logical-operators

Javascript logical “!==” operator?

时光总嘲笑我的痴心妄想 提交于 2019-12-03 06:13:08
问题 I am getting back into web development, and have been trying to go over the nuances of jscript recently. I was pouring through the source of the THREEx extension library built on top of Three.JS and noticed this function THREEx.KeyboardState.prototype.pressed = function(keyDesc) { var keys = keyDesc.split("+"); for(var i = 0; i < keys.length; i++){ var key = keys[i]; var pressed; if( THREEx.KeyboardState.MODIFIERS.indexOf( key ) !== -1 ){ pressed = this.modifiers[key]; }else if( Object.keys

Using && in EL results in error: The entity name must immediately follow the '&' in the entity reference

佐手、 提交于 2019-12-03 06:05:25
I'm trying to use a conditional expression in an el expression used in jsf, but it does not work. <h:outputText value="#{(sel.description !=null) && (sel.description !='') ? sel.description : 'Empty description'} - "/> but it does not work, the compiler says: Error Traced[line: 118] The entity name must immediately follow the '&' in the entity reference. Do you have any suggestions? Thank you! You seem to be using Facelets (which is perfectly fine). It's however a XML based view technology. Everything which you write in Facelets has to be syntactically valid XML. The & is in XML a special

Applying logical and to list of boolean values

社会主义新天地 提交于 2019-12-03 05:03:23
Consider the following list of Boolean values in Scala List(true, false, false, true) How would you using either foldRight or foldLeft emulate the function of performing a logical AND on all of the values within the list? val l = List(true, false, false, true) val andAll = l.foldLeft(true)(_ && _) Instead of using foldLeft/Right , you can also use forall(identity) for the logical AND, or exists(identity) for the logical OR. edit: The benefit of these functions is the early exit. If forall hits a false or exists a true , they will immediately return. Without initial value as in foldLeft , List

Logical operator AND with php regular expression

情到浓时终转凉″ 提交于 2019-12-03 03:30:30
I'd like to use a kind of logical operator "AND" in my regular expression. I tried this: (?=exp1)(?=exp2) But in PHP ?= doesn't work and need to write my program in PHP language. Is there another method? The expression has to match if there are present all the conditions and in any order. I don't wanna write every permutation like: (exp1)(exp2)(exp3)|(exp1)(exp3)(exp2)|.... PHP does support lookahead expressions. You're probably not using them correctly, though. Assuming you want to match a string that contains all three of foo , bar and baz , you need the regex ^(?=.*foo)(?=.*bar)(?=.*baz)

Database design / normalization structure needs to contain ANDs, ORs, optional elements and their relationships

心不动则不痛 提交于 2019-12-03 03:19:55
I want to store the details of college courses in a (MySql) database but I'm not sure how to maintain the relationship between modules and selections. Basically, a course can have mandatory section, group of optional modules, an options section and within each there can be selections which contain ANDs or ORs between modules. Simple example : A 60 credit course has a few mandatory modules which make up 40 credits. That leaves 20 credits to be selected from the group of optional modules. (Modules themselves can hold different amount of credits). Effectively; ('Mandatory module 1' AND 'Mandatory

Defining double exclamation?

女生的网名这么多〃 提交于 2019-12-03 03:12:56
I understand what a double exclamation mark does (or I think I understand) but I am not sure how it is defined on a random object. For example in the code snippet below: Assignment *a; if (!getAssignment(query, a)) return false; hasSolution = !!a; if (!a) return true; How do I know what value will the double exclamation mark result in ? In other words does it always convert to true ? false ? or can you define a behavior for it such as executing a method to determine the result (how does the object know how to act in this situation) ? I am bit confused about this piece of code due to all these

how to use NOT operator for integers in JAVA

别等时光非礼了梦想. 提交于 2019-12-02 23:41:34
问题 how to use NOT operator for integers in JAVA when i put NOT operator (!) it shows an error package com.learnJava.first; public class LogicalOpTable { public static void main(String[] args) { int p,q; System.out.println("P\t Q\t AND\t OR\t XOR\t NOT\n"); p = 1; q = 1; System.out.println(p+ "\t " + q + "\t " + (p&q) + "\t " + (p|q) + "\t " + (p^q) + "\t " + !p ); p = 1; q = 0; System.out.println(p + "\t " + q + "\t " + (p&q) + "\t " + (p|q) + "\t " + (p^q) + "\t " + !p); p = 0; q = 1; System

Compare character with multiple characters in C

∥☆過路亽.° 提交于 2019-12-02 21:48:02
问题 How can i compare a character in C with other characters without using an 'if' with tons of '||'? For example let's say I have a character named 'i' that I want to compare with 8 other characters that have no connection between them whatsoever, and if 'i' equals to at least one of those 8 characters then the expression is true. Something like this: if(i == c1 || i == c2 || i == c2 ........){ /* do stuff */} But on a big application these comparisons are a lot, not just 3 or 8. Is there a

Test for multiple conditions in same if test?

安稳与你 提交于 2019-12-02 18:37:50
问题 I tried googling and failed. Using C, I have an IF statement. I want to test a variable against two non-consecutive values. Is it possible to do if (state == 1 || 3) Meaning if state is 1 or if state is 3. Or does it have to be if (state == 1 || state == 3) I'm thinking the first actually means if state is 1, or 3, which means the test will always be true (if true or true). Is there a way to write this without having to rewrite the variable name multiple times? No, I don't want to use a case

Ruby logical operators [duplicate]

ぐ巨炮叔叔 提交于 2019-12-02 18:28:05
问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: Is there any wisdom behind “and”, “or” operators in Ruby ? What is the difference, if any, between the following pairs of logical operators? && vs. and || vs. or 回答1: The "word" versions have lower precedence than the "symbol" versions. In fact, they have even lower precedence than assignment. 来源: https://stackoverflow.com/questions/3225613/ruby-logical-operators