legend

问题 I generate a plot for multiple datasets. Each of the datasets should get it's own legend, which might contain greek letters, plotmath symbols or sub and superscrition. I'd like to generate the legend-texts in a loop. Bquote works fine, if there is only one legend text. If I try to add additinal legend texts, the plotmath-commads get lost,... x <- 0:10 y1 = x * x y2 = x * 10 plot (1,1, type="n", xlab=bquote(Omega), ylab="Y", las=1, xlim=range(x), ylim=range(y1, y2)) lines(x, y1, col=1, pch=1,

问题 I've got a data frame that looks like this: glimpse(spottingIntensityByMonth) # Observations: 27 # Variables: 3 # $ yearMonth <dttm> 2015-05-01, 2015-06-01, 2015-07-01, 2015-08-01, 2015-09-01, 2015-10-01, 2... # $ nClassificationsPerDayPerSpotter <dbl> 3.322581, 13.212500, 13.621701, 6.194700, 18.127778, 12.539589, 8.659722, ... # $ nSpotters <int> 8, 8, 22, 28, 24, 22, 24, 27, 25, 29, 32, 32, 21, 14, 18, 13, 20, 19, 15, ... I am trying to plot it with ggplot2 like so: ggplot() + geom_col

问题 I want to write a R-squared term for my legend but I do not know how. Could someone help me please? My legend syntax is: legend(2,10, c("BW (MPE=3%, R-squared=0.77)", "MY (MPE=5%, R-squared=0.80)", pch=c(2,3)) I would liek to express R-squared as R2 as we normally have in the text. 回答1: It will work if you combine bquote and as.expression : plot(1:10) legend(2, 10, c(as.expression(bquote("BW (MPE = 3%," ~ R^2 ~ "= 0.77)")), as.expression(bquote("MY (MPE = 5%," ~ R^2 ~ "= 0.80)"))), pch=c(2,3)

问题 What I want is like this: What I get is this: So how to merge the markers into one label? also for the lines, for the lines, of course, u can realize it by not assigning label to the second line while using the same linetype, but for the markers, you can not, since they are of different shapes. 回答1: I think it's best to use a full legend - otherwise, how will your readers know the difference between the two models, or the two datasets? I would do it this way: But, if you really want to do it

问题 I am using JQPlot and I have many graphs on one HTML page. Each of the graphs has the same legend. My question is this: Is it possible to display a legend totally outside of the graph with its own position on the HTML page or in its own div? 回答1: legend:{ show:true, renderer: $.jqplot.EnhancedLegendRenderer, location: 's' , placement : "outside", marginTop : "30px", rendererOptions: { numberRows: 1 } }, You can use placement : "outside" like in the above code. And you can move it using

问题 I'm creating a figure with multiple subplots. One of these subplots is giving me some trouble, as none of the axes corners or centers are free (or can be freed up) for placing the legend. What I'd like to do is to have the legend placed somewhere in between the 'upper left' and 'center left' locations, while keeping the padding between it and the y-axis equal to the legends in the other subplots (that are placed using one of the predefined legend location keywords). I know I can specify a

问题 I'm creating plots using Matplotlib that I save as SVG, export to .pdf + .pdf_tex using Inkscape, and include the .pdf_tex-file in a LaTeX document. This means that I can input LaTeX-commands in titles, legends etc., giving an image like this which renders like this when I use it in my LaTeX document. Notice that the font for the numbers on the axes change, and the LaTeX-code in the legend is compiled: Code for the plot (how to export to SVG not shown here, but can be shown on request):

问题 I want to plot a centered legend outside of the plotting area in a device having multiple plots. There has been many questions (with slight variations) asked in SO about changing the position of legend in a R plot. For example: 1) R - Common title and legend for combined plots 2) Common legend for multiple plots in R 3) Plot a legend outside of the plotting area in base graphics? etc. Now what I understood from the above questions is that I got to set the option xpd = T or xpd = NA to plot

问题 I am trying to find guidance on how to control and customize the legend in Seaborn plots but I can not find any. To make the issue more concrete I provide a reproducible example: surveys_by_year_sex_long year sex wgt 0 2001 F 36.221914 1 2001 M 36.481844 2 2002 F 34.016799 3 2002 M 37.589905 %matplotlib inline from matplotlib import * from matplotlib import pyplot as plt import seaborn as sn sn.factorplot(x = "year", y = "wgt", data = surveys_by_year_sex_long, hue = "sex", kind = "bar",

问题 How to Change Legend Text of a Chart Object in Crystal Reports 10? I did a report with chart by Crystal Report. The chart show me how many males and females there. So now the male enter to database as int = 0, and the females enter to database as int = 1, so in legend of chart display 0 = 226 and 1 = 44, means that the Males = 226, and the Females = 44. I need to make a formula that can change the 0 to Males, and the 1 to Females. please see the picture below: See the Format Object I couldnot