min

How can I make Excel's MIN function ignore zeroes in a set?

回眸只為那壹抹淺笑 提交于 2019-12-12 11:16:18
问题 In Excel, I have the following formula =(MIN(H69,H52,H35,H18)*(1/H18))*10 that is supposed to return the MIN of a range, and divide it by the current cell (*(1/H18) ), then multiply by 10. I am having difficulty with adding a type of NULLIF statement. I want to be able to have (the possibility for) blank rows, and have the MIN function ignore zero/blank fields while selecting the next lowest value (all are between 1.0-0.1). Is there a modifier i can apply to the MIN function to make it not

Finding a minimum and maximum value in an array

南楼画角 提交于 2019-12-12 06:39:14
问题 So I'm trying to find a min and max of an array which are put in by the user. This is my code public static void main(String[] args) { int[] a = new int[args.length]; for (int i = 0; i < args.length; i++) { a[i] = Integer.parseInt(args[i]); int max = a[0]; for (int j = 1; j < args.length; j++) { if (a[j] > max) { max = a[j]; } } System.out.println("the maximum value of the array is " + max); } } But the output I am getting is every single number I have put in. What is my mistake here? 回答1:

Iteration of matrix-vector multiplication which stores specific index-positions

一笑奈何 提交于 2019-12-12 06:27:08
问题 I need to solve a min distance problem, to see some of the work which has being tried take a look at: link: click here I have four elements : two column vectors : alpha of dim (px1) and beta of dim (qx1) . In this case p = q = 50 giving two column vectors of dim (50x1) each. They are defined as follows: alpha = alpha = 0:0.05:2; beta = beta = 0:0.05:2; and I have two matrices : L1 and L2 . L1 is composed of three column-vectors of dimension (kx1) each. L2 is composed of three column-vectors

Find min value of member, MDX

陌路散爱 提交于 2019-12-12 04:19:06
问题 Just started to explore MDX. Can anyone help me to get below result. Looking to build a MDX query which gives same out as below SQL query select max(date),min(date) from Fiscal_calendar Where : 1. Fiscal_Calendar is dimension in cube 2. date is the attribute 回答1: Min Date will be the First Child of the [All] member while Max Date will be the Last Child. SELECT {Fiscal_Calendar.Date.[All].FirstChild, Fiscal_Calendar.Date.[All].LastChild} ON 1, {} ON 0 FROM [YourCube] Second last child: Fiscal

ORACLE SELECT GROUP BY + something that I don't know

别来无恙 提交于 2019-12-12 03:35:26
问题 I have a table in the ORACLE database, details below: -------------------------------------------- | FRUITS | -------------------------------------------- | FRUIT_NAME | GROWTH_TIME | GROWTH_PLACE | -------------------------------------------- | melon | 0600 | shelf1 | | melon | 0630 | shelf1 | | melon | 0700 | shelf1 | | melon | 0730 | shelf1 | | melon | 0800 | shelf1 | | orange | 0600 | shelf5 | | orange | 0630 | shelf5 | | orange | 0700 | shelf5 | | orange | 0730 | shelf5 | | orange | 0800

how to get min or max date on columns in mdx query

﹥>﹥吖頭↗ 提交于 2019-12-12 03:32:28
问题 what mdx query logic could i implement for this example to get two rows in result set for hrid = 1 with 1/1/16 as min date(start) for first row where someattribut shows up on column with value 'A' and 1/15/16 as min date(start) for second row where someattribute has value of 'B' and measure.whatevers has its aggregation for whatever data corresponds to that dimension row. Im trying to just look at january 2016 everything ive tried i seem to get min date values of 1/1/1900 or both rows have

ZoomRange Highstock works not correct?

倖福魔咒の 提交于 2019-12-12 02:38:04
问题 I made a Highstock diagramm and got aproblem with zooming on the yAxis. I have a Button and 2 textfield to get the wanted min/max values for the axis. With min:0, max: 100 it works well. With min:0, max:80 it doesn't (max will still be 100 in the Diagramm). If I use the mouse for zooming it works well (even a min of: 3.7 and a max of 3.894 is possible). But using the mouse is not an Option, because in the later Diagramm there will be 3 yAxes with individual zoom. $(function () { var

Qlikview: tablebox or straight/pivot which would show minimum value and related value of the min value

冷暖自知 提交于 2019-12-12 02:31:42
问题 This is driving me nuts. Say I have a mass of lists with product names, their prices and the origins of the pricing: Product, 1$, USA Product, 2€, EU Product, 0.5€, HK What is the correct table configuration to get this result, without duplicating the record of the same product name?: Product 0.5€ HK That is to say the table calculates the minimum price and shows the correct origin for the minimum price? I either get all expanded pivot dupe products or the product origin is returned bogus.

SQL Update Table Where date = MIN(date)

放肆的年华 提交于 2019-12-12 02:19:30
问题 I got the following code: Update `Table` set amount='1003' WHERE date = (SELECT MIN(date)) AND `id` = 736 Something is wrong with my first Where rule date = (SELECT MIN(date)) but i dont know what. 回答1: You can update it from a join: Update `Table` a INNER JOIN ( SELECT `id`, min(exp_date) AS exp_date from `Table` WHERE `id`= 736 ) AS b ON (a.id=b.id AND a.exp_date=b.exp_date) set amount='1003' WHERE a.id = 736 AND a.exp_date=b.exp_date; 来源: https://stackoverflow.com/questions/40171682/sql

Find lowest date in each group [duplicate]

匆匆过客 提交于 2019-12-12 02:19:15
问题 This question already has answers here : Subset data based on Minimum Value (2 answers) Closed 3 years ago . Hi there: I'm trying to find the lowest date in each group. The purpose is to find what date is common to each of several time series. Currently the data look like this. library(tidyr) library(dplyr) grouping_variable<-sample(c('a', 'b', 'c'), 500, replace=TRUE) date<-sample(seq(as.Date('1999/01/01'), as.Date('2015/01/01'), by="day"), 500) numeric_variable<-rnorm(500, 50, sd=2) df<