kwargs

问题 I have the following: class Foo: def __init__(self, **kwargs): print kwargs settings = {foo:"bar"} f = Foo(settings) This generates an error: Traceback (most recent call last): File "example.py", line 12, in <module> settings = {foo:"bar"} NameError: name 'foo' is not defined How do I properly pass a dict of key/value args to kwargs? 回答1: Use the **kw call convention: f = Foo(**settings) This works on any callable that takes keyword arguments: def foo(spam='eggs', bar=None): return spam, bar

问题 When passing a named parameter request through **kwargs , I get an error- Traceback (most recent call last): File "testKwargs.py", line 9, in <module> load_strategy(request="myReq", backend="myBackend", redirect_uri=None, *args, **kwargs) File "testKwargs.py", line 5, in load_strategy get_strategy("backends", "strategy", "storage", *args, **kwargs) TypeError: get_strategy() got multiple values for keyword argument 'request' The code in testKwargs.py is below- def get_strategy(backends,

问题 I have a simple string which describes a mysql connection. The string is in this form: dsn = 'user=dbuser database=mydbase host=localhost' this string can contain many of the things listed in the connection params listed here: http://dev.mysql.com/doc/connector-python/en/connector-python-connectargs.html basically, when you connect to the database you do so something like: cnx = MySQLConnection(user='dbuser', database='mydbase', host='localhost') I want to create the name=value arguments for

问题 How do I pass a dictionary to a function with Python's Multiprocessing? The Documentation: https://docs.python.org/3.4/library/multiprocessing.html#reference says to pass a dictionary, but I keep getting TypeError: fp() got multiple values for argument 'what' Here's the code: from multiprocessing import Pool, Process, Manager def fp(name, numList=None, what='no'): print ('hello %s %s'% (name, what)) numList.append(name+'44') if __name__ == '__main__': manager = Manager() numList = manager

问题 Oh dear, I hope I got the title right. :) How can one pass the **kwargs supplied to a wrapper-function definition , to another (enclosed) function call that it wraps. For example: def wrapped_func(**kwargs): # Do some preparation stuff here. func('/path/to/file.csv', comma_separated_key=value_injected_here) # Do some other stuff. So for example, this call: wrapped_func(error_bad_lines=True, sep=':', skip_footer=0, ...) Should result in this: func('/path/to/file.csv', error_bad_lines=True, sep

问题 Oh dear, I hope I got the title right. :) How can one pass the **kwargs supplied to a wrapper-function definition , to another (enclosed) function call that it wraps. For example: def wrapped_func(**kwargs): # Do some preparation stuff here. func('/path/to/file.csv', comma_separated_key=value_injected_here) # Do some other stuff. So for example, this call: wrapped_func(error_bad_lines=True, sep=':', skip_footer=0, ...) Should result in this: func('/path/to/file.csv', error_bad_lines=True, sep

问题 I have some objects that have a dictionary of attributes, obj.attrs . The constructor for these objects accepts a dict and/or **kwargs , for convenience. It looks a little like this: class Thing: def __init__(self, attrs={}, **kwargs): for arg in kwargs: attrs[arg] = kwargs[arg] self.attrs = attrs Such that Thing({'color':'red'}) does the same as Thing(color='red') . My problem is that the constructor somehow remembers the last attrs value passed to it. For example: >>> thing1 = Thing(color=

问题 I have some objects that have a dictionary of attributes, obj.attrs . The constructor for these objects accepts a dict and/or **kwargs , for convenience. It looks a little like this: class Thing: def __init__(self, attrs={}, **kwargs): for arg in kwargs: attrs[arg] = kwargs[arg] self.attrs = attrs Such that Thing({'color':'red'}) does the same as Thing(color='red') . My problem is that the constructor somehow remembers the last attrs value passed to it. For example: >>> thing1 = Thing(color=

问题 This question already has answers here : Calling a Python function with *args,**kwargs and optional / default arguments (2 answers) Closed last year . I'm trying to wrap my head around using args and kwargs in Python 3 (Python 3.7.0) but I'm running into some issues with my understanding. Here is a simple function I have: def add_args(y=10, *args, **kwargs): return y, args, kwargs And test it to see what is returned: print(add_args(1, 5, 10, 20, 50)) print(add_args()) >> (1, (5, 10, 20, 50),

问题 I've got an error as a traceback below: Traceback (most recent call last): File "setup_rouge.py", line 7, in <module> from files2rouge import settings File "/home/cerdas/files2rouge/files2rouge/__init__.py", line 2, in <module> from files2rouge.files2rouge import main File "/home/cerdas/files2rouge/files2rouge/files2rouge.py", line 17, in <module> from files2rouge import utils File "/home/cerdas/files2rouge/files2rouge/utils.py", line 14 print(*args, **kwargs) ^ SyntaxError: invalid syntax