linkage

How can I prove that inline functions iin class default to internal linkage? In other words/: How can I display output of internal linkage to console? EDIT: unix platform Here is an FAQ about inline functions http://www.parashift.com/c++-faq-lite/inline-functions.html . 来源： https://stackoverflow.com/questions/4957582/how-can-i-prove-that-inline-functions-default-to-internal-linkage

Are methods of templated classes implied inline linkage (not talking about the inline optimization), or is it just templated methods which are? // A.h template<typename T> class A { public: void func1(); // #1 virtual void func2(); // #2 template<typename T2> void func3(); // #3 }; template<typename T> void A<T>::func1(){} // #1 template<typename T> void A<T>::func2(){} // #2 template<typename T> template<typename T2> void A<T>::func3<T2>(){} // #3 Are all the above cases inline [linkage]? (Should I explicitly write inline for any of them)? Template functions and member functions of template

存储类修饰符 声明中出现的存储类修饰符(storage class specifier)用于修改标识符的链接和对应对象的存储周期(链接与存储周期的概念将会在本章后面介绍)。链接(linkage)和存储周期(storage duration)是C语言中常会遇到的困扰。链接(标识符的属性)和存储周期(对象的属性)两者在声明中都会受相同关键字集(存储类修饰符)的影响。本章后面会介绍对象的存储周期可以是动态的、静态的,或已分配的(allocated),而标识符的链接可以是外部(external)、内部(internal)或不作限定的。类似“静态链接”或“外部存储”等说法在C语言中是没有意义的。注意:对象有存储周期,而非链接;标识符有链接,而非存储周期。 一个声明中不能出现多个存储类修饰符。函数标识符只可以使用存储类修饰符extern或static。函数参数只可以使用存储类修饰符register。5种存储类修饰符的含义如下: auto 声明中有修饰符auto的对象,具有动态存储周期。这种修饰符只能用于函数内的对象声明。在ANSI C中,默认情况下函数内的对象声明都有动态的存储周期,所以不需要使用修饰符auto。 register 当声明对象有动态存储周期时,可以使用修饰符register。该关键字告诉编译器,所声明对象的访问应该尽量快——理想情况下,应该将该对象存储在CPU寄存器

I have 2 files A.cpp and B.cpp which look something like A.cpp ---------- class w { public: w(); }; B.cpp ----------- class w { public: w(); }; Now I read somewhere ( http://publib.boulder.ibm.com/infocenter/comphelp/v8v101/index.jsp?topic=%2Fcom.ibm.xlcpp8a.doc%2Flanguage%2Fref%2Fcplr082.htm ) that classes have external linkage. So while building I was expecting a multiple definition error but on the contrary it worked like charm. However when I defined class w in A.cpp, I got the redefinition error which makes me believe that classes have internal linkage. Am I missing something here?

The standard says that given a declaration of inline void foo(); that foo is an inline function with external linkage (because by default all function declarations have external linkage). This strikes me as odd. because the one definition rule section 3.2 (in both C++03 and C++11) say: 3 ... An inline function shall be defined in every translation unit in which it is used. 5 There can be more than one definition of a[n] ... inline function with external linkage (7.1.2) ... Given such an entity named D defined in more than one translation unit ... each definition of D shall consist of the same

When we are compiling a C program the output is stored in a.out. How can we redirect the compiled output to another file? Most C compilers provide the -o option for this, such as: gcc -o gentext gentext.c cc -o mainprog -Llib -lmymath firstbit.c secondbit.o xlc -o coredump coredump.c -ofilename will make filename instead of a.out . Arkaitz Jimenez According to the manual: -o <file> Place the output into <file> In Unix, where C originated from, C programs are usually compiled module-by-module, and then the compiled modules are linked into an executable. For a project that consists of modules