match

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 1 year ago . Improve this question i want to use rust match in python3, instead of if...elif statement. https://doc.rust-lang.org/rust-by-example/flow_control/match.html fn main() { let number = 13; // TODO ^ Try different values for `number` println!("Tell me about {}", number); match number { //

问题 I'm new to Excel VBA and am trying to write a function that lets me use INDEX , MATCH and COUNTIFS functions to find value for a given column by matching criteria in other columns (multiple). I have a table named Price which contains some prices offered in different locations based on an assigned category: Area Category Cost Retail Price Wholesale Price USA Bad 1 13 25 Canada Okay 2 14 26 Mexico Good 3 15 27 USA Excellent 4 16 28 Canada Bad 5 17 29 Mexico Okay 6 18 30 USA Good 7 19 31 Canada

问题 I want to return the corresponding matched keyword that is contained in Column A, but I dont know the Excel query to be used. Please can you help? The details are as follows: Column A - List of Firms I need to match the Keywords Against (Column C) Column B - If the list of Keywords match the cell in Column A return the Matching value here Column C - Match these keywords to text in Column A, I am looking for a contains match rather than a Exact Match Here is the file in question: https://www

问题 I'd like to remove all the lines of a file based on matching a string from another file. This is what I have used but it only deletes some: grep -vFf to_delete.csv inputfile.csv > output.csv Here are sample lines from my input file (inputfile.csv): Ata,Aqu,Ama3,Abe,0.053475,0.025,0.1,0.11275,0.1,0.15,0.83377 Ata135,Aru2,Aba301,A29,0.055525,0.025,0.1,0.082825,0.075,0.125 Ata135,Atb,Aca,Am54,0.14695,0.1,0.2,0.05255,0.025,0.075,0.8005, Adc,Aru7,Ama301,Agr84,0.002075,0,0.025,0.240075,0.2,0. My

问题 I need to match if a sentence starts with a capital and ends with [?.!] in Python. EDIT It must have [?.!] only at end but allow other punctuation in the sentence import re s = ['This sentence is correct.','This sentence is not correct', 'Something is !wrong! here.','"This is an example of *correct* sentence."'] # What I tried so for is: for i in s: print(re.match('^[A-Z][?.!]$', i) is not None) It does not work, after some changes I know the ^[A-Z] part is correct but matching the

问题 I need to match if a sentence starts with a capital and ends with [?.!] in Python. EDIT It must have [?.!] only at end but allow other punctuation in the sentence import re s = ['This sentence is correct.','This sentence is not correct', 'Something is !wrong! here.','"This is an example of *correct* sentence."'] # What I tried so for is: for i in s: print(re.match('^[A-Z][?.!]$', i) is not None) It does not work, after some changes I know the ^[A-Z] part is correct but matching the

问题 I need to match if a sentence starts with a capital and ends with [?.!] in Python. EDIT It must have [?.!] only at end but allow other punctuation in the sentence import re s = ['This sentence is correct.','This sentence is not correct', 'Something is !wrong! here.','"This is an example of *correct* sentence."'] # What I tried so for is: for i in s: print(re.match('^[A-Z][?.!]$', i) is not None) It does not work, after some changes I know the ^[A-Z] part is correct but matching the

问题 I need to match if a sentence starts with a capital and ends with [?.!] in Python. EDIT It must have [?.!] only at end but allow other punctuation in the sentence import re s = ['This sentence is correct.','This sentence is not correct', 'Something is !wrong! here.','"This is an example of *correct* sentence."'] # What I tried so for is: for i in s: print(re.match('^[A-Z][?.!]$', i) is not None) It does not work, after some changes I know the ^[A-Z] part is correct but matching the

问题 I need to match if a sentence starts with a capital and ends with [?.!] in Python. EDIT It must have [?.!] only at end but allow other punctuation in the sentence import re s = ['This sentence is correct.','This sentence is not correct', 'Something is !wrong! here.','"This is an example of *correct* sentence."'] # What I tried so for is: for i in s: print(re.match('^[A-Z][?.!]$', i) is not None) It does not work, after some changes I know the ^[A-Z] part is correct but matching the

问题 How can I match all numbers along with specific characters in a String using regex? I have this so far if (!s.matches("[0-9]+")) return false; I don't understand much regex, but this matches all characters from 0-9 and now I need to be able to match other specific characters, for example "/", ":", "$" 回答1: You can use this regex by including those symbols in a character class : s.matches("[0-9$/:]+") Read more about character class 回答2: You can add the other characters that you need to match