linked-list

问题 I've just implemented the Linked List. It works perfectly fine but even tough I've seen notation I am unable to create working destructor on Node, that's why it's unimplemented here in code. I need to implement working destructor on node Destructor of List but this one is simple I will just use the destructor from Node class(but I need this one). Make the List friendly to Node so I will not have to use getNext(), but I think I can handle it myself(not sure how, but I'll find out). Please look

问题 Ok so I have never worked with fstream before or opened and read and files in a program. My instructor just gave a few lines of code that open, read, and close a text file. I'm supposed to take the data out of the text file and put it into separate nodes in a linked list and then go on to do other things with it which is not important because I know how to do it. My problem is that I don't know how to a assign these values to the struct values. The txt file looks like this: Clark Kent 55000

问题 I have a query in classic ASP like this: sql_test="select * from Openquery(it_test, 'select * from IT_DB.HOST') the problem is that I want to test the connection to the linked server before executing it and getting an error on the page. If the connection to the linked server doesn't work (ex: db down) I can execute a query on the local SQL server 2000 db avoiding getting an error on the page. 回答1: I tend to use this code... 'GetDataSet error columns... const C_ERROR = "ERROR" 'Used when an

问题 void InsertAtTail(struct node** headref,int val) { struct node *current,*newnode; current=*headref; newnode=malloc(sizeof(struct node)); if(current==NULL) { newnode->data=val; newnode->next=NULL; *headref=newnode; current=*headref; } else { while(current->next!=NULL) { current=current->next; } newnode->data=val; newnode->next=NULL; current->next=newnode; } } struct node* CopyList(struct node* headref) { struct node* newlist=NULL; struct node* current; current=headref; if(current==NULL) {

问题 Can you suggest an algorithm that find all pairs of nodes in a link list that add up to 10. I came up with the following. Algorithm: Compare each node, starting with the second node, with each node starting from the head node till the previous node (previous to the current node being compared) and report all such pairs. I think this algorithm should work however its certainly not the most efficient one having a complexity of O(n2). Can anyone hint at a solution which is more efficient

问题 I want to create a linked list using Cypher over REST. If I create the head of the list using the following query: MERGE (headNode:HEAD {list:"mylist"}) WITH headNode MERGE headNode-[:LINK]->(headNode) RETURN headNode And then do the insert using this query: MERGE (headNode:HEAD {list:"mylist"})-[old:LINK]->after DELETE old CREATE headNode-[:LINK]->(newNode:LINKNODE { number : {nodeNumber} })-[:LINK]->after Then everything is fine as long as I don't run multiple insert queries in parallel.

问题 I saw this example here http://www.d3noob.org/2013/03/d3js-force-directed-graph-example-basic.html I can understand it to an extent where I can make basic changes, but have not been able to do one thing specifically which is to highlight (change color) of all connected nodes. e.g If I mouse over node 1 or click on node 1,it should find all neighboring nodes and highlight the link paths by changing color. I looked at clicking a node in d3 from a button outside the svg already answered but I

问题 This question already has answers here : What is the reason for using a double pointer when adding a node in a linked list? (14 answers) Closed 6 years ago . I have a question about signly linked lists in C. I've created a linked list with the code shown below : #include <stdio.h> #include <stdlib.h> struct node { int data; struct node* next; }; struct node *mknode(int data) { struct node* np=malloc(sizeof(struct node)); np->data=data; np->next=NULL; return np; } struct node * insert (struct

问题 How to find the beginning node of a loop in a given linked list ? Let's call this the cycle point So far, I've understand the following (using slow/fast pointer): Assume list has a non-looped part of size k slow moves k steps fast moves 2k steps fast is (2k - k)= k steps ahead of slow slow is at the beginning of loop; also known as Cycle point fast is (LOOP_LENGTH - k) steps behind from Cycle point or slow pointer at this point for each 1 step slow moves, fast moves 2 steps and gains on slow

问题 This question already has answers here : Static nested class in Java, why? (13 answers) Closed 4 years ago . In most of the cases I've seen that nested classes are static . Lets take an example of Entry class in HashMap static class Entry<K,V> implements Map.Entry<K,V> { final K key; V value; Entry<K,V> next; final int hash; ..... ..... } Or Entry class of LinkedList private static class Entry<E> { E element; Entry<E> next; Entry<E> previous; ..... ..... } What I know so far about nested