max

Find row with maximum value of id in MySQL

自闭症网瘾萝莉.ら 提交于 2020-01-13 10:53:51
问题 Take a look at the MySQL table below called "Articles": +----+-----------+---------+------------------------+--------------------------+ | id | articleId | version | title | content | +----+-----------+---------+------------------------+--------------------------+ | 1 | 1 | 0.0 | ArticleNo.1 title v0.0 | ArticleNo.1 content v0.0 | | 2 | 1 | 1.0 | ArticleNo.1 title v1.0 | ArticleNo.1 content v1.0 | | 3 | 1 | 1.5 | ArticleNo.1 title v1.5 | ArticleNo.1 content v1.5 | | 4 | 1 | 2.0 | ArticleNo.1

Find row with maximum value of id in MySQL

别等时光非礼了梦想. 提交于 2020-01-13 10:53:31
问题 Take a look at the MySQL table below called "Articles": +----+-----------+---------+------------------------+--------------------------+ | id | articleId | version | title | content | +----+-----------+---------+------------------------+--------------------------+ | 1 | 1 | 0.0 | ArticleNo.1 title v0.0 | ArticleNo.1 content v0.0 | | 2 | 1 | 1.0 | ArticleNo.1 title v1.0 | ArticleNo.1 content v1.0 | | 3 | 1 | 1.5 | ArticleNo.1 title v1.5 | ArticleNo.1 content v1.5 | | 4 | 1 | 2.0 | ArticleNo.1

Max value per diagonal in 2d array

点点圈 提交于 2020-01-13 09:15:13
问题 I have array and need max of rolling difference with dynamic window. a = np.array([8, 18, 5,15,12]) print (a) [ 8 18 5 15 12] So first I create difference by itself: b = a - a[:, None] print (b) [[ 0 10 -3 7 4] [-10 0 -13 -3 -6] [ 3 13 0 10 7] [ -7 3 -10 0 -3] [ -4 6 -7 3 0]] Then replace upper triangle matrix to 0: c = np.tril(b) print (c) [[ 0 0 0 0 0] [-10 0 0 0 0] [ 3 13 0 0 0] [ -7 3 -10 0 0] [ -4 6 -7 3 0]] Last need max values per diagonal, so it means: max([0,0,0,0,0]) = 0 max([-10,13

Max value per diagonal in 2d array

血红的双手。 提交于 2020-01-13 09:15:11
问题 I have array and need max of rolling difference with dynamic window. a = np.array([8, 18, 5,15,12]) print (a) [ 8 18 5 15 12] So first I create difference by itself: b = a - a[:, None] print (b) [[ 0 10 -3 7 4] [-10 0 -13 -3 -6] [ 3 13 0 10 7] [ -7 3 -10 0 -3] [ -4 6 -7 3 0]] Then replace upper triangle matrix to 0: c = np.tril(b) print (c) [[ 0 0 0 0 0] [-10 0 0 0 0] [ 3 13 0 0 0] [ -7 3 -10 0 0] [ -4 6 -7 3 0]] Last need max values per diagonal, so it means: max([0,0,0,0,0]) = 0 max([-10,13

How to find max values from multiple lists?

孤街浪徒 提交于 2020-01-13 06:06:12
问题 I have multiple lists (or numpy arrays) of the same size and I want to return an array of the same size with the max value at each point. For example, A = [[0,1,0,0,3,0],[1,0,0,2,0,3]] B = [[1,0,0,0,0,4],[0,5,6,0,1,1]] C = numpy.zeros_like(A) for i in xrange(len(A)): for j in xrange(len(A[0])): C[i][j] = max(A[i][j],B[i][j]) The result is C = [[1,1,0,0,3,4],[1,5,6,2,1,3]] This works fine, but is not very efficient - especially for the size of arrays that I have and the number of arrays I need

How to find max values from multiple lists?

◇◆丶佛笑我妖孽 提交于 2020-01-13 06:05:14
问题 I have multiple lists (or numpy arrays) of the same size and I want to return an array of the same size with the max value at each point. For example, A = [[0,1,0,0,3,0],[1,0,0,2,0,3]] B = [[1,0,0,0,0,4],[0,5,6,0,1,1]] C = numpy.zeros_like(A) for i in xrange(len(A)): for j in xrange(len(A[0])): C[i][j] = max(A[i][j],B[i][j]) The result is C = [[1,1,0,0,3,4],[1,5,6,2,1,3]] This works fine, but is not very efficient - especially for the size of arrays that I have and the number of arrays I need

android edittext minmum and maximum value

我们两清 提交于 2020-01-13 03:15:30
问题 I am in development of an android app.. actually i need to set a minimum and maximum value for an editext entry my minimum value is 18 and maximum is 65.I did the exact code of this package com.test; import android.text.InputFilter; import android.text.Spanned; public class InputFilterMinMax implements InputFilter { private int min, max; public InputFilterMinMax(int min, int max) { this.min = min; this.max = max; } public InputFilterMinMax(String min, String max) { this.min = Integer.parseInt

MySQL selecting max record in group by

自作多情 提交于 2020-01-12 04:53:08
问题 I am trying to create a query in a table that has some 500,000 records and some 50 or 60 columns. What I need is to collate these records into groups and select the max record in each group. To simplify the problem I have a table as follows +----+-------------+----------+--------+ | id | external_id | group_id | mypath | +----+-------------+----------+--------+ | 1 | 1003 | 1 | a | | 2 | 1004 | 2 | b | | 3 | 1005 | 2 | c | +----+-------------+----------+--------+ The simple group by is as

How can I hide a meta tag from the devices with max width:1024px?

隐身守侯 提交于 2020-01-11 13:22:10
问题 I tried the below, but it didnt work. Can you help me please? <div class="viewport-setting"><meta name="viewport" content="maximum-scale=0.80"></div> <style>@media (min-width: 0px) and (max-width: 1024px) {.viewport-setting {display:none !important;}}</style> 来源: https://stackoverflow.com/questions/43764920/how-can-i-hide-a-meta-tag-from-the-devices-with-max-width1024px

How can I hide a meta tag from the devices with max width:1024px?

天涯浪子 提交于 2020-01-11 13:22:08
问题 I tried the below, but it didnt work. Can you help me please? <div class="viewport-setting"><meta name="viewport" content="maximum-scale=0.80"></div> <style>@media (min-width: 0px) and (max-width: 1024px) {.viewport-setting {display:none !important;}}</style> 来源: https://stackoverflow.com/questions/43764920/how-can-i-hide-a-meta-tag-from-the-devices-with-max-width1024px