long-integer | 易学教程

What is the argument for printf that formats a long?

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问题 The printf function takes an argument type, such as %d or %i for a signed int . However, I don\'t see anything for a long value. 回答1: Put an l (lowercased letter L) directly before the specifier. unsigned long n; long m; printf("%lu %ld", n, m); 回答2: I think you mean: unsigned long n; printf("%lu", n); // unsigned long or long n; printf("%ld", n); // signed long 回答3: On most platforms, long and int are the same size (32 bits). Still, it does have its own format specifier: long n; unsigned

Java creating byte array whose size is represented by a long

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问题 I\'m trying to create a byte array whose size is of type long . For example, think of it as: long x = _________; byte[] b = new byte[x]; Apparently you can only specify an int for the size of a byte array. Before anyone asks why I would need a byte array so large, I\'ll say I need to encapsulate data of message formats that I am not writing, and one of these message types has a length of an unsigned int ( long in Java). Is there a way to create this byte array? I am thinking if there\'s no

The literal xyz of type int is out of range

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I am working with data types at the moment in Java, and if I have understood correctly the type long accepts a value between the ranges of: -9,223,372,036,854 to +9,223,372,036,854,775,807. Now as you can see below I have create a Long variable called testLong , although when I insert 9223372036854775807 as the value, I get an error stating: "The literal 9223372036854775807 of the type int is out of range." I don't know why it is referring to the long data type as an int Anyone have any ideas? Code Below: char testChar = 01; byte testByte = -128; int testInt = -2147483648; short testShort =

wordwrap a very long string

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How can you display a long string, website address, word or set of symbols with automatic line breaks to keep a div width? I guess a wordwrap of sorts. Usually adding a space works but is there a CSS solution such as word-wrap? For example it (very nastily) overlaps divs, forces horizontal scrolling etc. wwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww What can I add to the above string to fit it neatly within a few lines in a div or within the browser window? Paolo Bergantino This question has

Converting Long to Date in Java returns 1970

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I have list with long values (for example: 1220227200, 1220832000, 1221436800...) which I downloaded from web service. I must convert it to Dates. Unfortunately this way, for example: Date d = new Date(1220227200); returns 1 Jan 1970. Anyone know another way to convert it correctly? The Date constructor (click the link!) accepts the time as long in milliseconds , not seconds. You need to multiply it by 1000 and make sure that you supply it as long . Date d = new Date(1220227200L * 1000); This shows here Sun Aug 31 20:00:00 GMT-04:00 2008 tl;dr Instant.ofEpochSecond( 1_220_227_200L ) Know Your

How to use long id in Rails applications?

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问题 How can I change the (default) type for ActiveRecord\'s IDs? int is not long enough, I would prefer long. I was surprised that there is no :long for the migrations - does one just use some decimal? 回答1: Credits to http://moeffju.net/blog/using-bigint-columns-in-rails-migrations class CreateDemo < ActiveRecord::Migration def self.up create_table :demo, :id => false do |t| t.integer :id, :limit => 8 end end end See the option :id => false which disables the automatic creation of the id field

Break long word with CSS

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I have a situation where there can be long words like 'hellowordsometext' or integer like '1234567891122' without any space in between. check this js please. http://jsfiddle.net/rzq5e/6/ how is it possible to break it in to next line after it reach the div width. what happens now is, it spans out out along with th div <div>Solutionforentprise</div> What you need is word-wrap: break-word; , this property will force the non spaced string to break inside the div Demo div { width: 20px; word-wrap: break-word; } dev1234 I have found this solution my self. word-break: break-all; but it doesn't work

Java: Checking if a bit is 0 or 1 in a long

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问题 What method would you use to determine if the the bit that represents 2^x is a 1 or 0 ? 回答1: I'd use: if ((value & (1L << x)) != 0) { // The bit was set } (You may be able to get away with fewer brackets, but I never remember the precedence of bitwise operations.) 回答2: Another alternative: if (BigInteger.valueOf(value).testBit(x)) { // ... } 回答3: I wonder if: if (((value >>> x) & 1) != 0) { } .. is better because it doesn't matter whether value is long or not, or if its worse because it's

How to printf “unsigned long” in C?

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问题 I can never understand how to print unsigned long datatype in C. Suppose unsigned_foo is an unsigned long , then I try: printf(\"%lu\\n\", unsigned_foo) printf(\"%du\\n\", unsigned_foo) printf(\"%ud\\n\", unsigned_foo) printf(\"%ll\\n\", unsigned_foo) printf(\"%ld\\n\", unsigned_foo) printf(\"%dl\\n\", unsigned_foo) And all of them print some kind of -123123123 number instead of unsigned long that I have. 回答1: %lu is the correct format for unsigned long . Sounds like there are other issues at

Convert Double to Binary representation?

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问题 I tried to convert a double to its binary representation, but using this Long.toBinaryString(Double.doubleToRawLongBits(d)) doesn\'t help, since I have large numbers, that Long can\'t store them i.e 2^900 . 回答1: Long.toBinaryString(Double.doubleToRawLongBits(d)) appears to work just fine. System.out.println("0: 0b" + Long.toBinaryString(Double.doubleToRawLongBits(0D))); System.out.println("1: 0b" + Long.toBinaryString(Double.doubleToRawLongBits(1D))); System.out.println("2: 0b" + Long