logical-operators

Why doesn't func3 get executed in the program below? After func1, func2 doesn't need to get evaluated but for func3, shouldn't it? if (func1() || func2() && func3()) { System.out.println("true"); } else { System.out.println("false"); } } public static boolean func1() { System.out.println("func1"); return true; } public static boolean func2() { System.out.println("func2"); return false; } public static boolean func3() { System.out.println("func3"); return false; } You're using a short-circuited or. If the first argument is true, the entire expression is true. It might help if I add the implicit

I'm learning Java, coming from C and I found an interesting difference between languages with the boolean type. In C there is no bool / ean so we need to use numeric types to represent boolean logic ( 0 == false ). I guess in Java that doesn't work: int i = 1; if (i) System.out.println("i is true"); Nor does changing the conditional via a typecast: if ((boolean)i) So besides doing something like: if ( i != 0 ) Is there any other way to do a C-ish logic check on an int type? Just wondering if there were any Java tricks that allow boolean logic on non-boolean types like this. EDIT: The example

When we write the fizzbuzz script, why are we testing to see if it is equal to 0? Or am I misunderstanding? Example: $i % 3 == 0 <?php for ($i=1; $i<=100; $i++) { if ($i%3==0 && $i%5==0) { echo 'FizzBuzz'; }else if($i%3==0){ echo 'Fizz'; }else if($i%5==0){ echo 'Buzz'; }else{ echo $i; } echo "\n"; } The program fizzbuzz prints 'fizz' if a number is divisible by 3, 'buzz' if a number is divisible by 5, and 'fizzbuzz' if a number is divisible by both. Your program is not checking if the numbers are equal to 0, instead it is using the modulo operator to check if the remainders are 0. $i%3==0

I know about the (change) event Binding in angular2 but i am surprised why my code is not working as expected? My code is here.. http://plnkr.co/edit/9pSWSeqBc5oaSAtsfwNY?p=preview When the change event is called not both condition work as expected. (change)="holiday= !holiday && employee= !employee" When change event is called the first time it works fine but the second time it will work only for first condition i.e holiday . In my example what I expected is both the value to be either true or false but not as expected. Surely there is some mistake. Is there anyone who can explain the life

Is there a better way to write the following conditional in javascript? if ( value == 1 || value == 16 || value == -500 || value == 42.42 || value == 'something' ) { // blah blah blah } I hate having all of those logical ORs strung together. I'm wondering if there is some kind of shorthand. Thanks! var a = [1, 16, -500, 42.42, 'something']; var value = 42; if (a.indexOf(value) > -1){ // blah blah blah } Upd: Utility function sample as proposed in comments: Object.prototype.in = function(){ for(var i = 0; i < arguments.length; i++){ if (this == arguments[i]) return true; } return false; } So

Is it a bad idea to overload &&, || or comma operator and Why? Fred Foo I wouldn't overload operator&& or operator|| . Even if you define a class that gives rise to a Boolean algebra (finite sets, for example), it would probably be a better choice to overload operator& and operator| . The reason is that C++ programmers expect special semantics for operator&& and operator|| : they are short-circuited , i.e. don't evaluate their right-hand argument if not necessary. You can't get this behavior by overloading, since you'll be defining a function. Overloading operator, has been done in e.g. the