third maximum swapped with the third minimum. Eg. Enter input- 0 1 2 3 4 5 6 7 8 9 -1 Output- 9873456210 a = [] nums = raw_input("Enter input- ") for n in nums.split(): n = int(n) if n < 0: break a.append(n) if len(a)<7: print "please enter more than 7