linked-list

问题 I am new to stackoverflow and the Python language and have a question. I know how to implement a singly linked list in Python but am having trouble with doubly linked list, more specifically inserting into the middle of the doubly linked list. Can anyone help me with code to do this? Thank you 回答1: Me also, I'm new to Python, but I hope I can help you. So if I got your question correctly, suppose you have some (classic) linked list implementation like this: # Simple LinkedList class class

问题 EDIT*(8:14 PM) - Sorry I corrected my code and made this instead a method so it can be more easily understood. I am not sure how to properly cast a struct when adding to the end of a linked list. Compiling this code gives me an cast warning at the very last line. This may be the reason why the rest of my code does not properly function. For example: #include <stdlib.h> typedef struct { int data; struct node *next; } node; node *HEAD = NULL; node *addNode(int num) { if (HEAD == NULL) { HEAD =

问题 I'm preparing for a technical interview and will be asked to write the algorithm for a linked list in ruby. I understand linked lists completely, but have struggled writing the code. Can someone show me how this is done? I started it below.. class Node def initialize(item) @item = item @next = nil end end 回答1: You almost did it, really. I can give you very old-school, Lisp-like implementation, if you are brave enough to show it to your interviewer. In this approach, list is a pair (two

问题 We are using a Doubly Linked List data structure to store some unordered data (The data as such is unordered, however the node order in the link list is relevant). A common operation on this data structure is NodeBeforeNode(Node N1, Node N2), which is given two node pointers in the list and determines which of them precedes the other. This operation takes linear time as it needs to traverse the list to find the other element, which is pretty slow. To speed this up we have cached the ordinal

问题 Firstly, if this question is inappropriate because I am not providing any code or not doing any thinking on my own, I apologize, and I will delete this question. For an assignment, we are required to create an array of nodes to simulate a linked list. Each node has an integer value and a pointer to the next node in the list. Here is my .DATA section .DATA linked_list DWORD 5 DUP (?) ;We are allowed to assume the linked list will have 5 items linked_node STRUCT value BYTE ? next BYTE ? linked

问题 I'm learning hashtable data structures and I want to make a hashtable with a flexible length array of pointers to struct Link (linked list pieces), so that hashtable initialization will set the array to be a length input into the initialization function. At first I was getting the error "flexible array not at the end of struct". When its at the end (as shown) the program crashes (but it still compiles). This is my code: typedef struct Link{ int key; char *name; struct Link *next; } Link;

问题 I am learning data structures and algorithms for C++ from Goodrich. They have given this LinkedList implementation. I understand the code but I am not but I am not able to use this in main class. How do I construct an instance and make insert, delete? For example I tried to create an instance of the class as follows: StringLinkedList() L; But it is showing the error: expected ";" before 'L #include <iostream> #include <string> using namespace std; class StringNode { private: string elem;

问题 There are 2 lists source={3,2,1} and dest ={4,5,6,7} where the head pointer of the linked lists are there in 3 and 4 respectively. head node from source is deleted and the data 3 is moved to dest list and it is made as new head node in dest list. So after first round source ={2,1} dest ={3,4,5,6,7} where head in source is pointing to 2 now and head in dest is pointing to 3. Finally I have to make source = NULL and Dest = {1,2,3,4,5,6,7} head => 1 . I can do that by calling the move node

问题 java.util.Queue<TreeNode> queue = new java.util.LinkedList<TreeNode>(); LinkedList implements Queue. Shouldn't Queue be on the right side of the above statement and LinkedList the left? 回答1: In Java, you can assign a value to a variable of the same type or a more general type. In your example, new LinkedList<TreeNode>() is a value. Since LinkedList implements Queue , it's more specific than Queue . i.e. A LinkedList is a Queue . For instance, all three of these are valid Object o = new

问题 I have been using Linked List implemented ArrayList for storing my data in Java . It is quite big and i am partitioning it into several regions using subList and sending it into different processor creating threads for processing.I have 80 cores in my system and I am creating 20 threads now. Each thread has to process at least one million of instances from millions of instances. Data is partitioned as: List<List<Integer>> totalInstances = new ArrayList<List<Integer>>(); //fill the data in