kotlin

SourceSets - Groovy -> Kotlin DSL

早过忘川 提交于 2021-01-05 06:46:00
问题 sourceSets { main { java.srcDirs = ['src/main/kotlin', 'src/main/java'] res.srcDirs = [ 'src/main/res/layouts/activity', 'src/main/res/layouts/fragment', 'src/main/res/layouts/dialog', 'src/main/res/layouts/items', 'src/main/res/layouts/views', 'src/main/res/layouts', 'src/main/res' ] } } Here for java.srcDirs we convert it in kotlin DSL like java.sourceSets { getByName("main").java.srcDirs("src/main/kotlin") } But I don't know how to change sub folders within 'layout' res folder code in DSL

SourceSets - Groovy -> Kotlin DSL

爱⌒轻易说出口 提交于 2021-01-05 06:45:21
问题 sourceSets { main { java.srcDirs = ['src/main/kotlin', 'src/main/java'] res.srcDirs = [ 'src/main/res/layouts/activity', 'src/main/res/layouts/fragment', 'src/main/res/layouts/dialog', 'src/main/res/layouts/items', 'src/main/res/layouts/views', 'src/main/res/layouts', 'src/main/res' ] } } Here for java.srcDirs we convert it in kotlin DSL like java.sourceSets { getByName("main").java.srcDirs("src/main/kotlin") } But I don't know how to change sub folders within 'layout' res folder code in DSL

Android Navigation - Is it possible to restore a bundle from upper fragment with popBackStack method?

拜拜、爱过 提交于 2021-01-04 14:47:16
问题 I was trying to pass data between fragments while I was passing from upper fragment to down fragment, but I don't want to use the navigate method. It adds a new destination to the process history, but I want back to the previous fragment, restore it data and refresh the view. Is it possible to do it with NavController and popBackStack method? 回答1: After few hours I found a strange solution. findNavController().popBackStack() cannot pass data to the previous fragment, but we can do it using

什么是模型思维?发现问题解决问题之道:14种 MR 模型关系思维模式

你说的曾经没有我的故事 提交于 2021-01-04 14:11:12
在职场或者生活中,我们经常会遇到这样的情况: 在面对和解决一些问题的时候,有些人忙作一团,找不到解决问题的路径。而有些人却可以通过清晰的分析框架一步步解决问题。这样的思维差异,会带来完全不同的结果,不论是从效率上还是效果上。 人所掌握的知识和技能绝非是零散的信息和随意的动作,他们大多具有某种“结构”,这些结构就是模型。而厉害的人,或者精英就是善于掌握和利用这些模型解决问题的人。 模型-关系(MR)是经过广泛实践、证实可靠的、或者科学研究验证过的、或者不证自明的原理规律。 伟人们会深层次的思考问题,最终看清本质问题,成功的发明家或者创业者的思维模式也具备这种特质。 人类从起源到现在,认知这个宇宙的主要方式就是靠“想象”和“思考”。而想象中很大一部分就是建立“模型”和“类比”。 From the beginning to the present, the main way of human cognition of the universe is to rely on "imagination" and "thinking". A large part of imagination is to build "models" and "analogies". 人类从用火,用石器,再到铁器,到机械化工业生产,再到今天的计算机数字化信息技术,每一次科技的进步都是人类底层思维逻辑的提升和飞跃。

kotlin.UninitializedPropertyAccessException: lateinit property preferences has not been initialized

…衆ロ難τιáo~ 提交于 2021-01-04 10:22:16
问题 I used the code of shared preference in my multiple project and it worked correctly but now when i apply the same code in another project it stopped working. following is error kotlin.UninitializedPropertyAccessException: lateinit property preferences has not been initialized Shared preferences code object AppPrefrence { private const val NAME = "AComputerEngineer" private const val MODE = Context.MODE_PRIVATE private lateinit var preferences: SharedPreferences private val user_id = Pair(

kotlin.UninitializedPropertyAccessException: lateinit property preferences has not been initialized

ε祈祈猫儿з 提交于 2021-01-04 10:21:50
问题 I used the code of shared preference in my multiple project and it worked correctly but now when i apply the same code in another project it stopped working. following is error kotlin.UninitializedPropertyAccessException: lateinit property preferences has not been initialized Shared preferences code object AppPrefrence { private const val NAME = "AComputerEngineer" private const val MODE = Context.MODE_PRIVATE private lateinit var preferences: SharedPreferences private val user_id = Pair(

FusedLocationProviderClient requestLocationUpdates doesn't trigger LocationCallBack for API 23 above

时间秒杀一切 提交于 2021-01-04 09:08:39
问题 I have run out of possible ways on how to solve this issue. I am technically using the same code that is working in API 23 and above before I made tweaks on my app. The callback (in the requestLocationUpdate) does not trigger in phones that are marshmallow and above (but it works fine in the emulator, tested using the Pixel 2 API 26 emulator). Take note that permission is already granted/allowed and GPS is also enabled. Also as you can see in the code below I already put a try catch and still

Android: How to convert HTML string to Spanned to display in TextView (MUST work on API < 24)

牧云@^-^@ 提交于 2021-01-04 05:57:08
问题 For my app, I need to display HTML that contains spans (with background-color ) to a Spanned such that it can be displayed on a TextView , as Android's TextView does not support the span tag. I have first tried converting the String to a SpannableStringBuilder , and then retrieving the HTML encoded string from the casted string ( Spanned ). I need this to work on API 22-23, and thus, I cannot simply use fromHTML as fromHTML does not support span for API below 24. I am writing a function

Android: How to convert HTML string to Spanned to display in TextView (MUST work on API < 24)

大城市里の小女人 提交于 2021-01-04 05:54:06
问题 For my app, I need to display HTML that contains spans (with background-color ) to a Spanned such that it can be displayed on a TextView , as Android's TextView does not support the span tag. I have first tried converting the String to a SpannableStringBuilder , and then retrieving the HTML encoded string from the casted string ( Spanned ). I need this to work on API 22-23, and thus, I cannot simply use fromHTML as fromHTML does not support span for API below 24. I am writing a function

Why do I get this? Kotlin: Type mismatch: inferred type is String? but String was expected

跟風遠走 提交于 2021-01-04 05:42:00
问题 When I try to run this code: fun main() { val input: String = readLine() val outputs = input.toCharArray() for (i in 0 until input.length) { print("${outputs[i]}${outputs[i]}") } } I get this Error:(2, 25) Kotlin: Type mismatch: inferred type is String? but String was expected. How do I fix that? 回答1: The readLine() function returns a String? (nullable String). Return the line read or null if the input stream is redirected to a file and the end of file has been reached. There is no end of