launching

Click a button --> Launch a *.exe file

ε祈祈猫儿з 提交于 2019-12-19 16:35:30
问题 Basically, what I want to do is launch an *.exe file when I click on a button. I want this done in VB.NET. I have Microsoft Visual Basic 2008 Express Edition. The button I have is called 'btnYES'. How can I launch an *.exe file from the click of this button? 回答1: In the event handler of the button call Process.Start("C:\path_to\myapp.exe") You will find further samples in the MSDN documentation for Process.Start(). In case you don't know how an event handler is created: Simply open the form

Click a button --> Launch a *.exe file

99封情书 提交于 2019-12-19 16:30:52
问题 Basically, what I want to do is launch an *.exe file when I click on a button. I want this done in VB.NET. I have Microsoft Visual Basic 2008 Express Edition. The button I have is called 'btnYES'. How can I launch an *.exe file from the click of this button? 回答1: In the event handler of the button call Process.Start("C:\path_to\myapp.exe") You will find further samples in the MSDN documentation for Process.Start(). In case you don't know how an event handler is created: Simply open the form

Opening non-default browser with lite-server in angular2 quick start guide

房东的猫 提交于 2019-12-03 11:14:41
问题 Having followed the TypeScript version of the Angular 2 Quick Start guide, I was wondering if it is possible, and if so how to configure the lite-server to launch a browser other than the default. It seems lite-server will take command line args, served to it via yargs.argv . And it seems yargs will attempt to parse command line args based on fairly common standards (i.e. If a token begins with a -- , it represents an argument name, otherwise an argument value) to obtain argv . lite-server

Opening non-default browser with lite-server in angular2 quick start guide

拟墨画扇 提交于 2019-12-03 02:43:43
Having followed the TypeScript version of the Angular 2 Quick Start guide , I was wondering if it is possible, and if so how to configure the lite-server to launch a browser other than the default. It seems lite-server will take command line args, served to it via yargs.argv . And it seems yargs will attempt to parse command line args based on fairly common standards (i.e. If a token begins with a -- , it represents an argument name, otherwise an argument value) to obtain argv . lite-server will attempt to use the open property that it gets from argv , which is ultimately what launches the

How to setup a JDI launching connector?

£可爱£侵袭症+ 提交于 2019-11-30 22:45:30
So I'm trying to work myself into JDI. I was already successful hooking my debugger application into my debugee program by first starting the debuggee with VM commands: -agentlib:jdwp=transport=dt_socket,server=y,address=8000 and then launching my debugger which establishes a connection by the use of an attaching connector: VirtualMachineManager vmm = Bootstrap.virtualMachineManager(); AttachingConnector ac = vmm.attachingConnectors().get(0); Map<String, Connector.Argument> env = ac.defaultArguments(); env.get("port").setValue("8000"); env.get("hostname").setValue("localhost"); VirtualMachine

How to setup a JDI launching connector?

隐身守侯 提交于 2019-11-30 17:25:33
问题 So I'm trying to work myself into JDI. I was already successful hooking my debugger application into my debugee program by first starting the debuggee with VM commands: -agentlib:jdwp=transport=dt_socket,server=y,address=8000 and then launching my debugger which establishes a connection by the use of an attaching connector: VirtualMachineManager vmm = Bootstrap.virtualMachineManager(); AttachingConnector ac = vmm.attachingConnectors().get(0); Map<String, Connector.Argument> env = ac

Get path+filename of file that was opened with my application

心不动则不痛 提交于 2019-11-27 07:10:26
问题 I'm an amateur at c# and I've been unable to locate the answer to this. Perhaps I am not aware of the correct terms to use. When a video file is dragged onto my exe application, I would like the application to know that it was launched with a file and be able to know the path and filename of that file. This way, the user does not have to use the file>open menu. Hope that makes sense. Thanks 回答1: You can check the command line arguments which were used to launch the application. If your