key

How to generate an ssh key for logging into a server without a password

a 夏天 提交于 2020-05-15 05:35:06
问题 I have used servers on amazon AWS where they send me a public key .pem file and when I ssh in, all I have to do is: ssh -i key.pem user@server I now have a server of my own and am trying to figure out how I can do this with my server so I can automate commands to my server via ssh. I imagine that I need to generate this key on my server and copy it to my client machine. How do I generate this key? 回答1: On the client machine you wish to login from , run ssh-keygen . For a quick and easy key,

Merge two arrays into a single object with jq

我只是一个虾纸丫 提交于 2020-05-13 18:56:27
问题 I'm trying to use jq to parse a NOAA data feed into just the values I need: http://forecast.weather.gov/MapClick.php?FcstType=json&lat=39.56&lon=-104.85 I'm able to (separately) extract the two arrays I'm looking to combine: $ cat noaa.json | jq .time.startPeriodName [ "Today", "Tonight", "Friday", "Friday Night", "Saturday", "Saturday Night", "Sunday", "Sunday Night", "Monday", "Monday Night", "Tuesday", "Tuesday Night", "Wednesday" ] $ cat noaa.json | jq .data.weather [ "Mostly Sunny",

Merge two arrays into a single object with jq

我的梦境 提交于 2020-05-13 18:56:06
问题 I'm trying to use jq to parse a NOAA data feed into just the values I need: http://forecast.weather.gov/MapClick.php?FcstType=json&lat=39.56&lon=-104.85 I'm able to (separately) extract the two arrays I'm looking to combine: $ cat noaa.json | jq .time.startPeriodName [ "Today", "Tonight", "Friday", "Friday Night", "Saturday", "Saturday Night", "Sunday", "Sunday Night", "Monday", "Monday Night", "Tuesday", "Tuesday Night", "Wednesday" ] $ cat noaa.json | jq .data.weather [ "Mostly Sunny",

flutter MyhomePage({Key key, this.title}) : super(key: key); pls any one explain clearly with example flutter

我的未来我决定 提交于 2020-05-09 19:40:16
问题 In flutter anyone explain clearly with example my confusion about key , code as below MyHomepage({Key key, this.title}) : super(key: key); 回答1: The code is the constructor of the MyHomepage widget. {Key key, this.title} declares 2 optional named parameters (optional named because of {} ) where the first is of name key with type Key` the 2nd is of name title with the type of the field this.title and automatically initializes this.title with the passed value This is nice syntactic sugar that

PostgreSQL的外键深入使用

て烟熏妆下的殇ゞ 提交于 2020-04-25 16:58:14
有开发同事问及postgresql外键的用法,这里普及一下。外键是一个很基础的概念,使用得当可以对事务的一致性有很好的保障,方法上和Oracle是很接近的,作用很简单地说就是保证子表的数据都能在主表中找到,可保证数据一致性。 建立主表 postgres=# create table t_parent( postgres(# id serial primary key, postgres(# vname varchar(32), postgres(# ctime timestamp without time zone); NOTICE: CREATE TABLE will create implicit sequence "t_parent_id_seq" for serial column "t_parent.id" NOTICE: CREATE TABLE / PRIMARY KEY will create implicit index "t_parent_pkey" for table "t_parent" CREATE TABLE 建立子表 postgres=# create table t_child( postgres(# cid int4, postgres(# vname varchar(32)); CREATE TABLE 查看表外键 postgres=# \d+

Information Security Encryption & Decryption Key Management - PCIDSS / PADSS Compliance

╄→尐↘猪︶ㄣ 提交于 2020-04-17 21:11:12
问题 We are going to get a Payment Gateway developed from a 3rd party and require this payment gateway to be PA-DSS and the environment to be PCI-DSS compliant. Payment Gateway will be encrypting sensitive information like (passwords, pins, credit and debit card information) and will save it into database. We require that the Key to encrypt and decrypt this information must be changed on regular basis (say quarterly). The requirement is also not to hard code this key into the code. What would be

How can I ask for a key of a subkey in a dictionary in Python?

Deadly 提交于 2020-04-11 05:35:31
问题 If I have a dictionary in a dictionary, how can I ask for a key in constant time? For example: def get_hobby(hobby): d = {'An' : {'Hobby': "Paintball", 'Age' : 22}, 'Jef' : {'Hobby' : "Football", 'Age': 24}, 'Jos' : {'Hobby': "Paintball", 'Age' : 46}} assert get_hobby("Paintball") == ['An', 'Jos'] This doesn't work: return d.keys[hobby] 回答1: Use a list comprehension: return [name for name, props in d.items() if props['Hobby'] == hobby] d.items() gives you a sequence of (key, value) pairs,

PHP - sort hash array by key length

蓝咒 提交于 2020-04-09 06:44:38
问题 I've found a few answers to sorting by value, but not key. What I'd like to do is a reverse sort, so with: $nametocode['reallylongname']='12'; $nametocode['shortname']='10'; $nametocode['mediumname']='11'; I'd like them to be in this order reallylongname mediumname shortname mediumname shortname Many thanks 回答1: Another solution using array_multisort: $keys = array_map('strlen', array_keys($arr)); array_multisort($keys, SORT_DESC, $arr); Here $keys is an array of the lengths of the keys of

js中json对象key值首字母大写化(转载,以备不时之需)

梦想与她 提交于 2020-04-07 11:55:37
function toUpperCase(jsonObj) { if(typeof(jsonObj)=='object'){ for (var key in jsonObj){ jsonObj[key.substring(0,1).toUpperCase()+key.substring(1)] = jsonObj[key]; delete(jsonObj[key]); } return jsonObj; } return data; } var res; var _data = {"myKey":"myValue"}; res = toUpperCase(_data); console.log(res);//{MyKey: "myValue"} console.log(JSON.stringify(res));//{"MyKey":"myValue"} ———————————————— 版权声明:本文为CSDN博主「WittyLu」的原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接及本声明。 原文链接:https://blog.csdn.net/baidu_28479651/java/article/details/78057626 来源: https://www.cnblogs.com/stone2012/p/12652248.html

5、字典类型

别来无恙 提交于 2020-04-07 11:14:52
字典类型 dict 定义方式 :通过大括号来存数据,通过key:value这种映射关系来定义键值对,每个键值对通过逗号分隔 key : 一定是不可变类型 value:可以是任意类型 三种定义方式: d1 = {"name":"shen", "age":18}# ***** d2 = dict(name = "shen", age = 18,'sex' = 'male')# ***** l1 = ['name',"age"] l2 = ['egon',18] z1 = zip(l1,l2) 常用方法: 1. 按照key:value 映射关系取值(可存可取) d1 = {'name':'shen','age':18} print(d1['age'])# 按照key查找value d1['age'] = 20# 改值 print(d1) d1['sex'] = 'male'# 增加键值对 print(d1) 2. 成员运算in ,not in (默认判断key) d1 = {'name':'shen','age':18} print("name" in d1)# >>>True print("shen" in d1)# >>>False 3. len() :获取当前字典中键值对的个数 内置方法 1、 .get() :通过key来查找value值,如果找不到,默认返回None