min

问题 How do i get the maximum or minimum of two values in Less. Just like Math.min() or Math.max() in javascript. I think this will be useful to use in your mixins. 回答1: This feature has been implemented in the meantime. Have a look at the official Function Reference: min() max() 回答2: Less min/max builtin functions are planned for future releases, see: https://github.com/less/less.js/pull/1371. For now you could try, based on https://stackoverflow.com/a/15982103/1596547: .max(@a,@b) { @max: ~"@{b

问题 I have this code wrote in python 3: matrix = [] loop = True while loop: line = input() if not line: loop = False values = line.split() row = [int(value) for value in values] matrix.append(row) print('\n'.join([' '.join(map(str, row)) for row in matrix])) print('matrix saved') an example of returned matrix would be [[1,2,4],[8,9,0]].Im wondering of how I could find the maximum and minimum value of a matrix? I tried the max(matrix) and min(matrix) built-in function of python but it doesnt work.

问题 I have created a subquery as follows select hospital.hospitalcode, name, wardno, annualbudget from hospital, ward where hospital.hospitalcode = ward.hospitalcode The question I am trying to answer is this: Taking account of all hospital wards, which hospital has the ward with the lowest annual budget? You should display the hospital code and its name, the ward number and its annual budget. How would I find a single entry for this question? I realise I need to use MIN but do not know where to

问题 I am currently working with a matrix and I want to find the lowest positive value in each row. Using apply(my.matrix,1,min) won't work since the output will always be 0... Is there a way to find the lowest value excluding 0? 回答1: You can do this with an anonymous function. apply(my.matrix, 1, FUN = function(x) {min(x[x > 0])}) 回答2: This variation on your approach works for me: apply(my.matrix, 1, FUN=function(x) {min(x>0)}) 来源： https://stackoverflow.com/questions/10717831/find-minimum

问题 I have this structure of table Diary: CREATE TABLE Diary ( [IdDiary] bigint, [IdDay] numeric(18,0) ); INSERT INTO Diary ([IdDiary], [IdDay]) values (51, 1), (52, 2), (53, 5); And this other structure for table DiaryTimetable: CREATE TABLE DiaryTimetable ( [IdDiary] bigint, [Hour] varchar(50) ); INSERT INTO DiaryTimetable ([IdDiary], [Hour]) VALUES (51, '09:00'), (51, '09:30'), (51, '10:00'), (51, '10:30'), (51, '11:00'), (51, '11:30'), (52, '11:00'), (52, '11:30'), (52, '12:00'), (52, '12:30'

问题 I would like to calculate the maximum value of the minimum values of each row in a spreadsheet (Google Sheets, specifically) that is greater than 0. I hope that makes sense. My data is: 0 6 7 8 1 0 12 21 22 21 0 10 18 24 0 7 9 1 17 0 16 16 20 So, I want an ArrayFormula of some sort that will generate: 1 12 10 1 16 Of which I could then get the maximum. I've read and experienced that the obvious solution doesn't work, which is: =max(ArrayFormula(min(if(A:Z>0,A:Z,""))) The reason being the

问题 I have a dataframe of which I put one variable into a vector. From this vector, I would like to calculate for every 5 values mean , min and max value. I have managed to calculate the means in this way: means <- colMeans(matrix(df$values, nrow=5)) I know I can calculate the min and max like this: max <- max(df$values[1:5]) min <- min(df$values[1:5]) How do I repeat this for every five values? Edit: Aditionally, how can I get statistic and p-value from a 1-sample t-test for each n-row? 回答1: You

问题 I have the following query: SELECT contact_purl, contact_firstName, contact_lastName, MIN( contact_id ) AS MinID FROM contacts WHERE contact_client_id = 1 GROUP BY contact_purl HAVING COUNT( contact_id ) > 1 The purpose is to find any contacts with a duplicate "contact_purl," and return the first entry. I'm running into a very strange problem... If the table has less than 8,000 rows, the query will render in less than 1 second. HOWEVER, if the table has more than 8,000 rows, the query will

问题 i have in my DB 3 col and i want to find a single value among all of them as explaind here: table name:MyTable ----------------------------- --id-- col1-- col2-- col3- ----------------------------- 1 200 300 400 2 100 150 300 3 800 102 20 4 80 80 0 i want the result out of col1 col2 col3 to be = 0 , which is the min value among them. is it possible !!!! my try: select Min(col1, col2 , col3) as Tablemin from MyTable 回答1: ANSI SQL: select min(col) from ( select col1 [col] from MyTable union all

问题 This is a part of a book I'm reading to learn Objective-C. The following defines a macro called MAX that gives the maximum of two values: #define MAX(a,b) ( ((a) > (b)) ? (a) : (b) ) And then there are some exercises in the book that asks the reader to define a macro ( MIN ) to find the minimum of two values and another that asks to define a macro called MAX3 that gives the maximum of 3 values. I think these two definitions will look similar to MAX , but I don't understand how the MAX formula