for-loop

How can I create a vector by only using for loop? (vector is specified in the body)

倖福魔咒の 提交于 2020-05-16 20:58:31
问题 (1,2,2,3,3,3,4,4,4,4,...,n,...,n) I want to make the above vector by for loop, but not using rep function or the other functions. This may not be good question to ask in stackoverflow, but since I am a newbie for R, I dare ask here to be helped. (You can suppose the length of the vector is 10) 回答1: With a for loop, it can be done with n <- 10 out <- c() for(i in seq_len(n)){ for(j in seq_len(i)) { out <- c(out, i) } } In R , otherwise, this can be done as rep(seq_len(n), seq_len(n)) 回答2: I

How can I create a vector by only using for loop? (vector is specified in the body)

我们两清 提交于 2020-05-16 20:57:07
问题 (1,2,2,3,3,3,4,4,4,4,...,n,...,n) I want to make the above vector by for loop, but not using rep function or the other functions. This may not be good question to ask in stackoverflow, but since I am a newbie for R, I dare ask here to be helped. (You can suppose the length of the vector is 10) 回答1: With a for loop, it can be done with n <- 10 out <- c() for(i in seq_len(n)){ for(j in seq_len(i)) { out <- c(out, i) } } In R , otherwise, this can be done as rep(seq_len(n), seq_len(n)) 回答2: I

Plotly: How to output multiple line charts in single figure?

给你一囗甜甜゛ 提交于 2020-05-15 22:42:48
问题 I am trying to plot line chart using plotly for multiple dataframes in a single graph. My code is: import plotly.express as px labels=category_names[:10] for category in category_names[:10]: df_b=df1[df1['Country/Region']==category] fig=px.line(df_b, x="Date", y="Confirmed",labels="Country/Region") print(category) fig.show() However, by using the above code I am just able to get the line graph for last iteration of for loop. Current output: Desired Output: Kindly help me with the code! 回答1:

Plotly: How to output multiple line charts in single figure?

穿精又带淫゛_ 提交于 2020-05-15 22:42:40
问题 I am trying to plot line chart using plotly for multiple dataframes in a single graph. My code is: import plotly.express as px labels=category_names[:10] for category in category_names[:10]: df_b=df1[df1['Country/Region']==category] fig=px.line(df_b, x="Date", y="Confirmed",labels="Country/Region") print(category) fig.show() However, by using the above code I am just able to get the line graph for last iteration of for loop. Current output: Desired Output: Kindly help me with the code! 回答1:

Terraform - how to use for_each loop on a list of objects to create resources

跟風遠走 提交于 2020-05-14 18:44:27
问题 I have an object containing the list of subnets I want to create. variable "subnet-map" { default = { ec2 = [ { cidr_block = "10.0.1.0/24" availability_zone = "eu-west-1a" } ], lambda = [ { cidr_block = "10.0.5.0/24" availability_zone = "eu-west-1a" }, { cidr_block = "10.0.6.0/24" availability_zone = "eu-west-1b" }, { cidr_block = "10.0.7.0/24" availability_zone = "eu-west-1c" } ], secrets = [ { cidr_block = "10.0.8.0/24" availability_zone = "eu-west-1a" }, { cidr_block = "10.0.9.0/24"

Python for loops only every second Item

…衆ロ難τιáo~ 提交于 2020-05-14 14:47:10
问题 never had such a problem and do not know how to solve or even call it... types = [105000, 105001, 105002, 105003, 105004, 105005, 105006, 105007] for type in types: print type prints only 105000 105002 105004 105006 but I don't know why. using a function to generate an array from input like self.arrSplit(105000,105001,105002,105003,105004,105005,105006,105007) function: def arrSplit(self, arr): itms = [] for it in arr.split(','): tt = it.split('-') if (len(tt) >= 2 and int(tt[0]) < int(tt[1])

Batch file : skipping folders starting with _ in FOR loop

穿精又带淫゛_ 提交于 2020-05-14 07:07:08
问题 I would like to exclude all profiles starting with _ without having to list each profile in an exclusion text file. Is it possible to do this ? @echo off set Target=D:\backup for /f "tokens=*" %%I in ('dir /a:d-h /b "%SystemDrive%\Users\*"') do if exist "%Target%\%%~nXI\" ( ........ ) pause exit Thank you very much in advance for helping ! 回答1: The following code example provides a methodology for retrieving the profile names you require, (those which are not a special account and whose names

forEach loop through two arrays at the same time in javascript [duplicate]

与世无争的帅哥 提交于 2020-05-12 06:53:41
问题 This question already has answers here : Javascript equivalent of Python's zip function (16 answers) Closed 8 months ago . I want to build a for loop that iterates through two variables at the same time. n is an array and j goes from 0 to 16. var n = [1,2,3,5,7,8,9,11,12,13,14,16,17,18,20,21,22]; var m = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]; m.forEach(k => { n.forEach(i => { console.log(i, k) }); }; The final result should output: 1,0 2,1 3,2 5,3 (...) Unfortunately this loop doesn't do

forEach loop through two arrays at the same time in javascript [duplicate]

我的梦境 提交于 2020-05-12 06:53:06
问题 This question already has answers here : Javascript equivalent of Python's zip function (16 answers) Closed 8 months ago . I want to build a for loop that iterates through two variables at the same time. n is an array and j goes from 0 to 16. var n = [1,2,3,5,7,8,9,11,12,13,14,16,17,18,20,21,22]; var m = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]; m.forEach(k => { n.forEach(i => { console.log(i, k) }); }; The final result should output: 1,0 2,1 3,2 5,3 (...) Unfortunately this loop doesn't do

forEach loop through two arrays at the same time in javascript [duplicate]

ⅰ亾dé卋堺 提交于 2020-05-12 06:52:39
问题 This question already has answers here : Javascript equivalent of Python's zip function (16 answers) Closed 8 months ago . I want to build a for loop that iterates through two variables at the same time. n is an array and j goes from 0 to 16. var n = [1,2,3,5,7,8,9,11,12,13,14,16,17,18,20,21,22]; var m = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]; m.forEach(k => { n.forEach(i => { console.log(i, k) }); }; The final result should output: 1,0 2,1 3,2 5,3 (...) Unfortunately this loop doesn't do