left-join

LEFT OUTER JOIN Error creating a subquery on bigquery

ぃ、小莉子 提交于 2021-02-18 19:29:32
问题 I'm trying to eval MAL, WAL and DAU from a event table on my bq... I create a query find DAU and with him find WAU and MAU, but it does not work, i received this error: LEFT OUTER JOIN cannot be used without a condition that is an equality of fields from both sides of the join. It's my query WITH dau AS ( SELECT date, COUNT(DISTINCT(events.device_id)) as DAU_explorer FROM `workspace.event_table` as events GROUP BY 1 ) SELECT date, dau, (SELECT COUNT(DISTINCT(device_id)) FROM `workspace.event

MySQL Select rows that from table01 that doesn't exist on table02 [duplicate]

廉价感情. 提交于 2021-02-17 06:55:26
问题 This question already has answers here : Find records from one table which don't exist in another (8 answers) Closed 10 months ago . I have two tables, table03 have 10 rows and table01 have 21 rows, now I want to get rows from table03 where they don't exist in table01, so far I wrote this query but it shows all rows of table03 even some rows doesn't exist on table01. SELECT T3.`DateAdded`, T3.`Query_name`, T3.`Fund`, T3.`Ticker` FROM `table_name03` T3 LEFT JOIN `table_name01` T1 ON T3.

Double left join in dplyr to recover values

微笑、不失礼 提交于 2021-02-16 14:29:40
问题 I've checked this issue but couldn't find a matching entry. Say you have 2 DFs: df1:mode df2:sex 1 1 2 2 3 And a DF3 where most of the combinations are not present, e.g. mode | sex | cases 1 1 9 1 1 2 2 2 7 3 1 2 1 2 5 and you want to summarise it with dplyr obtaining all combinations (with not existent ones=0): mode | sex | cases 1 1 11 1 2 5 2 1 0 2 2 7 3 1 2 3 2 0 If you do a single left_join (left_join(df1,df3) you recover the modes not in df3, but 'Sex' appears as 'NA', and the same if

Using update with Left Join BigQuery

China☆狼群 提交于 2021-02-11 13:28:58
问题 I am trying to write an Update query with LEFT JOIN in BigQuery but I am not sure how to write it. update Table1 set ColumnTest = ifnull(b.value, 'no run') From left join (select distinct ID,value FROM Table2 where value = 10) B -- where Table1.ID= Table2.ID I have 2 tables Table1 and Table2 I want to update Table1.ColumnTest with Table2.Value where Table1.ID= Table2.ID and if Table1 <> Table2 then update Table1.ColumnTest with 'no run' Thanks!! New Try UPDATE Table1 SET LP = IFNULL(t2.value,

Using update with Left Join BigQuery

夙愿已清 提交于 2021-02-11 13:28:12
问题 I am trying to write an Update query with LEFT JOIN in BigQuery but I am not sure how to write it. update Table1 set ColumnTest = ifnull(b.value, 'no run') From left join (select distinct ID,value FROM Table2 where value = 10) B -- where Table1.ID= Table2.ID I have 2 tables Table1 and Table2 I want to update Table1.ColumnTest with Table2.Value where Table1.ID= Table2.ID and if Table1 <> Table2 then update Table1.ColumnTest with 'no run' Thanks!! New Try UPDATE Table1 SET LP = IFNULL(t2.value,

Replacing null based on a condition

泪湿孤枕 提交于 2021-02-11 04:24:13
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

Replacing null based on a condition

梦想与她 提交于 2021-02-11 04:24:13
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

Replacing null based on a condition

给你一囗甜甜゛ 提交于 2021-02-11 04:23:24
问题 I am having a table with many columns (but posting only col1, col2, col3 here for simplified post): id col1 col2 col3 source_id a1 765.3 23-Apr-08 cat a5 a2 3298.3 (null) dog a4 a3 8762.1 27-Nov-10 rat a8 a4 (null) (null) (null) (null) a5 (null) (null) (null) a6 a6 (null) (null) (null) (null) I want to fill null values of source _id with values from id . For example, source_id a5 row has null which has to replaced with id a1 values , subsequently, source_id a6 row having null to be replaced

SQL left join two tables independently

一曲冷凌霜 提交于 2021-02-10 20:39:49
问题 If I have these tables: Thing id | name ---+--------- 1 | thing 1 2 | thing 2 3 | thing 3 Photos id | thing_id | src ---+----------+--------- 1 | 1 | thing-i1.jpg 2 | 1 | thing-i2.jpg 3 | 2 | thing2.jpg Ratings id | thing_id | rating ---+----------+--------- 1 | 1 | 6 2 | 2 | 3 3 | 2 | 4 How can I join them to produce id | name | rating | photo ---+---------+--------+-------- 1 | thing 1 | 6 | NULL 1 | thing 1 | NULL | thing-i1.jpg 1 | thing 1 | NULL | thing-i2.jpg 2 | thing 2 | 3 | NULL 2 |

How do I remove results based on conditions to calculate an average and specific movie

不想你离开。 提交于 2021-02-10 16:20:51
问题 I have the schema below. A quick explanation of it is: bob rated the movie up, 5/5 james rated the movie up, 1/5 macy rated the movie up, 5/5 No one has rated the movie avengers. The logic: If I am personA, look up everyone I have blocked. Look up all the movie reviews. Anyone who has left a movie review, and personA has blocked, remove them from the calculation. Calculate the average rating of the movies. CREATE TABLE movies ( id integer AUTO_INCREMENT primary key, name varchar(100) NOT NULL