kotlin

Ordering Users List based on MessageList - Kotlin & Android

由 我的梦境 提交于 2020-12-15 01:40:19
问题 I am trying to sort a list of User Objects by the order in which User IDs appear in the MessageList Array. The MessageList consists of ID's of people a user is chatting with (ordered by time - using sortwith), which is then to be sent to a User Adapter as a list of Users in the same order as the message list. This is so that username, profile image and other details can be displayed... I have learnt a datasnapshot of the Users from firebase provides as is order and hence needs to be ordered

Ordering Users List based on MessageList - Kotlin & Android

由 断了今生、忘了曾经 提交于 2020-12-15 01:38:53
问题 I am trying to sort a list of User Objects by the order in which User IDs appear in the MessageList Array. The MessageList consists of ID's of people a user is chatting with (ordered by time - using sortwith), which is then to be sent to a User Adapter as a list of Users in the same order as the message list. This is so that username, profile image and other details can be displayed... I have learnt a datasnapshot of the Users from firebase provides as is order and hence needs to be ordered

Ordering Users List based on MessageList - Kotlin & Android

由 梦想的初衷 提交于 2020-12-15 01:38:02
问题 I am trying to sort a list of User Objects by the order in which User IDs appear in the MessageList Array. The MessageList consists of ID's of people a user is chatting with (ordered by time - using sortwith), which is then to be sent to a User Adapter as a list of Users in the same order as the message list. This is so that username, profile image and other details can be displayed... I have learnt a datasnapshot of the Users from firebase provides as is order and hence needs to be ordered

'Inappropriate blocking method call' - How to handle this warning on Android Studio

由 我只是一个虾纸丫 提交于 2020-12-15 00:53:16
问题 I have written this code snippet to download image files from firebase storage to local storage. contentResolver.openOutputStream(uri)?.use { ops -> // * Firebase.storage.getReferenceFromUrl(model.mediaUrl).stream.await().stream.use { ips -> val buffer = ByteArray(1024) while (true) { val bytes = ips.read(buffer) // * if (bytes == -1) break ops.write(buffer, 0, bytes) // * } } } In the marked lines, android studio is giving me Inappropriate blocking method call warning, highlighting

'Inappropriate blocking method call' - How to handle this warning on Android Studio

由 て烟熏妆下的殇ゞ 提交于 2020-12-15 00:48:41
问题 I have written this code snippet to download image files from firebase storage to local storage. contentResolver.openOutputStream(uri)?.use { ops -> // * Firebase.storage.getReferenceFromUrl(model.mediaUrl).stream.await().stream.use { ips -> val buffer = ByteArray(1024) while (true) { val bytes = ips.read(buffer) // * if (bytes == -1) break ops.write(buffer, 0, bytes) // * } } } In the marked lines, android studio is giving me Inappropriate blocking method call warning, highlighting

'Inappropriate blocking method call' - How to handle this warning on Android Studio

由 谁都会走 提交于 2020-12-15 00:48:13
问题 I have written this code snippet to download image files from firebase storage to local storage. contentResolver.openOutputStream(uri)?.use { ops -> // * Firebase.storage.getReferenceFromUrl(model.mediaUrl).stream.await().stream.use { ips -> val buffer = ByteArray(1024) while (true) { val bytes = ips.read(buffer) // * if (bytes == -1) break ops.write(buffer, 0, bytes) // * } } } In the marked lines, android studio is giving me Inappropriate blocking method call warning, highlighting

Type mismatch: inferred type is String? but String was expected

由 北慕城南 提交于 2020-12-14 13:13:51
问题 Due to this line in my codes : var myRef = child_myRef.child(FirebaseAuth.getInstance().uid) 回答1: The reason because your FirebaseAuth.getInstance().uid is String? (can be Null), but input of .child() need a String (none Null), so please check null before that: FirebaseAuth.getInstance().uid?.let{ var myRef = child_myRef.child(it) ..... } Or if you make sure FirebaseAuth.getInstance().uid never Null, you can using FirebaseAuth.getInstance().uid!! , but It not is a good approach 回答2: You can

Spring Boot 的2020最后一击：2.4.1、2.3.7、2.2.12 发布

由 夙愿已清 提交于 2020-12-14 12:27:23
近日，Spring Boot官方发布了本年度最后一次版本更新，主要针对目前维护的三个版本： 2.4.x：第一个bug修复版本 2.4.1 2.3.x：常规维护版本 2.3.7 2.2.x：常规维护版本 2.2.12 由于2.2.x和2.3.x已经非常稳定，所以我们主要关注本次2.4.1的更新。 2.4.1版本内容 由于在Spring Boot 2.4.0版本中，对原有的配置加载机制做了较大改动，不少开发者反映在升级的时候也出现了各种不同的问题。而这次2.4.1的发布，主要着手解决了不少关于配置相关的Bug。下面我们一起看看这次都解决了哪些重要问题： 通过通配符匹配的配置文件互相覆盖的问题 配置属性与JavaBean之间绑定的顺序问题 允许递归配置文件组的引用 外部应用程序属性加载顺序的问题 @Name在Kotlin中绑定失败的问题 Redis健康检查器对性能消耗过大的问题 Actuator端点在MVC和WebFlux下运行时，无法正确响应自定义HTTP状态码 Actuator的env端点没有正确显示包装类型的数据 通过配置树绑定非字符串属性时，找不到转换器的问题 使用Log4J调用LoggingSystem时会抛出NullPointerException的问题 加载属性文件的时候，“#”标注之后的内容会丢失 在启用 WebTestClientContextCustomizer 之前

细节决定成败！34岁安卓开发大叔感慨，面试心得体会

由 为君一笑 提交于 2020-12-13 10:22:04
前文 本文希望通过揭开一些 React 隐藏的技术细节, 来辅助对官方文档中某些概念的理解 读者可以将本文看做对官方文档的补充 行文方式我采用的是 提问-解答 的方式, 即先根据官方文档给出的使用规则, 提出Why, 然后我们根据实际的调试再来解答这些Why, 最后系统的整理这些 Why 变成 How, 如果你们有更好的行文方式, 也欢迎留言讨论 另外为了阅读体验, 我不会粘贴过多的源码, 避免打断各位读者的思路. Android 相关 1. Android 之 SharedPreferences 内部原理浅析 2. Android 源码分析-消息队列和 Looper 3. Android 源码分析—带你认识不一样的 AsyncTask 4. Android 性能优化之使用线程池处理异步任务 5. Android Context 完全解析，你所不知道的 Context 的各种细节 6. LocalBroadcastManager 的实现原理，与 BroadcastReceiver 异同 7. Android进程间通信（IPC）机制Binder简要介绍和学习计划 8.Activity的启动方式和flag详解 9.Android源码分析-资源加载机制 10.Android中Thread、Handler、Looper、MessageQueue的原理分析 11.Android 源码解析 之

Problem with Kotlin readLine() function using IntelliJ internal console

由 时光怂恿深爱的人放手 提交于 2020-12-13 06:31:38
问题 When I try to read some value from a user, I get strange behavior. For example, if I have one simple program: fun main() { print("insert value: ") val tmp = readLine() println("value = $tmp") } I would expect the next behavior of the program: insert value: 1 value = 1 But I get the next behavior: insert value: 1 1 value = 1 So I would expect to insert the value 1 , hit Enter , and the program would output value = 1 . But instead of this, I have to input the value 1 , hit Enter , input the
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