main

Where does the OS store argv and argc when a child process is executed?

时光怂恿深爱的人放手 提交于 2019-12-03 08:20:31
I'm having some difficulty understanding how the OS passes data from the address space of a parent process to the address space of a child process. Namely, in a C program, where is argc and argv stored upon being passed into main? I understand how argv is essentially a double pointer. What I'm not understanding is what the OS does with those values after loading them into the kernel. After creating an address space for the child process does it push these values on the stack of the new space? We obviously don't want to pass in pointers to another address space. For the record, I'm working with

Is there a good reason to write code in Program.cs/main as opposed to using classes? [closed]

为君一笑 提交于 2019-12-03 08:17:28
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . I am working on a pretty large application and my tech lead and I are not seeing eye to eye on certain things. One of them is regarding console applications. These applications are being ported to C# from shell scripts. Some of these scripts are reasonably large (300-400 lines of code after conversion) and do

Using module's own objects in __main__.py

你离开我真会死。 提交于 2019-12-03 06:28:56
问题 I’m trying to access a module’s data from inside its __main__.py . The structure is as follows: mymod/ __init__.py __main__.py Now, if I expose a variable in __init__.py like this: __all__ = ['foo'] foo = {'bar': 'baz'} How can I access foo from __main__.py ? 回答1: You need to either have the package already in sys.path , add the directory containing mymod to sys.path in __main__.py , or use the -m switch. To add mymod to the path would look something like this (in __main__.py ): import sys

public static void main () access non static variable

故事扮演 提交于 2019-12-03 05:11:52
问题 Its said that non-static variables cannot be used in a static method.But public static void main does.How is that? 回答1: No, it doesn't. public class A { int a = 2; public static void main(String[] args) { System.out.println(a); // won't compile!! } } but public class A { static int a = 2; public static void main(String[] args) { System.out.println(a); // this works! } } or if you instantiate A public class A { int a = 2; public static void main(String[] args) { A myA = new A(); System.out

ios access main window or view

余生长醉 提交于 2019-12-03 04:55:44
I would like to know if there is a simple way to access the main window or view in IOS. Something similar to: [UIScreen mainScreen] Thank you. Try : UIWindow *frontWindow = [[[UIApplication sharedApplication] windows] lastObject]; or simply : UIWindow *frontWindow = [[UIApplication sharedApplication] keyWindow]; The main window is best found using UIWindow * mainWindow = [UIApplication sharedApplication].windows.firstObject; Using keyWindow can return a keyboard or UIAlertView window, which lie above your application window. If you have a pointer to some subview in the window, you can easily

Scala App val initialization in main method

空扰寡人 提交于 2019-12-03 04:53:07
I have some code: object Main extends App { val NameTemplate = """^([A-Za-z]+)_(\d+)\.png""".r override def main (args:Array[String]) { // Why is NameTemplate null here? } } Why is NameTemplate not initialized within the main method? tenshi If you are using App trait, then you don't need to override main method - just write your code in the body of the object : object Main extends App { val NameTemplate = """^([A-Za-z]+)_(\d+)\.png""".r println(NameTemplate) val NameTemplate(name, version) = args(0) println(name + " v" + version) } It works because App trait extends DelayedInit trait which has

Get name of executable jar from within main() method [duplicate]

≡放荡痞女 提交于 2019-12-03 04:48:14
问题 This question already has answers here : How to get the path of a running JAR file? (29 answers) Closed 4 years ago . I've created an executable jar and using commons-cli to give the user the ability to specify command line parameters when he launches the client. Everything works fine. However, when I print the usage statement for the jar, I would like to show the following: usage: java -jar myprog.jar <options> <file> --help Display the help message --debug Enable debugging .... Printing of

Why is main() argument argv of type char*[] rather than const char*[]?

与世无争的帅哥 提交于 2019-12-03 04:32:22
When I wrote the following code and executed it, the compiler said deprecated conversion from string constant to char* int main() { char *p; p=new char[5]; p="how are you"; cout<< p; return 0; } It means that I should have written const char * . But when we pass arguments into main using char* argv[] we don't write const char* argv[] . Why? Because ... argv[] isn't const. And it certainly isn't a (static) string literal since it's being created at runtime. You're declaring a char * pointer then assigning a string literal to it, which is by definition constant; the actual data is in read-only

What is the difference between String[] and String… in Java?

只谈情不闲聊 提交于 2019-12-03 03:41:45
问题 How should I declare main() method in Java? Like this: public static void main(String[] args) { System.out.println("foo"); } Or like this: public static void main(String... args) { System.out.println("bar"); } What's actually the difference between String[] and String... if any? 回答1: How should I declare main() method in Java? String[] and String... are the same thing internally, i. e., an array of Strings. The difference is that when you use a varargs parameter ( String... ) you can call the

How does this C program compile and run with two main functions?

岁酱吖の 提交于 2019-12-03 02:55:17
问题 Today, while working with one custom library, I found a strange behavior. A static library code contained a debug main() function. It wasn't inside a #define flag. So it is present in library also. And it is used link to another program which contained the real main() . When both of them are linked together, the linker didn't throw a multiple declaration error for main() . I was wondering how this could happen. To make it simple, I have created a sample program which simulated the same