long-integer

long value with 0 on left

流过昼夜 提交于 2019-11-28 10:02:12
问题 Why this behavior happens? long value = 123450; System.out.println("value: " + value); value: 123450 long value = 0123450; // ^ System.out.println("value: " + value); value: 42792 What is this 42792? 回答1: Why this behavior happens? Just as literals starting with 0x are treated as hexadecimal numbers (base 16), literals starting with a 0 are treated as octal numbers, i.e., numbers in base 8. (Try writing 0789, and you'll see that the compiler will complain.) What is this 42792? The number

Why can't I assign a 'long' a value of 4 billion?

烂漫一生 提交于 2019-11-28 08:54:28
I'm trying to declare a long value in Java, which unfortunately does not work. This is my code. It results in the following error message: "The literal 4294967296 of type int is out of range". long bytes = 4294967296; I need this value to make a file filter that filters out files that are bigger than 4294967296 bytes (4GB). The other way round works without any issues ( long size = file.length() ) with every file size, which is why I can't figure out why my declaration is not working. Add L to the end of the number: long bytes = 4294967296L; To answer your question title, the maximum value of

How do I include extremely long literals in C++ source?

不打扰是莪最后的温柔 提交于 2019-11-28 08:05:20
问题 I've got a bit of a problem. Essentially, I need to store a large list of whitelisted entries inside my program, and I'd like to include such a list directly -- I don't want to have to distribute other libraries and such, and I don't want to embed the strings into a Win32 resource, for a bunch of reasons I don't want to go into right now. I simply included my big whitelist in my .cpp file, and was presented with this error: 1>ServicesWhitelist.cpp(2807): fatal error C1091: compiler limit:

warning: left shift count >= width of type

若如初见. 提交于 2019-11-28 06:41:57
I'm very new to dealing with bits and have got stuck on the following warning when compiling: 7: warning: left shift count >= width of type My line 7 looks like this unsigned long int x = 1 << 32; This would make sense if the size of long on my system was 32 bits. However, sizeof(long) returns 8 and CHAR_BIT is defined as 8 suggesting that long should be 8x8 = 64 bits long. What am I missing here? Are sizeof and CHAR_BIT inaccurate or have I misunderstood something fundamental? long may be a 64-bit type, but 1 is still an int . You need to make 1 a long int using the L suffix: unsigned long x

Long vs BigInteger

可紊 提交于 2019-11-28 06:16:18
I understand that both java.lang.Long and java.math.BigInteger can hold very large natural numbers. I also know Long's max value, but what is the max value for BigInteger? And aside from capacity, would BigInteger ever perform better when working with generally large integers that still fall in Long's range? Question Is the only consideration: is my value too large for Long? AHungerArtist BigInteger is capable of holding far bigger numbers than Long. BigInteger seems capable of holding (2 ^ 32) ^ Integer.MAX_VALUE, though that depends on the implementation (and, even if truly unbounded in the

Parse String to long with leading zero

被刻印的时光 ゝ 提交于 2019-11-28 05:28:39
问题 Long story short (in Java): String input= "0888880747; long convert = Long.parseLong(input); The value of convert is now: 888880747 How can I parse the String to a long but retain the leading zero? 回答1: You cannot because a long does not have a leading zero. A long is supposed to store integers (the mathematical concept, not int), i.e. A string of characters like 05 is not an integer, 5 is. What you can do is format a long that holds 5 with a leading zero when you print it, see e.g. java.util

Can I convert long to int?

匆匆过客 提交于 2019-11-28 04:47:50
I want to convert long to int . If the value of long > int.MaxValue , I am happy to let it wrap around. What is the best way? Just do (int)myLongValue . It'll do exactly what you want (discarding MSBs and taking LSBs) in unchecked context (which is the compiler default). It'll throw OverflowException in checked context if the value doesn't fit in an int : int myIntValue = unchecked((int)myLongValue); Convert.ToInt32(myValue); Though I don't know what it will do when it's greater than int.MaxValue. realbart Sometimes you're not actually interested in the actual value, but in its usage as

Convert long to byte array and add it to another array

余生颓废 提交于 2019-11-28 04:04:55
I want to change a values in byte array to put a long timestamp value in in the MSBs. Can someone tell me whats the best way to do it. I do not want to insert values bit-by-bit which I believe is very inefficient. long time = System.currentTimeMillis(); Long timeStamp = new Long(time); byte[] bArray = new byte[128]; What I want is something like: byte[0-63] = timeStamp.byteValue(); Is something like this possible . What is the best way to edit/insert values in this byte array. since byte is a primitive I dont think there are some direct implementations I can make use of? Edit: It seems that

Long Int literal - Invalid Syntax?

和自甴很熟 提交于 2019-11-28 03:36:32
问题 The Python tutorial book I'm using is slightly outdated, but I've decided to continue using it with the latest version of Python to practice debugging. Sometimes there are a few things in the book's code that I learn have changed in the updated Python, and I'm not sure if this is one of them. While fixing a program so that it can print longer factorial values, it uses a long int to solve the problem. The original code is as follows: #factorial.py # Program to compute the factorial of a number

Java - Convert Human Readable Size to Bytes

僤鯓⒐⒋嵵緔 提交于 2019-11-28 03:19:28
问题 I've found lots of information about converting raw byte information into a human-readable format, but I need to do the opposite, i.e. convert the String "1.6 GB" into the long value 1717990000. Is there an in-built/well-defined way to do this, or will I pretty much have to roll my own? [Edit]: Here is my first stab... static class ByteFormat extends NumberFormat { @Override public StringBuffer format(double arg0, StringBuffer arg1, FieldPosition arg2) { // TODO Auto-generated method stub