math

Java: Is there a tool available that can allow me input, store, and evaluate math formulas?

流过昼夜 提交于 2020-02-20 06:10:10
问题 Even something very rudimentary is fine. Like entering and evaluating something like x+1, where x is a variable I get to specify. I was thinking of writing my own using Strings for each formula, regex for parsing them, etc., but let's assume my goal is to be as lazy as I can possibly get away with, and that if there's another option (especially a formal one), I'd rather try to use that instead, first. Is there anything out there that does something like this? 回答1: You can think about using

Java: Is there a tool available that can allow me input, store, and evaluate math formulas?

北城余情 提交于 2020-02-20 06:05:40
问题 Even something very rudimentary is fine. Like entering and evaluating something like x+1, where x is a variable I get to specify. I was thinking of writing my own using Strings for each formula, regex for parsing them, etc., but let's assume my goal is to be as lazy as I can possibly get away with, and that if there's another option (especially a formal one), I'd rather try to use that instead, first. Is there anything out there that does something like this? 回答1: You can think about using

Java: Is there a tool available that can allow me input, store, and evaluate math formulas?

感情迁移 提交于 2020-02-20 06:04:38
问题 Even something very rudimentary is fine. Like entering and evaluating something like x+1, where x is a variable I get to specify. I was thinking of writing my own using Strings for each formula, regex for parsing them, etc., but let's assume my goal is to be as lazy as I can possibly get away with, and that if there's another option (especially a formal one), I'd rather try to use that instead, first. Is there anything out there that does something like this? 回答1: You can think about using

Subtracting two timestamps in bash script

China☆狼群 提交于 2020-02-14 03:11:20
问题 I have a file that contains a set of Timestamps in format of H:M:S.MS , I can read and print all of the saved Timestamps but when I do some arithmetic operation like Subtract (say Timestamp2 - Timestamp1 ) it doesn't give me the answer, I do not have experience work with bash script programming. Any suggestions, recommendations will be much appreciated. Here is the screen shot of my problem. Here is an example : Start Time = 17:53:01.166721 End Time = 17:53:01.369787 The expected result for

Subtracting two timestamps in bash script

核能气质少年 提交于 2020-02-14 03:08:57
问题 I have a file that contains a set of Timestamps in format of H:M:S.MS , I can read and print all of the saved Timestamps but when I do some arithmetic operation like Subtract (say Timestamp2 - Timestamp1 ) it doesn't give me the answer, I do not have experience work with bash script programming. Any suggestions, recommendations will be much appreciated. Here is the screen shot of my problem. Here is an example : Start Time = 17:53:01.166721 End Time = 17:53:01.369787 The expected result for

How to find repeating sequence of Integers in an array of Integers?

一世执手 提交于 2020-02-14 02:27:10
问题 How to find repeating sequence of Integers in an array of Integers? 00 would be repeating, so would 123123, but 01234593623 would not be. I have an idea to how to do this, but it is blurry in my mind, and my implementation doesn't go far due to this. My idea was Offset by a certain amount each time going through a for loop Loop through inside of that and compare chunks of numbers by that offset In Java, I got this far: String[] p1 = new String[nDigitGroup]; String[] p2 = new String

Round number to nearest .5 decimal

守給你的承諾、 提交于 2020-02-13 05:51:05
问题 I'm looking for an output of 4.658227848101266 = 4.5 4.052117263843648 = 4.0 the closest I've gotten is rating = (Math.round(rating * 4) / 4).toFixed(1) but with this the number 4.658227848101266 = 4.8??? 回答1: (Math.round(rating * 2) / 2).toFixed(1) 回答2: It's rather simple, you should multiply that number by 2, then round it and then divide it by 2: var roundHalf = function(n) { return (Math.round(n*2)/2).toFixed(1); }; 回答3: This works for me! (Using the closest possible format to yours)

Calculate coordinates for 45 degree snap

假装没事ソ 提交于 2020-02-07 16:33:42
问题 I have a SVG that draws a line between an origin point and the mouse pointer, what i'd like to do is when shift is depressed (event.shiftKey === true) make the line "snap" to the nearest 45 degree coordinate, the same behaviour you get in photoshop basically. I've managed to work out the angle in degrees between the two points (so i can decide which angle to snap too, probably using an IF/ELSE tree if needs be) however I don't know how i re-calculate the "end" coordinates based on the new

Calculate coordinates for 45 degree snap

放肆的年华 提交于 2020-02-07 16:33:32
问题 I have a SVG that draws a line between an origin point and the mouse pointer, what i'd like to do is when shift is depressed (event.shiftKey === true) make the line "snap" to the nearest 45 degree coordinate, the same behaviour you get in photoshop basically. I've managed to work out the angle in degrees between the two points (so i can decide which angle to snap too, probably using an IF/ELSE tree if needs be) however I don't know how i re-calculate the "end" coordinates based on the new

Calculate coordinates for 45 degree snap

隐身守侯 提交于 2020-02-07 16:32:23
问题 I have a SVG that draws a line between an origin point and the mouse pointer, what i'd like to do is when shift is depressed (event.shiftKey === true) make the line "snap" to the nearest 45 degree coordinate, the same behaviour you get in photoshop basically. I've managed to work out the angle in degrees between the two points (so i can decide which angle to snap too, probably using an IF/ELSE tree if needs be) however I don't know how i re-calculate the "end" coordinates based on the new