largenumber

Stocking large numbers into numpy array

故事扮演 提交于 2020-05-08 06:58:26
问题 I have a dataset on which I'm trying to apply some arithmetical method. The thing is it gives me relatively large numbers, and when I do it with numpy, they're stocked as 0. The weird thing is, when I compute the numbers appart, they have an int value, they only become zeros when I compute them using numpy. x = np.array([18,30,31,31,15]) 10*150**x[0]/x[0] Out[1]:36298069767006890 vector = 10*150**x/x vector Out[2]: array([0, 0, 0, 0, 0]) I have off course checked their types: type(10*150**x[0

Stocking large numbers into numpy array

China☆狼群 提交于 2020-05-08 06:58:10
问题 I have a dataset on which I'm trying to apply some arithmetical method. The thing is it gives me relatively large numbers, and when I do it with numpy, they're stocked as 0. The weird thing is, when I compute the numbers appart, they have an int value, they only become zeros when I compute them using numpy. x = np.array([18,30,31,31,15]) 10*150**x[0]/x[0] Out[1]:36298069767006890 vector = 10*150**x/x vector Out[2]: array([0, 0, 0, 0, 0]) I have off course checked their types: type(10*150**x[0

SQL Server retain decimal scale and precision for operations on very lage numbers

眉间皱痕 提交于 2020-04-30 06:28:40
问题 Following my previous question I am still struggling with an arithmetic overflow error in SQL Server 2017. How can I perform a multiplication/division of a large decimal(38,0) value and retain/regain both the precision and scale? In my current example I simply want to halve DECLARE @var1 decimal(38,0) = 85070591730234615865699536669866196992; (and truncate the result if @var1 were odd). From this post I have gathered that even if I do not attempt to divide by 2 but multiply by 0.5 instead I

Time limit excedeed error for large values

半腔热情 提交于 2020-04-07 08:01:13
问题 I have been given x and k , where x is the number of factors of a number A , and k is the number of prime factors of A . Given x and k , I have to find out whether such an A exists. For example: INPUT : 4 2 OUTPUT : 1 Since 6 is a number that has 4 factors 1, 2, 3, 6 out of which 2 are prime(2, 3). Also it is given that x and k can have any values between 1 and 10 9 . Here is my code for the this: long long int x, k; scanf("%lld%lld", &x, &k); int ans = 0; bool stop = false; for (long long

which datatype should i use to store a variable 10^200 in C language?

核能气质少年 提交于 2020-01-30 06:30:24
问题 how to handle integers like 10^200 or larger than that in C language? it won't work even I use long long. then what should I do? I heard about big integer. but don't know how to work with it. as far i know it is a library function for C#. but I am working with C. is there any other way except big integer to work with such large integers? and can someone also explain me how to use big integer? To clarify, I'm only looking for a solution that will work in C. 回答1: See similair question. In short

How do i calculate the remainder for extremely large exponential numbers using java?

空扰寡人 提交于 2020-01-05 02:43:51
问题 How do i calculate the remainder for extremely large exponential numbers using java ? eg. (48^26)/2401 I tried using BIGINTEGER, however it gave the same output for large divisors.I'm not sure if BIG INTEGER can do this .I have tried all other PRIMITIVE data type.They seem to be insufficient. FYI it tried the following code: BigInteger a = new BigInteger("48"); a = a.pow(26); BigInteger b = new BigInteger("2401");//49*49 a = a.mod(b); System.out.println(a); I don't know why i got the same

How do i calculate the remainder for extremely large exponential numbers using java?

柔情痞子 提交于 2020-01-05 02:43:27
问题 How do i calculate the remainder for extremely large exponential numbers using java ? eg. (48^26)/2401 I tried using BIGINTEGER, however it gave the same output for large divisors.I'm not sure if BIG INTEGER can do this .I have tried all other PRIMITIVE data type.They seem to be insufficient. FYI it tried the following code: BigInteger a = new BigInteger("48"); a = a.pow(26); BigInteger b = new BigInteger("2401");//49*49 a = a.mod(b); System.out.println(a); I don't know why i got the same

How to round/ceil/floor a bcmath number in PHP?

。_饼干妹妹 提交于 2019-12-29 07:30:48
问题 Is there any library function for this purpose, so I don't do it by hand and risk ending in TDWTF? echo ceil(31497230840470473074370324734723042.6); // Expected result 31497230840470473074370324734723043 // Prints <garbage> 回答1: This will work for you: $x = '31497230840470473074370324734723042.9'; bcscale(100); var_dump(bcFloor($x)); var_dump(bcCeil($x)); var_dump(bcRound($x)); function bcFloor($x) { $result = bcmul($x, '1', 0); if ((bccomp($result, '0', 0) == -1) && bccomp($x, $result, 1))

C++ Random number from 1 to a very large number (e.g. 25 million)

不想你离开。 提交于 2019-12-28 23:48:05
问题 How would you make a function that generates a random number from 1 to 25 million? I've thought about using rand() but am I right in thinking that the maximum number, RAND_MAX is = 32000 (there about)? Is there a way around this, a way that doesn't reduce the probability of picking very low numbers and doesn't increase the probability of picking high / medium numbers? Edit: @Jamey D 's method worked perfectly independent of Qt. 回答1: You could (should) use the new C++11 std::uniform_real

select2 + large number of records

此生再无相见时 提交于 2019-12-24 05:53:14
问题 I am using select2 dropdown. It's working fine for smaller number of items. But when the list is huge (more than 40000 items) it really slows down. It's slowest in IE. Otherwise simple Dropdownlist works very fast, till 1000 records. Are there any workarounds for this situation? 回答1: ///////////////**** Jquery Code *******/////////////// var CompanypageSize = 10; function initCompanies() { var defaultTxtOnInit = 'a'; $("#DefaultCompanyId").select2({ allowClear: true, ajax: { url: "