largenumber

Summing Large Numbers

旧时模样 提交于 2019-11-29 22:05:09
问题 I have being doing some problems on the Project Euler website and have come across a problem. The Question asks,"Work out the first ten digits of the sum of the following one-hundred 50-digit numbers." I am guessing there is some mathematical way to solve this but I was just wondering how numbers this big are summed? I store the number as a string and convert each digit to a long but the number is so large that the sum does not work. Is there a way to hold very large numbers as a variable

Why do comparisions between very large float values fail in python?

僤鯓⒐⒋嵵緔 提交于 2019-11-29 12:37:45
In my understanding, sys.float_info.max is the largest possible float value. However, it seems that comparing such large values fail . import math import sys m = sys.float_info.max # type 'float' m == m # True m < m # False m > m # False m == m-1.0 # True m < m-1.0 # False m > m-1.0 # False m == m-1e100 # True m < m-1e100 # False m > m-1e100 # False m == m-1e300 # False m > m-1e300 # True m < m-1e300 # False I assume that's because of the limited precision? If so, in what numerical range can i operate safely? The above code was run with Python 3.5.2. On a typical machine running Python, there

How to convert Active Directory pwdLastSet to Date/Time

不问归期 提交于 2019-11-29 09:50:47
public static string GetProperty(SearchResult searchResult, string PropertyName) { if (searchResult.Properties.Contains(PropertyName)) { return searchResult.Properties[PropertyName][0].ToString(); } else { return string.Empty; } } The above method works great for most Active Directory properties except those that are related to date/time such as pwdLastSet, maxPwdAge, etc. My question is how to I get the pwdLastSet to a human readable datetime (like 8/13/2013 or August 13, 2013, etc) I've tries this but it threw exceptions public static Int64 ConvertADSLargeIntegerToInt64(object

How to round/ceil/floor a bcmath number in PHP?

北战南征 提交于 2019-11-29 09:39:14
Is there any library function for this purpose, so I don't do it by hand and risk ending in TDWTF? echo ceil(31497230840470473074370324734723042.6); // Expected result 31497230840470473074370324734723043 // Prints <garbage> This will work for you: $x = '31497230840470473074370324734723042.9'; bcscale(100); var_dump(bcFloor($x)); var_dump(bcCeil($x)); var_dump(bcRound($x)); function bcFloor($x) { $result = bcmul($x, '1', 0); if ((bccomp($result, '0', 0) == -1) && bccomp($x, $result, 1)) $result = bcsub($result, 1, 0); return $result; } function bcCeil($x) { $floor = bcFloor($x); return bcadd(

Extremely Large Integers in PHP [duplicate]

风流意气都作罢 提交于 2019-11-29 04:02:06
Possible Duplicate: Working with large numbers in PHP. I run a completely useless Facebook app. I'm having a problem with PHP's support for integers. Basically, users give themselves ridiculous numbers of points. The current "king" has 102,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,002,557,529,927 points. PHP does not seem to play well with large integers. When someone tries to add more than a certain amount of points it will fail because PHP treats those numbers as infinite. Is there some math library for working with ridiculously large numbers? Should I treat the

How are extremely large floating-point numbers represented in memory?

余生颓废 提交于 2019-11-28 14:34:25
How do arbitrary-precision libraries like GMP store extremely large floating-point numbers represented in memory? I would imagine that if for instance you wanted to compute Pi or Euler's constant to say, 2,000,000 digits that you would allocate a massive array of bytes for the digits to the right of the decimal place. Each byte would store 2 decimal place values and the array would be a member of a data structure with the number of digits and number of bytes used to store the value. Is this how it works? Current computers have 32 or 64-bit registers, so doing calculations on bytes is very

Long ints in Fortran

妖精的绣舞 提交于 2019-11-28 13:50:52
I'm trying to work with large numbers (~10^14), and I need to be able to store them and iterate over loops of that length, i.e. n=SOME_BIG_NUMBER do i=n,1,-1 I've tried the usual star notation, kind=8 etc. but nothing seems to work. Then I checked the huge intrinsic function, and the code: program inttest print *,huge(1) print *,huge(2) print *,huge(4) print *,huge(8) print *,huge(16) print *,huge(32) end program inttest produces the number 2147483647 in all cases. Why is this? I'm using gfortran (f95) on a 64-bit machine. If I'm going to need a bignum library, which one do people suggest? M.

C++ Random number from 1 to a very large number (e.g. 25 million)

懵懂的女人 提交于 2019-11-28 12:20:27
How would you make a function that generates a random number from 1 to 25 million? I've thought about using rand() but am I right in thinking that the maximum number, RAND_MAX is = 32000 (there about)? Is there a way around this, a way that doesn't reduce the probability of picking very low numbers and doesn't increase the probability of picking high / medium numbers? Edit: @Jamey D 's method worked perfectly independent of Qt. You could (should) use the new C++11 std::uniform_real_distribution #include <random> std::random_device rd; std::mt19937 gen(rd()); std::uniform_real_distribution<>

Handling numbers larger than Long in VBA

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-28 12:13:18
I am Currently trying to write some code in VBA to solve a problem from Project Euler. I have been trying to answer a question that requires you to find primes that can be divided into a number that will not fit in a long. Any suggestions as how to handle this problem? I know I can split the number between two variables and I have done that for addition and subtraction but never division. Any help will be appreciated. You can define a Decimal data type (12 Bytes), but only within a variant. Dim i As Variant i = CDec(i) Use the "Double" data type that takes larger values. 来源: https:/

Pascal's Triangle in C

試著忘記壹切 提交于 2019-11-28 11:01:31
问题 I'm a computer engineering student and next semester I am going to start C course. So in order to prepare myself a bit, I have started learning C by myself and stumbled across an interesting task, designed for, how it seemed to me at first sight, not a very advanced level. The task is to write a program to compute the value of a given position in Pascal's Triangle . And the formula given to compute it is written as element = row! / ( position! * (row - position)! ) I've written a simple