laravel-5.5

I was wondering if it is possible to define different data for item resource and collection resource. For collection I only want to send ['id', 'title', 'slug'] but the item resource will contain extra details ['id', 'title', 'slug', 'user', etc.] I want to achieve something like: class PageResource extends Resource { /** * Transform the resource into an array. * * @param \Illuminate\Http\Request * @return array */ public function toArray($request) { return [ 'id' => $this->id, 'title' => $this->title, 'slug' => $this->slug, 'user' => [ 'id' => $this->user->id, 'name' => $this->user->name,

I have two tables in a Postgresql 9.3 database, companies and sites. There is a one-to-many relationship between them with companies on the one side. There is a foreign key constraint that prevents the deletion of a company if sites have been assigned to it. If I attempt to delete the company with the ID 'KSL' using an SQL query directly on the database, I get the expected error: ERROR: update or delete on table "companies" violates foreign key constraint "sites_company_id_fkey" on table "sites" DETAIL: Key (company_id)=(KSL) is still referenced from table "sites". I have defined an artisan

I just created a new project of laravel version 5.5 with the laravel installer.And run the command " php artisan make:auth ".The views and controller are generated for the user authentication.And also run " php artisan migrate " to create tables needed in the database.When visiting the login page and register page,filling the form and submit.It shows "The page has expired due to inactivity. Please refresh and try again.".But refreshing the page does nothing help. Seen in the source code,where causes the exception: if ($e instanceof ModelNotFoundException) { $e = new NotFoundHttpException($e-

I'm new to Laravel and I'm trying to use the Artisan command... php artisan serve It displays... Laravel development server started: http://127.0.0.1:8000 However, it won't automatically launch and when I manually enter http://127.0.0.1:8000 it shows this error: RuntimeException No application encryption key has been specified. Any ideas? I'm using Laravel framework 5.5-dev. From Encryption - Laravel - The PHP Framework For Web Artisans : "Before using Laravel's encrypter, you must set a key option in your config/app.php configuration file. You should use the php artisan key:generate command

In Laravel 4 I was able to get the current route name using... Route::currentRouteName() How can I do it in Laravel 5? Try this Route::getCurrentRoute()->getPath(); or \Request::route()->getName() from v5.+ use Illuminate\Support\Facades\Route; $currentPath= Route::getFacadeRoot()->current()->uri(); Laravel 5.3 Route::currentRouteName(); //use Illuminate\Support\Facades\Route; Or if you need the action name Route::getCurrentRoute()->getActionName(); You can find everything about laravel Routes in the Laravel API: http://laravel.com/api/5.0/Illuminate/Routing/Router.html http://laravel.com/api

When I create a new Laravel project, the browser displays an error 500. I found this in the log: PHP Parse error: syntax error, unexpected '?' in vendor/laravel/framework/src/Illuminate/Foundation/helpers.php on line 233 the code in 233 is: return app('cache')->get($arguments[0], $arguments[1] ?? null); But as i know, null coalescing operator( ?? ) is supported from PHP 7.0 My PHP Version: PHP 7.1.8-2+ubuntu14.04.1+deb.sury.org+4 (cli) (built: Aug 4 2017 14:34:05) ( NTS ) Copyright (c) 1997-2017 The PHP Group Zend Engine v3.1.0, Copyright (c) 1998-2017 Zend Technologies with Zend OPcache v7.1