max

Get the maximum value from an element in a multidimensional array?

Deadly 提交于 2020-01-08 17:42:08
问题 I'm trying to select the maximum value for a particular key in a multidimensional array. I'm having trouble "getting to" the key in question... So, the array (which is much more lengthy than what I'm posting here) [0] => stdClass Object ( [id] => 70 [cust] => 4 [dnum] => 1 [upper] => Array ( [0] => 66 ) ) [1] => stdClass Object ( [id] => 43 [cust] => 42 [dnum] => 2 [upper] => Array ( [0] => 77 ) ) [2] => stdClass Object ( [id] => 12 [cust] => 3 [dnum] => 0 [upper] => Array ( [0] => 99 ) ) I'm

Minimum and maximum date

一个人想着一个人 提交于 2020-01-08 11:27:49
问题 I was wondering which is the minimum and the maximum date allowed for a Javascript Date object. I found that the minimum date is something like 200000 B.C., but I couldn't get any reference about it. Does anyone know the answer? I just hope that it doesn't depend on the browser. An answer in "epoch time" (= milliseconds from 1970-01-01 00:00:00 UTC+00) would be the best. 回答1: From the spec, §15.9.1.1: A Date object contains a Number indicating a particular instant in time to within a

Minimum and maximum date

三世轮回 提交于 2020-01-08 11:25:31
问题 I was wondering which is the minimum and the maximum date allowed for a Javascript Date object. I found that the minimum date is something like 200000 B.C., but I couldn't get any reference about it. Does anyone know the answer? I just hope that it doesn't depend on the browser. An answer in "epoch time" (= milliseconds from 1970-01-01 00:00:00 UTC+00) would be the best. 回答1: From the spec, §15.9.1.1: A Date object contains a Number indicating a particular instant in time to within a

Aggregating hourly data into daily aggregates with missing value in R

╄→尐↘猪︶ㄣ 提交于 2020-01-07 07:47:09
问题 [enter image description here][1][enter image description here][2]I have a data frame "RH", with hourly data and I want to convert it to daily maximum and minimum data. This code was very useful [question]:Aggregating hourly data into daily aggregates RH$Date <- strptime(RH$Date,format="%y/%m/%d) RH$day <- trunc(RH$Date,"day") require(plyr) x <- ddply(RH,.(Date), summarize, aveRH=mean(RH), maxRH=max(RH), minRH=min(RH) ) But my first 5 years data are 3 hours data not hourly. so no results for

Python: how key is passed into the function with default value of None [closed]

一个人想着一个人 提交于 2020-01-07 04:21:25
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . I'm confused in this code, the allmax passes hand_rank function as the key, but in the definition of allmax, it sets the key to be None, then how the hand_rank passed to this allmax function? def poker(hands): "Return a list of winning hands: poker([hand,...]) => [hand,...]" return allmax(hands, key=hand_rank)

MongoDB: min(), max() doesn't support embedded document

我怕爱的太早我们不能终老 提交于 2020-01-06 15:01:51
问题 I have applied index on embedded document field which is of type date. Due to unpredictable behavior of MongoDB query with $lt & $gt operators I am trying to use min() max() functions of Cursor which force both lower & upper bounds on the index. But when I used it, it gave me error: planner returned error: unable to find relevant index for max/min query" Query looks like: db.user.find().min({'record.date':ISODate("2014-12-01")}).max({'record.date':ISODate("2014-12-01")}).explain() I have

MongoDB: min(), max() doesn't support embedded document

僤鯓⒐⒋嵵緔 提交于 2020-01-06 14:59:11
问题 I have applied index on embedded document field which is of type date. Due to unpredictable behavior of MongoDB query with $lt & $gt operators I am trying to use min() max() functions of Cursor which force both lower & upper bounds on the index. But when I used it, it gave me error: planner returned error: unable to find relevant index for max/min query" Query looks like: db.user.find().min({'record.date':ISODate("2014-12-01")}).max({'record.date':ISODate("2014-12-01")}).explain() I have

Maximum and Minimum values from a summed Formula in Crystal Reports 2008

守給你的承諾、 提交于 2020-01-06 13:30:51
问题 Maximum and Minimum values from a summed Formula problem Hello, I am currently using Crystal Reports 2008 which is getting its data from an Oracle database. I have looked into this at length and I have been unable to find the information I need. I have query about getting the Maximum and Minimum values from a given formula which totals 2 or more fields. A snapshot of the information I am using is: Field1 = dB1.Left_Serious Field2 = dB1.Left_Dangerous Field3 = @Tester Formula = @LeftTot Fields

Maximum and Minimum values from a summed Formula in Crystal Reports 2008

倾然丶 夕夏残阳落幕 提交于 2020-01-06 13:29:16
问题 Maximum and Minimum values from a summed Formula problem Hello, I am currently using Crystal Reports 2008 which is getting its data from an Oracle database. I have looked into this at length and I have been unable to find the information I need. I have query about getting the Maximum and Minimum values from a given formula which totals 2 or more fields. A snapshot of the information I am using is: Field1 = dB1.Left_Serious Field2 = dB1.Left_Dangerous Field3 = @Tester Formula = @LeftTot Fields

How to get maximum Id in List and then return list

好久不见. 提交于 2020-01-06 07:44:35
问题 I have a structure like this: No ID Name Status 1 1 A 1 2 1 B 1 3 1 c 1 4 1 D 1 5 2 E 3 6 2 F 3 7 2 G 3 I want to run a linq when I get a list results get maximum row where for each status and row details as well.Like: No ID Name Status 4 1 D 1 7 2 G 3 Means latest entry for the status. Is there a way around, as I have tried all Max, Orderby descending but I get single result but I need a List as a result. 回答1: You have to extract the groups of a same id (GroupBy), and then export the max No