max

问题 I've multiple values with different timestamps like the following: 10 01:01:00 20 01:35:00 30 02:10:00 05 02:45:00 12 03:05:00 21 03:30:00 10 04:06:00 40 05:15:00 I don't have a column with which I can group by and find max. I want to get the records with max values like 30,21, and 40. The data is always in this format, like value increasing and then starts from zero again. What query will help me to find these records? To clarify, it's sorted by the timestamp, and I want to get the

问题 I've multiple values with different timestamps like the following: 10 01:01:00 20 01:35:00 30 02:10:00 05 02:45:00 12 03:05:00 21 03:30:00 10 04:06:00 40 05:15:00 I don't have a column with which I can group by and find max. I want to get the records with max values like 30,21, and 40. The data is always in this format, like value increasing and then starts from zero again. What query will help me to find these records? To clarify, it's sorted by the timestamp, and I want to get the

问题 I am building a program that selects max elements from a list which sums to a given input value load_data = [1, 2, 3, 4, 10, 20] eg user inputs 30 select 20 and 10 or user inputs 35 select 20, 10, 4 and 1 since they are the possible largest elements that sum up to 30 or 35 code def process(m): print m def selection(): aux = range(len(load_data)) global value # <- value is the input while aux and value > 0: posit = max(aux) >= value index = aux[posit] elem = load_data[index] value = value -

问题 I have 2 lists with elements like: list1=[2,54,31,6,42] list2=[4,98,43,3,2] I want a def that compares the numbers and returns a 3rd list with the biggest one. In this example the 3rd list would be: list3=[4,98,43,6,42] 回答1: Here's a simple def /function to zip() the two lists and then get max() and store it into a new list3 and returned: list1=[2,54,31,6,42] list2=[4,98,43,3,2] def function(list1,list2): #def returns 3rd list list3 = [max(value) for value in zip(list1, list2)] return list3

问题 Here is a code for removing only one of the max values (in this case the first one, but this is irrelevant) from the list. It is O(n) in time and O(n) in space (beyond the input). public List<Integer> removeOneOfTheMax(List<Integer> nums) { int max = Integer.MIN_VALUE; int maxIndex = -1; Iterator<Integer> it = nums.iterator(); for (int i = 0; it.hasNext(); i++) { Integer temp = it.next(); if (max < temp) { maxIndex = i; max = temp; } } nums.remove(maxIndex); return nums; } 1. What would be

问题 Can anyone please explain why the following will compile int a = aAssignments[i]->Count; int b = fInstanceData->NumRequiredEmpsPerJob[i]; fInstanceData->NumSlotsPerJob[i] = max(a,b); but fInstanceData->NumSlotsPerJob[i] = max((int)(aAssignments[i]->Count), (int)(fInstanceData->NumRequiredEmpsPerJob[i])); //why on earth does this not work? wont? The error it gives is error C2665: 'std::max' : none of the 7 overloads could convert all the argument types The variable aAssigmments is of type

问题 I'm trying to find out how to write an SQL sentence in LINQ but I can't find a way to do it for the moment, this is the SQL command: SELECT cs.Site_Name, MAX(ed.EffectiveDate_Date) FROM [WAPMaster].[Factsheets].[EffectiveDate] ed, [WAPMaster].[Configuration].[Site] cs WHERE cs.Site_Id = ed.EffectiveDate_SiteId GROUP BY cs.Site_Name Can someone help me witht he linq syntax please? **I'm trying this so far (thanks levanlevi) var test = (from e in this._wapDatabase.EffectiveDates join c in this.

问题 i'm using codeigniter 2. i've a mysql table column storing the time taken for each student. eg. 1.2327, 0.6547, 1.9876 i want to get the max. value that column. This is my code: $this->db->select_max('time_taken', 'time'); $result = $this->db->get('students'); echo $result->row()->time; when i echo the result, it give me a value of 2(correct value should be 1.9876). What is the correct way to get this value i need, thanks? 回答1: Try: $this->db->select_max('time_taken AS time'); $result = $this

问题 I have a data.frame with columns of factors, on which I want to compute a max (or min, or quantiles). I can't use these functions on factors, but I want to. Here's some example : set.seed(3) df1 <- data.frame(id = rep(1:5,each=2),height=sample(c("low","medium","high"),size = 10,replace=TRUE)) df1$height <- factor(df1$height,c("low","medium","high")) df1$height_num <- as.numeric(df1$height) # > df1 # id height height_num # 1 1 low 1 # 2 1 high 3 # 3 2 medium 2 # 4 2 low 1 # 5 3 medium 2 # 6 3

问题 I want to determine the maximum size of the stack programmatically from within Java (the size set by -Xss). How do I do this? Alternatively, as my Java module also uses a native code module, I would be able to do this via JNI; but how? 回答1: Use ManagementFactory.getRuntimeMXBean().getInputArguments() to access all arguments passed to VM. 回答2: Maybe not best practice but certainly straight-forward: I'd write a recursive method counting up a value, recurring until java.lang.StackOverflowError