laravel-4

问题 I'm using Laravel and Composer to build a web app. On my local machine I have its requirements setup within the composer.json file and everything works as it should. I'm using Github to push to the production server, however, I then run composer install and add the providers and aliases for one of my packages, I then get an error saying that the service provider hasn't been found. I then proceeded to check the vendor folder, which had the directory in it for the package, but within this

问题 I'm trying to keep the values of a form when Redirect::back on Laravel 4, but I can't find a way to do this. This is my form: {{ Form::open(array('route' => 'generate', 'files' => true)) }} {{ Form::radio('myType', '1', true); }} {{ Form::label('myType', '1'); }} {{ Form::radio('myType', '2'); }} {{ Form::label('myType', '2'); }} {{ Form::radio('myType', '3'); }} {{ Form::label('myType', '3'); }} {{ Form::text('myName'); }} {{ Form::file('uploadImage'); }} {{ Form::submit('Go'); }} {{ Form:

问题 I need to run a query having collate utf8_bin like so: SELECT * FROM `table` WHERE `field`='value' collate utf8_bin; This is strictly for an admin script and I don't want to update the table charset itself, just for the particular query. Can I do this using the Eloquent ORM or do I need to write this query out? 回答1: Since you can configure MySQL driver to use one: 'mysql' => array( 'driver' => 'mysql', 'host' => 'localhost', 'database' => 'database', 'username' => 'root', 'password' => '',

问题 I'm building a Laravel 4 app and I want to protect my admin area so it is only accessible if the user is logged in/authenticated. What is the best way to do this? The Laravel docs say you can protect a route like this: Route::get('profile', array('before' => 'auth', function() { // Only authenticated users may enter... })); But what happens when my route looks like this: Route::resource('cms', 'PostsController'); How do I protect a route that is directing to a controller? Thanks in advance!

问题 In the Laravel documentation it says you can use this syntax for querying an object relation to get only the Posts that have at least one Comment: $posts = Post::has('comments')->get(); I'm trying something similar where I want to fetch only objects that have at least one relation object. These are my two classes: class Movie extends Eloquent { protected $table = 'movie'; public function matches() { return $this->hasMany("Match"); } } class Match extends Eloquent { protected $table = 'match';

问题 I'm working on inserting a CSV into a table. I don't have any control over what's in the CSV and a lot of the fields are blank. In my very first record for instance, the field "baths_full" is just empty (two commas back to back). On my production server running MySQL 5.5.37, it inserts the record with the baths_full as an empty field. On my local machine running MySQL 5.6.19, it gives me the error: [Illuminate\Database\QueryException] SQLSTATE[HY000]: General error: 1366 Incorrect integer

问题 I have a website which works fine on host, but I'm currently trying to install it on localhost. I've downloaded everything and configured to work on localhost - Database & URL. The problem is this error: Unhandled Exception Message: syntax error, unexpected end of file Location: C:\Program Files (x86)\EasyPHP-12.1\www\laravel\view.php(386) : eval()'d code on line 118 And I don't know what causes it. Any solutions? P.S. I've setup in my windows' host file 127.0.0.1 myproject.dev . 回答1: There

问题 I am trying to upload photos by using kcfinder as a plugin for Ckeditor. When configuring kcfinder I use this config : CKEDITOR.editorConfig = function(config) { config.filebrowserBrowseUrl = '../../../../assets/kcfinder/browse.php?type=files'; config.filebrowserImageBrowseUrl = 'assets/kcfinder/browse.php?type=images'; config.filebrowserFlashBrowseUrl = 'assets/kcfinder/browse.php?type=flash'; config.filebrowserUploadUrl = '../../../../assets/kcfinder/upload.php?type=files'; config

问题 I downloaded the starter kit for laravel using sentry from GitHub. Everything is fine so far. Blog page has pagination. I am able to change the number of items per page as I like by changing the same pagination(x) value. Now problem is, i created a new page manually by myself called "Search" which displays results for Keywords searched. Here I added the same pagination, it shows the number of items per page as mentioned, page numbers, arrows. Everything is perfect, but when I click page 2 it

问题 I'm trying to add a class to a laravel form. The array is being passed as the third argument, as required, but I get the above error. {{ Form::input('text', $variable->name, array('class' => 'form-control')) }} If I get rid of the third argument, the form displays as expected (unstyled). I can't see what I'm doing wrong here - can anyone help? 回答1: {{ Form::text('text', $variable->name, array('class' => 'form-control')) }} 回答2: I can see from the api that there is another argument expected: